FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Periodic Time of SHM for Compound Pendulum given Radius of Gyration Formula

Fx Copy

LaTeX Copy

Periodic Time for Compound Pendulum is the time taken by a complete cycle of the wave to pass a point. Check FAQs

t' p = 2 \cdot π \cdot \sqrt{\frac{{k G}^{2} + h^{2}}{g \cdot h}}

t'_p - Periodic Time for Compound Pendulum?k_G - Radius of Gyration?h - Distance of PT of Suspension of Pendulum From CG?g - Acceleration Due to Gravity?π - Archimedes' constant?

Periodic Time of SHM for Compound Pendulum given Radius of Gyration Example

With values

With units

Only example

Here is how the Periodic Time of SHM for Compound Pendulum given Radius of Gyration equation looks like with Values.

Here is how the Periodic Time of SHM for Compound Pendulum given Radius of Gyration equation looks like with Units.

Here is how the Periodic Time of SHM for Compound Pendulum given Radius of Gyration equation looks like.

5 = 2 \cdot 3.1416 \cdot \sqrt{\frac{3103^{2} + 3100^{2}}{9.8 \cdot 3100}}

5s = 2 \cdot 3.1416 \cdot \sqrt{\frac{{3103mm}^{2} + {3100mm}^{2}}{9.8m/s² \cdot 3100mm}}

5 = 2 \cdot 3.1416 \cdot \sqrt{\frac{3103^{2} + 3100^{2}}{9.8 \cdot 3100}}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Physics » Category

Mechanical » Category

Theory of Machine » fx Periodic Time of SHM for Compound Pendulum given Radius of Gyration

Periodic Time of SHM for Compound Pendulum given Radius of Gyration Solution

Follow our step by step solution on how to calculate Periodic Time of SHM for Compound Pendulum given Radius of Gyration?

FIRST Step Consider the formula

t' p = 2 \cdot π \cdot \sqrt{\frac{{k G}^{2} + h^{2}}{g \cdot h}}

Next Step Substitute values of Variables

∴

t' p = 2 \cdot π \cdot \sqrt{\frac{{3103mm}^{2} + {3100mm}^{2}}{9.8m/s² \cdot 3100mm}}

Next Step Substitute values of Constants

∴

t' p = 2 \cdot 3.1416 \cdot \sqrt{\frac{{3103mm}^{2} + {3100mm}^{2}}{9.8m/s² \cdot 3100mm}}

Next Step Convert Units

∴

t' p = 2 \cdot 3.1416 \cdot \sqrt{\frac{{3.103m}^{2} + {3.1m}^{2}}{9.8m/s² \cdot 3.1m}}

Next Step Prepare to Evaluate

∴

t' p = 2 \cdot 3.1416 \cdot \sqrt{\frac{{3.103}^{2} + {3.1}^{2}}{9.8 \cdot 3.1}}

Next Step Evaluate

∴

t' p = 5.00003239037879s

LAST Step Rounding Answer

∴

t' p = 5s

Periodic Time of SHM for Compound Pendulum given Radius of Gyration Formula Elements

Variables

Constants

Functions

Periodic Time for Compound Pendulum

Periodic Time for Compound Pendulum is the time taken by a complete cycle of the wave to pass a point.

Symbol: t'_p

Measurement: TimeUnit: s

Note: Value should be greater than 0.

Formulas to find Periodic Time for Compound Pendulum

Radius of Gyration

The Radius of Gyration or gyradius is defined as the radial distance to a point that would have a moment of inertia the same as the body's actual distribution of mass.

Symbol: k_G

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Radius of Gyration

Distance of PT of Suspension of Pendulum From CG

Distance of PT of Suspension of Pendulum From CG is measured length between that point and center of gravity of the body.

Symbol: h

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Distance of PT of Suspension of Pendulum From CG

Acceleration Due to Gravity

Acceleration Due to Gravity is acceleration gained by an object because of gravitational force.

