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Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Formula

GoPower Transmitted using Area of X-Section (1-Phase 2-Wire US) Formula

GoPower Transmitted using Load Current (1-Phase 2-Wire US) Formula

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Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work. Check FAQs

P = \sqrt{P loss \cdot V \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{8 \cdot ρ \cdot {(L)}^{2}}}

P - Power Transmitted?P_loss - Line Losses?V - Volume Of Conductor?V_m - Maximum Voltage Underground AC?Φ - Phase Difference?ρ - Resistivity?L - Length of Underground AC Wire?

Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Example

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Here is how the Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) equation looks like.

9007.5987 = \sqrt{2.67 \cdot 60 \cdot \frac{{(230 \cdot \cos (30))}^{2}}{8 \cdot 1.7E-5 \cdot {(24)}^{2}}}

9007.5987W = \sqrt{2.67W \cdot 60m³ \cdot \frac{{(230V \cdot \cos (30°))}^{2}}{8 \cdot 1.7E-5Ω*m \cdot {(24m)}^{2}}}

9007.5987 = \sqrt{2.67 \cdot 60 \cdot \frac{{(230 \cdot \cos (30))}^{2}}{8 \cdot 1.7E-5 \cdot {(24)}^{2}}}

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Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)?

FIRST Step Consider the formula

P = \sqrt{P loss \cdot V \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{8 \cdot ρ \cdot {(L)}^{2}}}

Next Step Substitute values of Variables

∴

P = \sqrt{2.67W \cdot 60m³ \cdot \frac{{(230V \cdot \cos (30°))}^{2}}{8 \cdot 1.7E-5Ω*m \cdot {(24m)}^{2}}}

Next Step Convert Units

∴

P = \sqrt{2.67W \cdot 60m³ \cdot \frac{{(230V \cdot \cos (0.5236rad))}^{2}}{8 \cdot 1.7E-5Ω*m \cdot {(24m)}^{2}}}

Next Step Prepare to Evaluate

∴

P = \sqrt{2.67 \cdot 60 \cdot \frac{{(230 \cdot \cos (0.5236))}^{2}}{8 \cdot 1.7E-5 \cdot {(24)}^{2}}}

Next Step Evaluate

∴

P = 9007.59866111417W

LAST Step Rounding Answer

∴

P = 9007.5987W

Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Formula Elements

Variables

Functions

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume Of Conductor

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Power Transmitted

Go Power Transmitted using Area of X-Section (1-Phase 2-Wire US)

P = \sqrt{\frac{A \cdot ({V m}^{2}) \cdot P loss \cdot ({(\cos (Φ))}^{2})}{4 \cdot ρ \cdot L}}

Go Power Transmitted using Load Current (1-Phase 2-Wire US)

P = I \cdot V m \cdot \frac{\cos (Φ)}{\sqrt{2}}

Other formulas in Power and Power Factor category

Go Power Factor using Area of X-Section (1-Phase 2-Wire US)

PF = \sqrt{\frac{(4) \cdot (P^{2}) \cdot ρ \cdot L}{A \cdot P loss \cdot ({V m}^{2})}}

Go Power Factor using Volume of Conductor Material (1-Phase 2-Wire US)

PF = \sqrt{(2) \cdot \frac{K}{V}}

How to Evaluate Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)?

Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) evaluator uses Power Transmitted = sqrt(Line Losses*Volume Of Conductor*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(8*Resistivity*(Length of Underground AC Wire)^2)) to evaluate the Power Transmitted, The Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations. Power Transmitted is denoted by P symbol.

How to evaluate Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US), enter Line Losses (P_loss), Volume Of Conductor (V), Maximum Voltage Underground AC (V_m), Phase Difference (Φ), Resistivity (ρ) & Length of Underground AC Wire (L) and hit the calculate button.

FAQs on Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)

What is the formula to find Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)?

The formula of Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) is expressed as Power Transmitted = sqrt(Line Losses*Volume Of Conductor*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(8*Resistivity*(Length of Underground AC Wire)^2)). Here is an example- 9007.599 = sqrt(2.67*60*(230*cos(0.5235987755982))^2/(8*1.7E-05*(24)^2)).

How to calculate Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)?

With Line Losses (P_loss), Volume Of Conductor (V), Maximum Voltage Underground AC (V_m), Phase Difference (Φ), Resistivity (ρ) & Length of Underground AC Wire (L) we can find Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) using the formula - Power Transmitted = sqrt(Line Losses*Volume Of Conductor*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(8*Resistivity*(Length of Underground AC Wire)^2)). This formula also uses Cosine (cos), Square Root (sqrt) function(s).

What are the other ways to Calculate Power Transmitted?

Here are the different ways to Calculate Power Transmitted-

Power Transmitted=sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire))
Power Transmitted=Current Underground AC*Maximum Voltage Underground AC*cos(Phase Difference)/(sqrt(2))
Power Transmitted=sqrt(Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistivity*Length of Underground AC Wire))

Can the Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) be negative?

Yes, the Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US), measured in Power can be negative.

Which unit is used to measure Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)?

Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) is usually measured using the Watt[W] for Power. Kilowatt[W], Milliwatt[W], Microwatt[W] are the few other units in which Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) can be measured.

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Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Formula

​GoPower Transmitted using Area of X-Section (1-Phase 2-Wire US) Formula

​GoPower Transmitted using Load Current (1-Phase 2-Wire US) Formula

Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Example

Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Solution

Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Formula Elements

Other Formulas to find Power Transmitted

Other formulas in Power and Power Factor category

How to Evaluate Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)?

FAQs on Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)

Variable Name

GoPower Transmitted using Area of X-Section (1-Phase 2-Wire US) Formula

GoPower Transmitted using Load Current (1-Phase 2-Wire US) Formula