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Pumping Power Required in Heat Exchanger Given Pressure Drop Formula

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Pumping Power in a heat exchanger refers to the energy required to circulate the heat transfer fluid (typically a liquid) through the exchanger. Check FAQs

P p = \frac{M flow \cdot ΔP Tube Side}{ρ fluid}

P_p - Pumping Power?M_flow - Mass Flowrate?ΔP_{Tube Side} - Tube Side Pressure Drop?ρ_fluid - Fluid Density?

Pumping Power Required in Heat Exchanger Given Pressure Drop Example

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Here is how the Pumping Power Required in Heat Exchanger Given Pressure Drop equation looks like with Values.

Here is how the Pumping Power Required in Heat Exchanger Given Pressure Drop equation looks like with Units.

Here is how the Pumping Power Required in Heat Exchanger Given Pressure Drop equation looks like.

2629.1099 = \frac{14 \cdot 186854.6}{995}

2629.1099W = \frac{14kg/s \cdot 186854.6Pa}{995kg/m³}

2629.1099 = \frac{14 \cdot 186854.6}{995}

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Pumping Power Required in Heat Exchanger Given Pressure Drop Solution

Follow our step by step solution on how to calculate Pumping Power Required in Heat Exchanger Given Pressure Drop?

FIRST Step Consider the formula

P p = \frac{M flow \cdot ΔP Tube Side}{ρ fluid}

Next Step Substitute values of Variables

∴

P p = \frac{14kg/s \cdot 186854.6Pa}{995kg/m³}

Next Step Prepare to Evaluate

∴

P p = \frac{14 \cdot 186854.6}{995}

Next Step Evaluate

∴

P p = 2629.10994974874W

LAST Step Rounding Answer

∴

P p = 2629.1099W

Pumping Power Required in Heat Exchanger Given Pressure Drop Formula Elements

Variables

Pumping Power

Pumping Power in a heat exchanger refers to the energy required to circulate the heat transfer fluid (typically a liquid) through the exchanger.

Symbol: P_p

Measurement: PowerUnit: W

Note: Value should be greater than 0.

Formulas to find Pumping Power

Mass Flowrate

Mass Flowrate is the mass of a substance that passes per unit of time.

Symbol: M_flow

Measurement: Mass Flow RateUnit: kg/s

Note: Value should be greater than 0.

Formulas to find Mass Flowrate

Tube Side Pressure Drop

Tube Side Pressure Drop is the difference between inlet and outlet pressure of the tube side fluid in a shell and tube heat exchanger.

Symbol: ΔP_{Tube Side}

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Tube Side Pressure Drop

Fluid Density

Fluid Density is defined as the ratio of mass of given fluid with respect to the volume that it occupies.

Symbol: ρ_fluid

Measurement: DensityUnit: kg/m³

Note: Value should be greater than 0.

Formulas to find Fluid Density

Other formulas in Basic Formulas of Heat Exchanger Designs category

Go Equivalent Diameter for Square Pitch in Heat Exchanger

D e = (\frac{1.27}{D Outer}) \cdot (({P Tube}^{2}) - 0.785 \cdot ({D Outer}^{2}))

Go Equivalent Diameter for Triangular Pitch in Heat Exchanger

D e = (\frac{1.10}{D Outer}) \cdot (({P Tube}^{2}) - 0.917 \cdot ({D Outer}^{2}))

Go Number of Baffles in Shell and Tube Heat Exchanger

N Baffles = (\frac{L Tube}{L Baffle}) - 1

Go Number of Tubes in Center Row Given Bundle Diameter and Tube Pitch

N r = \frac{D B}{P Tube}

How to Evaluate Pumping Power Required in Heat Exchanger Given Pressure Drop?

Pumping Power Required in Heat Exchanger Given Pressure Drop evaluator uses Pumping Power = (Mass Flowrate*Tube Side Pressure Drop)/Fluid Density to evaluate the Pumping Power, The Pumping Power Required in Heat Exchanger Given Pressure Drop formula is defined as the energy required by pumps or similar equipment to circulate the heat transfer fluid through the exchanger. Pumping Power is denoted by P_p symbol.

How to evaluate Pumping Power Required in Heat Exchanger Given Pressure Drop using this online evaluator? To use this online evaluator for Pumping Power Required in Heat Exchanger Given Pressure Drop, enter Mass Flowrate (M_flow), Tube Side Pressure Drop (ΔP_{Tube Side}) & Fluid Density (ρ_fluid) and hit the calculate button.

FAQs on Pumping Power Required in Heat Exchanger Given Pressure Drop

What is the formula to find Pumping Power Required in Heat Exchanger Given Pressure Drop?

The formula of Pumping Power Required in Heat Exchanger Given Pressure Drop is expressed as Pumping Power = (Mass Flowrate*Tube Side Pressure Drop)/Fluid Density. Here is an example- 2629.11 = (14*186854.6)/995.

How to calculate Pumping Power Required in Heat Exchanger Given Pressure Drop?

With Mass Flowrate (M_flow), Tube Side Pressure Drop (ΔP_{Tube Side}) & Fluid Density (ρ_fluid) we can find Pumping Power Required in Heat Exchanger Given Pressure Drop using the formula - Pumping Power = (Mass Flowrate*Tube Side Pressure Drop)/Fluid Density.

Can the Pumping Power Required in Heat Exchanger Given Pressure Drop be negative?

No, the Pumping Power Required in Heat Exchanger Given Pressure Drop, measured in Power cannot be negative.

Which unit is used to measure Pumping Power Required in Heat Exchanger Given Pressure Drop?

Pumping Power Required in Heat Exchanger Given Pressure Drop is usually measured using the Watt[W] for Power. Kilowatt[W], Milliwatt[W], Microwatt[W] are the few other units in which Pumping Power Required in Heat Exchanger Given Pressure Drop can be measured.

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Pumping Power Required in Heat Exchanger Given Pressure Drop Formula

Pumping Power Required in Heat Exchanger Given Pressure Drop Example

Pumping Power Required in Heat Exchanger Given Pressure Drop Solution

Pumping Power Required in Heat Exchanger Given Pressure Drop Formula Elements

Other formulas in Basic Formulas of Heat Exchanger Designs category

How to Evaluate Pumping Power Required in Heat Exchanger Given Pressure Drop?

FAQs on Pumping Power Required in Heat Exchanger Given Pressure Drop

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