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The Negative Log of Hydroxyl Concentration gives us the value of hydroxyl concentration on the pH scale. Check FAQs
pOH=-log10(N1⋅V1+N2⋅V2V1+V2)
pOH - Negative Log of Hydroxyl Concentration?N1 - Normality of Solution 1?V1 - Volume of Solution 1?N2 - Normality of Solution 2?V2 - Volume of Solution 2?

pOH of Mixture of Two Strong Bases Example

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Here is how the pOH of Mixture of Two Strong Bases equation looks like with Values.

Here is how the pOH of Mixture of Two Strong Bases equation looks like with Units.

Here is how the pOH of Mixture of Two Strong Bases equation looks like.

3.1461Edit=-log10(0.0008Edit⋅0.0002Edit+0.0005Edit⋅0.0001Edit0.0002Edit+0.0001Edit)
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HomeIcon Home » Category Chemistry » Category Equilibrium » Category Ionic equilibrium » fx pOH of Mixture of Two Strong Bases

pOH of Mixture of Two Strong Bases Solution

Follow our step by step solution on how to calculate pOH of Mixture of Two Strong Bases?

FIRST Step Consider the formula
pOH=-log10(N1⋅V1+N2⋅V2V1+V2)
Next Step Substitute values of Variables
∴ pOH=-log10(0.0008Eq/L⋅0.0002L+0.0005Eq/L⋅0.0001L0.0002L+0.0001L)
Next Step Prepare to Evaluate
∴ pOH=-log10(0.0008⋅0.0002+0.0005⋅0.00010.0002+0.0001)
Next Step Evaluate
∴pOH=3.14612803567824
LAST Step Rounding Answer
∴pOH=3.1461

pOH of Mixture of Two Strong Bases Formula Elements

Variables
Functions
Negative Log of Hydroxyl Concentration
The Negative Log of Hydroxyl Concentration gives us the value of hydroxyl concentration on the pH scale.
Symbol: pOH
Measurement: NAUnit: Unitless
Note: Value can be positive or negative.
Formulas to find Negative Log of Hydroxyl ConcentrationOpen Variable
Normality of Solution 1
The Normality of Solution 1 is described as the number of gram or mole equivalents of solution 1 present in one liter of solution 1.
Symbol: N1
Measurement: Molar ConcentrationUnit: Eq/L
Note: Value should be greater than 0.
Formulas to find Normality of Solution 1Open Variable
Volume of Solution 1
The Volume of Solution 1 gives the volume of solution 1 in liters.
Symbol: V1
Measurement: VolumeUnit: L
Note: Value should be greater than 0.
Formulas to find Volume of Solution 1Open Variable
Normality of Solution 2
The Normality of Solution 2 is described as the number of gram or mole equivalents of solution 2 present in one liter of solution 2.
Symbol: N2
Measurement: Molar ConcentrationUnit: Eq/L
Note: Value should be greater than 0.
Formulas to find Normality of Solution 2Open Variable
Volume of Solution 2
The Volume of Solution 2 gives the volume of the solution 2 in liters.
Symbol: V2
Measurement: VolumeUnit: L
Note: Value should be greater than 0.
Formulas to find Volume of Solution 2Open Variable
log10
The common logarithm, also known as the base-10 logarithm or the decimal logarithm, is a mathematical function that is the inverse of the exponential function.
Syntax: log10(Number)

Other Formulas to find Negative Log of Hydroxyl Concentration

​Go pOH given Concentration of Hydroxyl Ion
pOH=-log10(OH-)
​Go pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature
pOH=14+log10(N1⋅V1-N2⋅V2V1+V2)

Other formulas in Acidity and pH Scale category

​Go pH given Activity of Hydrogen Ion
pH=-log10(aH+)
​Go Activity of Hydrogen Ion given pH
aH+=10-pH
​Go pH given Concentration of Hydrogen Ion
pH=-log10(H+)
​Go Concentration of Hydrogen Ion given pH
H+=10-pH

How to Evaluate pOH of Mixture of Two Strong Bases?

pOH of Mixture of Two Strong Bases evaluator uses Negative Log of Hydroxyl Concentration = -log10((Normality of Solution 1*Volume of Solution 1+Normality of Solution 2*Volume of Solution 2)/(Volume of Solution 1+Volume of Solution 2)) to evaluate the Negative Log of Hydroxyl Concentration, The pOH of Mixture of Two Strong Bases formula is defined as the negative base-10 logarithm of the concentration of hydroxyl ion of a solution which is calculated using normality and volume of two strong acids of 1 and 2. Negative Log of Hydroxyl Concentration is denoted by pOH symbol.

How to evaluate pOH of Mixture of Two Strong Bases using this online evaluator? To use this online evaluator for pOH of Mixture of Two Strong Bases, enter Normality of Solution 1 (N1), Volume of Solution 1 (V1), Normality of Solution 2 (N2) & Volume of Solution 2 (V2) and hit the calculate button.

FAQs on pOH of Mixture of Two Strong Bases

What is the formula to find pOH of Mixture of Two Strong Bases?
The formula of pOH of Mixture of Two Strong Bases is expressed as Negative Log of Hydroxyl Concentration = -log10((Normality of Solution 1*Volume of Solution 1+Normality of Solution 2*Volume of Solution 2)/(Volume of Solution 1+Volume of Solution 2)). Here is an example- 3.103219 = -log10((0.8*2.5E-07+0.5*1E-07)/(2.5E-07+1E-07)).
How to calculate pOH of Mixture of Two Strong Bases?
With Normality of Solution 1 (N1), Volume of Solution 1 (V1), Normality of Solution 2 (N2) & Volume of Solution 2 (V2) we can find pOH of Mixture of Two Strong Bases using the formula - Negative Log of Hydroxyl Concentration = -log10((Normality of Solution 1*Volume of Solution 1+Normality of Solution 2*Volume of Solution 2)/(Volume of Solution 1+Volume of Solution 2)). This formula also uses Common Logarithm Function function(s).
What are the other ways to Calculate Negative Log of Hydroxyl Concentration?
Here are the different ways to Calculate Negative Log of Hydroxyl Concentration-
  • Negative Log of Hydroxyl Concentration=-log10(Concentration of Hydroxyl Ion)OpenImg
  • Negative Log of Hydroxyl Concentration=14+log10((Normality of Solution 1*Volume of Solution 1-Normality of Solution 2*Volume of Solution 2)/(Volume of Solution 1+Volume of Solution 2))OpenImg
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