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Power Transmitted using Load Current (1-Phase 2-Wire US) Formula

GoPower Transmitted using Area of X-Section (1-Phase 2-Wire US) Formula

GoPower Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Formula

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Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work. Check FAQs

P = I \cdot V m \cdot \frac{\cos (Φ)}{\sqrt{2}}

P - Power Transmitted?I - Current Underground AC?V_m - Maximum Voltage Underground AC?Φ - Phase Difference?

Power Transmitted using Load Current (1-Phase 2-Wire US) Example

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Here is how the Power Transmitted using Load Current (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Power Transmitted using Load Current (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Power Transmitted using Load Current (1-Phase 2-Wire US) equation looks like.

1267.6109 = 9 \cdot 230 \cdot \frac{\cos (30)}{\sqrt{2}}

1267.6109W = 9A \cdot 230V \cdot \frac{\cos (30°)}{\sqrt{2}}

1267.6109 = 9 \cdot 230 \cdot \frac{\cos (30)}{\sqrt{2}}

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Power Transmitted using Load Current (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Power Transmitted using Load Current (1-Phase 2-Wire US)?

FIRST Step Consider the formula

P = I \cdot V m \cdot \frac{\cos (Φ)}{\sqrt{2}}

Next Step Substitute values of Variables

∴

P = 9A \cdot 230V \cdot \frac{\cos (30°)}{\sqrt{2}}

Next Step Convert Units

∴

P = 9A \cdot 230V \cdot \frac{\cos (0.5236rad)}{\sqrt{2}}

Next Step Prepare to Evaluate

∴

P = 9 \cdot 230 \cdot \frac{\cos (0.5236)}{\sqrt{2}}

Next Step Evaluate

∴

P = 1267.61094189029W

LAST Step Rounding Answer

∴

P = 1267.6109W

Power Transmitted using Load Current (1-Phase 2-Wire US) Formula Elements

Variables

Functions

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Current Underground AC

Current Underground AC is defined as the current flowing through the overhead ac supply wire.

Symbol: I

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Current Underground AC

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Power Transmitted

Go Power Transmitted using Area of X-Section (1-Phase 2-Wire US)

P = \sqrt{\frac{A \cdot ({V m}^{2}) \cdot P loss \cdot ({(\cos (Φ))}^{2})}{4 \cdot ρ \cdot L}}

Go Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)

P = \sqrt{P loss \cdot V \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{8 \cdot ρ \cdot {(L)}^{2}}}

Go Power Transmitted using Line Losses (1-Phase 2-Wire US)

P = \sqrt{P loss \cdot A \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{4 \cdot ρ \cdot L}}

Go Power Transmitted using Resistance (1-Phase 2-Wire US)

P = \sqrt{P loss \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{4 \cdot R}}

Other formulas in Power and Power Factor category

Go Power Factor using Area of X-Section (1-Phase 2-Wire US)

PF = \sqrt{\frac{(4) \cdot (P^{2}) \cdot ρ \cdot L}{A \cdot P loss \cdot ({V m}^{2})}}

Go Power Factor using Volume of Conductor Material (1-Phase 2-Wire US)

PF = \sqrt{(2) \cdot \frac{K}{V}}

Go Power Factor using Load Current (1-Phase 2-Wire US)

PF = \frac{\sqrt{2} \cdot P}{V m \cdot I}

Go Power Factor using Line Losses (1-Phase 2-Wire US)

PF = (2 \cdot \frac{P}{V m}) \cdot \sqrt{ρ \cdot \frac{L}{P loss} \cdot A}

How to Evaluate Power Transmitted using Load Current (1-Phase 2-Wire US)?

Power Transmitted using Load Current (1-Phase 2-Wire US) evaluator uses Power Transmitted = Current Underground AC*Maximum Voltage Underground AC*cos(Phase Difference)/(sqrt(2)) to evaluate the Power Transmitted, The Power Transmitted using Load Current (1-Phase 2-Wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations. Power Transmitted is denoted by P symbol.

How to evaluate Power Transmitted using Load Current (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Power Transmitted using Load Current (1-Phase 2-Wire US), enter Current Underground AC (I), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) and hit the calculate button.

FAQs on Power Transmitted using Load Current (1-Phase 2-Wire US)

What is the formula to find Power Transmitted using Load Current (1-Phase 2-Wire US)?

The formula of Power Transmitted using Load Current (1-Phase 2-Wire US) is expressed as Power Transmitted = Current Underground AC*Maximum Voltage Underground AC*cos(Phase Difference)/(sqrt(2)). Here is an example- 1267.611 = 9*230*cos(0.5235987755982)/(sqrt(2)).

How to calculate Power Transmitted using Load Current (1-Phase 2-Wire US)?

With Current Underground AC (I), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) we can find Power Transmitted using Load Current (1-Phase 2-Wire US) using the formula - Power Transmitted = Current Underground AC*Maximum Voltage Underground AC*cos(Phase Difference)/(sqrt(2)). This formula also uses Cosine (cos), Square Root (sqrt) function(s).

What are the other ways to Calculate Power Transmitted?

Here are the different ways to Calculate Power Transmitted-

Power Transmitted=sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire))
Power Transmitted=sqrt(Line Losses*Volume Of Conductor*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(8*Resistivity*(Length of Underground AC Wire)^2))
Power Transmitted=sqrt(Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*Resistivity*Length of Underground AC Wire))

Can the Power Transmitted using Load Current (1-Phase 2-Wire US) be negative?

Yes, the Power Transmitted using Load Current (1-Phase 2-Wire US), measured in Power can be negative.

Which unit is used to measure Power Transmitted using Load Current (1-Phase 2-Wire US)?

Power Transmitted using Load Current (1-Phase 2-Wire US) is usually measured using the Watt[W] for Power. Kilowatt[W], Milliwatt[W], Microwatt[W] are the few other units in which Power Transmitted using Load Current (1-Phase 2-Wire US) can be measured.

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Power Transmitted using Load Current (1-Phase 2-Wire US) Formula

​GoPower Transmitted using Area of X-Section (1-Phase 2-Wire US) Formula

​GoPower Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Formula

Power Transmitted using Load Current (1-Phase 2-Wire US) Example

Power Transmitted using Load Current (1-Phase 2-Wire US) Solution

Power Transmitted using Load Current (1-Phase 2-Wire US) Formula Elements

Other Formulas to find Power Transmitted

Other formulas in Power and Power Factor category

How to Evaluate Power Transmitted using Load Current (1-Phase 2-Wire US)?

FAQs on Power Transmitted using Load Current (1-Phase 2-Wire US)

Variable Name

GoPower Transmitted using Area of X-Section (1-Phase 2-Wire US) Formula

GoPower Transmitted using Volume of Conductor Material (1-Phase 2-Wire US) Formula