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Phase Angle for Horizontal Fluid Particle Displacement Formula

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Phase Angle refers to the difference in phase between two wave components, usually waves propagating from different directions or generated by different mechanisms. Check FAQs

θ = a {\sin ({((\frac{ε}{a}) \cdot (\frac{\sinh (2 \cdot π \cdot \frac{d}{λ})}{\cosh (2 \cdot π \cdot \frac{y}{λ})}))}^{2})}^{2}

θ - Phase Angle?ε - Fluid Particle Displacement?a - Wave Amplitude?d - Water Depth?λ - Wavelength of Coast?y - Elevation above the Bottom?π - Archimedes' constant?

Phase Angle for Horizontal Fluid Particle Displacement Example

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Here is how the Phase Angle for Horizontal Fluid Particle Displacement equation looks like with Values.

Here is how the Phase Angle for Horizontal Fluid Particle Displacement equation looks like with Units.

Here is how the Phase Angle for Horizontal Fluid Particle Displacement equation looks like.

0.0001 = a {\sin ({((\frac{0.4}{1.56}) \cdot (\frac{\sinh (2 \cdot 3.1416 \cdot \frac{1.05}{26.8})}{\cosh (2 \cdot 3.1416 \cdot \frac{4.92}{26.8})}))}^{2})}^{2}

0.0001° = a {\sin ({((\frac{0.4m}{1.56m}) \cdot (\frac{\sinh (2 \cdot 3.1416 \cdot \frac{1.05m}{26.8m})}{\cosh (2 \cdot 3.1416 \cdot \frac{4.92m}{26.8m})}))}^{2})}^{2}

0.0001 = a {\sin ({((\frac{0.4}{1.56}) \cdot (\frac{\sinh (2 \cdot 3.1416 \cdot \frac{1.05}{26.8})}{\cosh (2 \cdot 3.1416 \cdot \frac{4.92}{26.8})}))}^{2})}^{2}

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Phase Angle for Horizontal Fluid Particle Displacement Solution

Follow our step by step solution on how to calculate Phase Angle for Horizontal Fluid Particle Displacement?

FIRST Step Consider the formula

θ = a {\sin ({((\frac{ε}{a}) \cdot (\frac{\sinh (2 \cdot π \cdot \frac{d}{λ})}{\cosh (2 \cdot π \cdot \frac{y}{λ})}))}^{2})}^{2}

Next Step Substitute values of Variables

∴

θ = a {\sin ({((\frac{0.4m}{1.56m}) \cdot (\frac{\sinh (2 \cdot π \cdot \frac{1.05m}{26.8m})}{\cosh (2 \cdot π \cdot \frac{4.92m}{26.8m})}))}^{2})}^{2}

Next Step Substitute values of Constants

∴

θ = a {\sin ({((\frac{0.4m}{1.56m}) \cdot (\frac{\sinh (2 \cdot 3.1416 \cdot \frac{1.05m}{26.8m})}{\cosh (2 \cdot 3.1416 \cdot \frac{4.92m}{26.8m})}))}^{2})}^{2}

Next Step Prepare to Evaluate

∴

θ = a {\sin ({((\frac{0.4}{1.56}) \cdot (\frac{\sinh (2 \cdot 3.1416 \cdot \frac{1.05}{26.8})}{\cosh (2 \cdot 3.1416 \cdot \frac{4.92}{26.8})}))}^{2})}^{2}

Next Step Evaluate

∴

θ = 1.7931958817265E-06rad

Next Step Convert to Output's Unit

∴

θ = 0.000102742555863188°

LAST Step Rounding Answer

∴

θ = 0.0001°

Phase Angle for Horizontal Fluid Particle Displacement Formula Elements

Variables

Constants

Functions

Phase Angle

Phase Angle refers to the difference in phase between two wave components, usually waves propagating from different directions or generated by different mechanisms.

Symbol: θ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Angle

Fluid Particle Displacement

Fluid Particle Displacement refers to the movement of individual particles within a fluid medium, such as water or air.

Symbol: ε

Measurement: LengthUnit: m