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Photocurrent due to Incident Light Formula

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Photocurrent is the electrical current produced by the photodetector when exposed to light. Check FAQs

I p = \frac{P o \cdot [Charge-e] \cdot (1 - r)}{[hP] \cdot f} \cdot (1 - \exp (- α ab \cdot d ab))

I_p - Photocurrent?P_o - Incident Power?r - Reflection Coefficient?f - Frequency Of Incident Light?α_ab - Absorption Coefficient?d_ab - Width of Absorption Region?[Charge-e] - Charge of electron?[hP] - Planck constant?

Photocurrent due to Incident Light Example

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Here is how the Photocurrent due to Incident Light equation looks like with Values.

Here is how the Photocurrent due to Incident Light equation looks like with Units.

Here is how the Photocurrent due to Incident Light equation looks like.

70.2354 = \frac{1.75 \cdot 1.6E-19 \cdot (1 - 0.25)}{6.6E-34 \cdot 20} \cdot (1 - \exp (- 2.011 \cdot 2.201))

70.2354mA = \frac{1.75µW \cdot 1.6E-19C \cdot (1 - 0.25)}{6.6E-34 \cdot 20Hz} \cdot (1 - \exp (- 2.011 \cdot 2.201nm))

70.2354 = \frac{1.75 \cdot 1.6E-19 \cdot (1 - 0.25)}{6.6E-34 \cdot 20} \cdot (1 - \exp (- 2.011 \cdot 2.201))

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Photocurrent due to Incident Light Solution

Follow our step by step solution on how to calculate Photocurrent due to Incident Light?

FIRST Step Consider the formula

I p = \frac{P o \cdot [Charge-e] \cdot (1 - r)}{[hP] \cdot f} \cdot (1 - \exp (- α ab \cdot d ab))

Next Step Substitute values of Variables

∴

I p = \frac{1.75µW \cdot [Charge-e] \cdot (1 - 0.25)}{[hP] \cdot 20Hz} \cdot (1 - \exp (- 2.011 \cdot 2.201nm))

Next Step Substitute values of Constants

∴

I p = \frac{1.75µW \cdot 1.6E-19C \cdot (1 - 0.25)}{6.6E-34 \cdot 20Hz} \cdot (1 - \exp (- 2.011 \cdot 2.201nm))

Next Step Convert Units

∴

I p = \frac{1.8E-6W \cdot 1.6E-19C \cdot (1 - 0.25)}{6.6E-34 \cdot 20Hz} \cdot (1 - \exp (- 2.011 \cdot 2.2E-9m))

Next Step Prepare to Evaluate

∴

I p = \frac{1.8E-6 \cdot 1.6E-19 \cdot (1 - 0.25)}{6.6E-34 \cdot 20} \cdot (1 - \exp (- 2.011 \cdot 2.2E-9))

Next Step Evaluate

∴

I p = 0.0702353567505259A

Next Step Convert to Output's Unit

∴

I p = 70.2353567505259mA

LAST Step Rounding Answer

∴

I p = 70.2354mA

Photocurrent due to Incident Light Formula Elements

Variables

Constants

Functions

Photocurrent

Photocurrent is the electrical current produced by the photodetector when exposed to light.

Symbol: I_p

Measurement: Electric CurrentUnit: mA

Note: Value should be greater than 0.

Formulas to find Photocurrent

Incident Power

Incident Power w.r.t optics is the amount of optical power (light energy) incident on the photodetector.

Symbol: P_o

Measurement: PowerUnit: µW

Note: Value should be greater than 0.

Formulas to find Incident Power

Reflection Coefficient

Reflection Coefficient is a parameter that describes how much of a wave is reflected by an impedance discontinuity in the transmission medium.

Symbol: r

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Reflection Coefficient

Frequency Of Incident Light

Frequency of incident light is a measure of how many cycles (oscillations) of the electromagnetic wave occur per second.

Symbol: f

Measurement: FrequencyUnit: Hz

Note: Value should be greater than 0.

Formulas to find Frequency Of Incident Light

Absorption Coefficient

The Absorption Coefficient is a measure of how readily a material absorbs radiant energy. It can be defined in terms of unit thickness, unit mass, or per atom of an absorber.

