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The Ratio of Molecular Masses of 2 immiscible liquids in a mixture say liquid A and liquid B. Check FAQs
MA:B=PB°WAPA°WB
MA:B - Ratio of Molecular Masses of 2 Immiscible Liquids?PB° - Vapor Pressure of Pure Component B?WA - Weight of Liquid A?PA° - Vapor Pressure of Pure Component A?WB - Weight of Liquid B?

Ratio of Molecular Mass of 2 Immiscible Liquids Example

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Here is how the Ratio of Molecular Mass of 2 Immiscible Liquids equation looks like with Values.

Here is how the Ratio of Molecular Mass of 2 Immiscible Liquids equation looks like with Units.

Here is how the Ratio of Molecular Mass of 2 Immiscible Liquids equation looks like.

0.463Edit=0.25Edit0.5Edit2.7Edit0.1Edit
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Ratio of Molecular Mass of 2 Immiscible Liquids Solution

Follow our step by step solution on how to calculate Ratio of Molecular Mass of 2 Immiscible Liquids?

FIRST Step Consider the formula
MA:B=PB°WAPA°WB
Next Step Substitute values of Variables
MA:B=0.25Pa0.5g2.7Pa0.1g
Next Step Convert Units
MA:B=0.25Pa0.0005kg2.7Pa0.0001kg
Next Step Prepare to Evaluate
MA:B=0.250.00052.70.0001
Next Step Evaluate
MA:B=0.462962962962963
LAST Step Rounding Answer
MA:B=0.463

Ratio of Molecular Mass of 2 Immiscible Liquids Formula Elements

Variables
Ratio of Molecular Masses of 2 Immiscible Liquids
The Ratio of Molecular Masses of 2 immiscible liquids in a mixture say liquid A and liquid B.
Symbol: MA:B
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Vapor Pressure of Pure Component B
Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
Symbol: PB°
Measurement: PressureUnit: Pa
Note: Value can be positive or negative.
Weight of Liquid A
The Weight of Liquid A in a mixture of immiscible liquids.
Symbol: WA
Measurement: WeightUnit: g
Note: Value should be greater than 0.
Vapor Pressure of Pure Component A
Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.
Symbol: PA°
Measurement: PressureUnit: Pa
Note: Value can be positive or negative.
Weight of Liquid B
The Weight of Liquid B in a mixture of immiscible liquids.
Symbol: WB
Measurement: WeightUnit: g
Note: Value should be greater than 0.

Other Formulas to find Ratio of Molecular Masses of 2 Immiscible Liquids

​Go Ratio of Molecular Masses of Water to Liquid forming Immiscible Mixture
MA:B=WwaterPB°PowaterWB

Other formulas in Immiscible Liquids category

​Go Total Pressure of Mixture of Two Immiscible Liquids
P=PA°+PB°
​Go Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid
PA°=WAMBPB°MAWB
​Go Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass
PA:B=WAMBWBMA
​Go Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles
PA:B=nAnB

How to Evaluate Ratio of Molecular Mass of 2 Immiscible Liquids?

Ratio of Molecular Mass of 2 Immiscible Liquids evaluator uses Ratio of Molecular Masses of 2 Immiscible Liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B) to evaluate the Ratio of Molecular Masses of 2 Immiscible Liquids, The Ratio of Molecular Mass of 2 Immiscible Liquids formula is defined as the ratio of the molecular masses in mixture. Ratio of Molecular Masses of 2 Immiscible Liquids is denoted by MA:B symbol.

How to evaluate Ratio of Molecular Mass of 2 Immiscible Liquids using this online evaluator? To use this online evaluator for Ratio of Molecular Mass of 2 Immiscible Liquids, enter Vapor Pressure of Pure Component B (PB°), Weight of Liquid A (WA), Vapor Pressure of Pure Component A (PA°) & Weight of Liquid B (WB) and hit the calculate button.

FAQs on Ratio of Molecular Mass of 2 Immiscible Liquids

What is the formula to find Ratio of Molecular Mass of 2 Immiscible Liquids?
The formula of Ratio of Molecular Mass of 2 Immiscible Liquids is expressed as Ratio of Molecular Masses of 2 Immiscible Liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B). Here is an example- 0.462963 = (0.25*0.0005)/(2.7*0.0001).
How to calculate Ratio of Molecular Mass of 2 Immiscible Liquids?
With Vapor Pressure of Pure Component B (PB°), Weight of Liquid A (WA), Vapor Pressure of Pure Component A (PA°) & Weight of Liquid B (WB) we can find Ratio of Molecular Mass of 2 Immiscible Liquids using the formula - Ratio of Molecular Masses of 2 Immiscible Liquids = (Vapor Pressure of Pure Component B*Weight of Liquid A)/(Vapor Pressure of Pure Component A*Weight of Liquid B).
What are the other ways to Calculate Ratio of Molecular Masses of 2 Immiscible Liquids?
Here are the different ways to Calculate Ratio of Molecular Masses of 2 Immiscible Liquids-
  • Ratio of Molecular Masses of 2 Immiscible Liquids=(Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B)/(Partial Pressure of Pure Water*Weight of Liquid B)OpenImg
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