Symbol: g

Measurement: AccelerationUnit: m/s²

Note: Value should be greater than 0.

Formulas to find Acceleration Due to Gravity

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other formulas in Compound Pendulum category

Go Minimum Periodic Time of SHM for Compound Pendulum

t p = 2 \cdot π \cdot \sqrt{2 \cdot \frac{k G}{g}}

Go Frequency of Compound Pendulum in SHM

f = \frac{1}{t' p}

How to Evaluate Periodic Time of SHM for Compound Pendulum given Radius of Gyration?

Periodic Time of SHM for Compound Pendulum given Radius of Gyration evaluator uses Periodic Time for Compound Pendulum = 2*pi*sqrt((Radius of Gyration^2+Distance of PT of Suspension of Pendulum From CG^2)/(Acceleration Due to Gravity*Distance of PT of Suspension of Pendulum From CG)) to evaluate the Periodic Time for Compound Pendulum, Periodic Time of SHM for Compound Pendulum given Radius of Gyration formula is defined as a measure of the time taken by the compound pendulum to complete one oscillation, which depends on the radius of gyration, gravitational acceleration, and the height of the pendulum. Periodic Time for Compound Pendulum is denoted by t'_p symbol.

How to evaluate Periodic Time of SHM for Compound Pendulum given Radius of Gyration using this online evaluator? To use this online evaluator for Periodic Time of SHM for Compound Pendulum given Radius of Gyration, enter Radius of Gyration (k_G), Distance of PT of Suspension of Pendulum From CG (h) & Acceleration Due to Gravity (g) and hit the calculate button.

FAQs on Periodic Time of SHM for Compound Pendulum given Radius of Gyration

What is the formula to find Periodic Time of SHM for Compound Pendulum given Radius of Gyration?

The formula of Periodic Time of SHM for Compound Pendulum given Radius of Gyration is expressed as Periodic Time for Compound Pendulum = 2*pi*sqrt((Radius of Gyration^2+Distance of PT of Suspension of Pendulum From CG^2)/(Acceleration Due to Gravity*Distance of PT of Suspension of Pendulum From CG)). Here is an example- 30.39231 = 2*pi*sqrt((3.103^2+3.1^2)/(9.8*3.1)).

How to calculate Periodic Time of SHM for Compound Pendulum given Radius of Gyration?

With Radius of Gyration (k_G), Distance of PT of Suspension of Pendulum From CG (h) & Acceleration Due to Gravity (g) we can find Periodic Time of SHM for Compound Pendulum given Radius of Gyration using the formula - Periodic Time for Compound Pendulum = 2*pi*sqrt((Radius of Gyration^2+Distance of PT of Suspension of Pendulum From CG^2)/(Acceleration Due to Gravity*Distance of PT of Suspension of Pendulum From CG)). This formula also uses Archimedes' constant and Square Root (sqrt) function(s).

Can the Periodic Time of SHM for Compound Pendulum given Radius of Gyration be negative?

Yes, the Periodic Time of SHM for Compound Pendulum given Radius of Gyration, measured in Time can be negative.

Which unit is used to measure Periodic Time of SHM for Compound Pendulum given Radius of Gyration?

Periodic Time of SHM for Compound Pendulum given Radius of Gyration is usually measured using the Second[s] for Time. Millisecond[s], Microsecond[s], Nanosecond[s] are the few other units in which Periodic Time of SHM for Compound Pendulum given Radius of Gyration can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Periodic Time of SHM for Compound Pendulum given Radius of Gyration Formula

Periodic Time of SHM for Compound Pendulum given Radius of Gyration Example

Periodic Time of SHM for Compound Pendulum given Radius of Gyration Solution

Periodic Time of SHM for Compound Pendulum given Radius of Gyration Formula Elements

Other formulas in Compound Pendulum category

How to Evaluate Periodic Time of SHM for Compound Pendulum given Radius of Gyration?

FAQs on Periodic Time of SHM for Compound Pendulum given Radius of Gyration

Variable Name