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pOH of Strong acid and Strong base Formula

GopOH using Concentration of Hydroxide ion Formula

GopOH of Salt of Strong Base and Weak Acid Formula

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The Negative Log of Hydroxyl Concentration gives us the value of hydroxyl concentration on the pH scale. Check FAQs

pOH = \frac{pK w}{2}

pOH - Negative Log of Hydroxyl Concentration?pK_w - Negative Log of Ionic Product of Water?

pOH of Strong acid and Strong base Example

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Here is how the pOH of Strong acid and Strong base equation looks like with Values.

Here is how the pOH of Strong acid and Strong base equation looks like with Units.

Here is how the pOH of Strong acid and Strong base equation looks like.

7 = \frac{14}{2}

7 = \frac{14}{2}

7 = \frac{14}{2}

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pOH of Strong acid and Strong base Solution

Follow our step by step solution on how to calculate pOH of Strong acid and Strong base?

FIRST Step Consider the formula

pOH = \frac{pK w}{2}

Next Step Substitute values of Variables

∴

pOH = \frac{14}{2}

Next Step Prepare to Evaluate

∴

pOH = \frac{14}{2}

LAST Step Evaluate

∴

pOH = 7

pOH of Strong acid and Strong base Formula Elements

Variables

Negative Log of Hydroxyl Concentration

The Negative Log of Hydroxyl Concentration gives us the value of hydroxyl concentration on the pH scale.

Symbol: pOH

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Negative Log of Hydroxyl Concentration

Negative Log of Ionic Product of Water

Negative Log Of Ionic Product of Water should be Negative Log Of Ionic Product of Water gives us the product of the concentration of hydronium ions and hydroxyl ions in the solution, on the pH scale.

Symbol: pK_w

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Negative Log of Ionic Product of Water

Other Formulas to find Negative Log of Hydroxyl Concentration

Go pOH using Concentration of Hydroxide ion

pOH = 14 + \log 10 (C)

Go pOH of Salt of Strong Base and Weak Acid

pOH = 14 - \frac{pk a + pK w + \log 10 (C salt)}{2}

Go pOH of Salt of Weak Base and Strong Base

pOH = 14 - \frac{pK w - pk b - \log 10 (C salt)}{2}

Go pOH of Salt of Weak Acid and Weak Base

pOH = 14 - \frac{pK w + pk a - pk b}{2}

Other formulas in Electrolytes and Ions category

Go Ionic Mobility

μ = \frac{V}{x}

Go Quantity of Charges given Mass of Substance

q = \frac{m ion}{Z}

Go Time required for Flowing of Charge given Mass and Time

t tot = \frac{m ion}{Z \cdot i p}

Go Cell Potential given Electrochemical Work

E cell = (\frac{w}{n \cdot [Faraday]})

How to Evaluate pOH of Strong acid and Strong base?

pOH of Strong acid and Strong base evaluator uses Negative Log of Hydroxyl Concentration = Negative Log of Ionic Product of Water/2 to evaluate the Negative Log of Hydroxyl Concentration, The pOH of Strong acid and Strong base formula is defined as the hyudroxyl ion concentration in aqueous solution. Negative Log of Hydroxyl Concentration is denoted by pOH symbol.

How to evaluate pOH of Strong acid and Strong base using this online evaluator? To use this online evaluator for pOH of Strong acid and Strong base, enter Negative Log of Ionic Product of Water (pK_w) and hit the calculate button.

FAQs on pOH of Strong acid and Strong base

What is the formula to find pOH of Strong acid and Strong base?

The formula of pOH of Strong acid and Strong base is expressed as Negative Log of Hydroxyl Concentration = Negative Log of Ionic Product of Water/2. Here is an example- 7 = 14/2.

How to calculate pOH of Strong acid and Strong base?

With Negative Log of Ionic Product of Water (pK_w) we can find pOH of Strong acid and Strong base using the formula - Negative Log of Hydroxyl Concentration = Negative Log of Ionic Product of Water/2.

What are the other ways to Calculate Negative Log of Hydroxyl Concentration?

Here are the different ways to Calculate Negative Log of Hydroxyl Concentration-

Negative Log of Hydroxyl Concentration=14+log10(Hydronium Ion Concentration)
Negative Log of Hydroxyl Concentration=14-(Negative Log of Acid Ionization Constant+Negative Log of Ionic Product of Water+log10(Concentration of Salt))/2
Negative Log of Hydroxyl Concentration=14-(Negative Log of Ionic Product of Water-Negative Log of Base Ionization Constant-log10(Concentration of Salt))/2

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