Symbol: α_ab

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Absorption Coefficient

Width of Absorption Region

The width of absorption region refers to the width of the region in the optical fiber where light is absorbed and converted into heat by molecules in the fiber core and cladding.

Symbol: d_ab

Measurement: LengthUnit: nm

Note: Value should be greater than 0.

Formulas to find Width of Absorption Region

Charge of electron

Charge of electron is a fundamental physical constant, representing the electric charge carried by an electron, which is the elementary particle with a negative electric charge.

Symbol: [Charge-e]

Value: 1.60217662E-19 C

Planck constant

Planck constant is a fundamental universal constant that defines the quantum nature of energy and relates the energy of a photon to its frequency.

Symbol: [hP]

Value: 6.626070040E-34

exp

n an exponential function, the value of the function changes by a constant factor for every unit change in the independent variable.

Syntax: exp(Number)

Other formulas in Optical Detectors category

Go Quantum Efficiency of Photodetector

η = \frac{N e}{N p}

Go Incident Photon Rate

R i = \frac{P i}{[hP] \cdot F i}

Go Electron Rate in Detector

R p = η \cdot R i

Go Long Wavelength Cutoff Point

λ c = [hP] \cdot \frac{[c]}{E g}

How to Evaluate Photocurrent due to Incident Light?

Photocurrent due to Incident Light evaluator uses Photocurrent = (Incident Power*[Charge-e]*(1-Reflection Coefficient))/([hP]*Frequency Of Incident Light)*(1-exp(-Absorption Coefficient*Width of Absorption Region)) to evaluate the Photocurrent, Photocurrent due to Incident Light is generated when light is absorbed by a photodetector, such as a photodiode. The light transmitted through the fiber is detected by a photodetector at the receiving end. The photodetector absorbs the incident photons and generates electron-hole pairs. The electric field across the device causes these carriers to be swept out of the intrinsic region, thereby giving rise to a current flow in an external circuit. This current flow is known as the photocurrent. Photocurrent is denoted by I_p symbol.

How to evaluate Photocurrent due to Incident Light using this online evaluator? To use this online evaluator for Photocurrent due to Incident Light, enter Incident Power (P_o), Reflection Coefficient (r), Frequency Of Incident Light (f), Absorption Coefficient (α_ab) & Width of Absorption Region (d_ab) and hit the calculate button.

FAQs on Photocurrent due to Incident Light

What is the formula to find Photocurrent due to Incident Light?

The formula of Photocurrent due to Incident Light is expressed as Photocurrent = (Incident Power*[Charge-e]*(1-Reflection Coefficient))/([hP]*Frequency Of Incident Light)*(1-exp(-Absorption Coefficient*Width of Absorption Region)). Here is an example- 1.6E+13 = (1.75E-06*[Charge-e]*(1-0.25))/([hP]*20)*(1-exp(-2.011*2.201E-09)).

How to calculate Photocurrent due to Incident Light?

With Incident Power (P_o), Reflection Coefficient (r), Frequency Of Incident Light (f), Absorption Coefficient (α_ab) & Width of Absorption Region (d_ab) we can find Photocurrent due to Incident Light using the formula - Photocurrent = (Incident Power*[Charge-e]*(1-Reflection Coefficient))/([hP]*Frequency Of Incident Light)*(1-exp(-Absorption Coefficient*Width of Absorption Region)). This formula also uses Charge of electron, Planck constant and Exponential Growth (exp) function(s).

Can the Photocurrent due to Incident Light be negative?

No, the Photocurrent due to Incident Light, measured in Electric Current cannot be negative.

Which unit is used to measure Photocurrent due to Incident Light?

Photocurrent due to Incident Light is usually measured using the Milliampere[mA] for Electric Current. Ampere[mA], Microampere[mA], Centiampere[mA] are the few other units in which Photocurrent due to Incident Light can be measured.

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Photocurrent due to Incident Light Formula

Photocurrent due to Incident Light Example

Photocurrent due to Incident Light Solution

Photocurrent due to Incident Light Formula Elements

Other formulas in Optical Detectors category

How to Evaluate Photocurrent due to Incident Light?

FAQs on Photocurrent due to Incident Light

Variable Name