FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Periodic Time for SHM Formula

GoPeriodic Time of Particle Moving with Angular Simple Harmonic Motion Formula

Fx Copy

LaTeX Copy

Time Period SHM is time required for the periodic motion. Check FAQs

t p = 2 \cdot π \cdot \sqrt{\frac{d m}{g}}

t_p - Time Period SHM?d_m - Total Displacement?g - Acceleration Due to Gravity?π - Archimedes' constant?

Periodic Time for SHM Example

With values

With units

Only example

Here is how the Periodic Time for SHM equation looks like with Values.

Here is how the Periodic Time for SHM equation looks like with Units.

Here is how the Periodic Time for SHM equation looks like.

5 = 2 \cdot 3.1416 \cdot \sqrt{\frac{6206}{9.8}}

5s = 2 \cdot 3.1416 \cdot \sqrt{\frac{6206mm}{9.8m/s²}}

5 = 2 \cdot 3.1416 \cdot \sqrt{\frac{6206}{9.8}}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Physics » Category

Mechanical » Category

Theory of Machine » fx Periodic Time for SHM

Periodic Time for SHM Solution

Follow our step by step solution on how to calculate Periodic Time for SHM?

FIRST Step Consider the formula

t p = 2 \cdot π \cdot \sqrt{\frac{d m}{g}}

Next Step Substitute values of Variables

∴

t p = 2 \cdot π \cdot \sqrt{\frac{6206mm}{9.8m/s²}}

Next Step Substitute values of Constants

∴

t p = 2 \cdot 3.1416 \cdot \sqrt{\frac{6206mm}{9.8m/s²}}

Next Step Convert Units

∴

t p = 2 \cdot 3.1416 \cdot \sqrt{\frac{6.206m}{9.8m/s²}}

Next Step Prepare to Evaluate

∴

t p = 2 \cdot 3.1416 \cdot \sqrt{\frac{6.206}{9.8}}

Next Step Evaluate

∴

t p = 5.00003122084785s

LAST Step Rounding Answer

∴

t p = 5s

Periodic Time for SHM Formula Elements

Variables

Constants

Functions

Time Period SHM

Time Period SHM is time required for the periodic motion.

Symbol: t_p

Measurement: TimeUnit: s

Note: Value should be greater than 0.

Formulas to find Time Period SHM

Total Displacement

Total Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Symbol: d_m

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Total Displacement

Acceleration Due to Gravity

Acceleration Due to Gravity is acceleration gained by an object because of gravitational force.

Symbol: g

Measurement: AccelerationUnit: m/s²

Note: Value should be greater than 0.

Formulas to find Acceleration Due to Gravity

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Time Period SHM

Go Periodic Time of Particle Moving with Angular Simple Harmonic Motion

t p = 2 \cdot π \cdot \sqrt{\frac{θ}{α}}

Other formulas in Basics category

Go Frequency of Oscillation for SHM

f = \frac{1}{t p}

Go Frequency of Particle Moving with Angular Simple Harmonic Motion

f = \frac{\sqrt{\frac{α}{θ}}}{2 \cdot π}

How to Evaluate Periodic Time for SHM?

Periodic Time for SHM evaluator uses Time Period SHM = 2*pi*sqrt(Total Displacement/Acceleration Due to Gravity) to evaluate the Time Period SHM, Periodic Time for SHM formula is defined as the time taken by an object to complete one oscillation in simple harmonic motion, which depends on the mass of the object and the gravitational acceleration, providing a fundamental characteristic of the motion. Time Period SHM is denoted by t_p symbol.

How to evaluate Periodic Time for SHM using this online evaluator? To use this online evaluator for Periodic Time for SHM, enter Total Displacement (d_m) & Acceleration Due to Gravity (g) and hit the calculate button.

FAQs on Periodic Time for SHM

What is the formula to find Periodic Time for SHM?

The formula of Periodic Time for SHM is expressed as Time Period SHM = 2*pi*sqrt(Total Displacement/Acceleration Due to Gravity). Here is an example- 0.249073 = 2*pi*sqrt(6.206/9.8).

How to calculate Periodic Time for SHM?

With Total Displacement (d_m) & Acceleration Due to Gravity (g) we can find Periodic Time for SHM using the formula - Time Period SHM = 2*pi*sqrt(Total Displacement/Acceleration Due to Gravity). This formula also uses Archimedes' constant and Square Root Function function(s).

What are the other ways to Calculate Time Period SHM?

Here are the different ways to Calculate Time Period SHM-

Time Period SHM=2*pi*sqrt(Angular Displacement/Angular Acceleration)

Can the Periodic Time for SHM be negative?

No, the Periodic Time for SHM, measured in Time cannot be negative.

Which unit is used to measure Periodic Time for SHM?

Periodic Time for SHM is usually measured using the Second[s] for Time. Millisecond[s], Microsecond[s], Nanosecond[s] are the few other units in which Periodic Time for SHM can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Periodic Time for SHM Formula

​GoPeriodic Time of Particle Moving with Angular Simple Harmonic Motion Formula

Periodic Time for SHM Example

Periodic Time for SHM Solution

Periodic Time for SHM Formula Elements

Other Formulas to find Time Period SHM

Other formulas in Basics category

How to Evaluate Periodic Time for SHM?

FAQs on Periodic Time for SHM

Variable Name

GoPeriodic Time of Particle Moving with Angular Simple Harmonic Motion Formula