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Percentage of Sand given Unit Weight of Deposit Formula

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Percentage of Sand on weight basis present in the sediment deposit. Check FAQs

p sa = \frac{(W av) - ((\frac{p si}{100}) \cdot (W 2 + B 2 \cdot \log 10 (T))) - ((\frac{p cl}{100}) \cdot (W 3 + B 3 \cdot \log 10 (T)))}{\frac{W 1 + B 1 \cdot \log 10 (T)}{100}}

p_sa - Percentage of Sand?W_av - Average Unit Weight of Deposit?p_si - Percentage of Silt?W₂ - Unit Weight of Silt?B₂ - Constant B2?T - Age of Sediment?p_cl - Percentage of Clay?W₃ - Unit Weight of Clay?B₃ - Constant B3?W₁ - Unit Weight of Sand?B₁ - Constant B1?

Percentage of Sand given Unit Weight of Deposit Example

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Here is how the Percentage of Sand given Unit Weight of Deposit equation looks like with Values.

Here is how the Percentage of Sand given Unit Weight of Deposit equation looks like with Units.

Here is how the Percentage of Sand given Unit Weight of Deposit equation looks like.

20.0606 = \frac{(15.06) - ((\frac{35}{100}) \cdot (19 + 0.1 \cdot \log 10 (25))) - ((\frac{31.3}{100}) \cdot (16 + 40 \cdot \log 10 (25)))}{\frac{16.4 + 0.2 \cdot \log 10 (25)}{100}}

20.0606 = \frac{(15.06kN/m³) - ((\frac{35}{100}) \cdot (19kN/m³ + 0.1 \cdot \log 10 (25Year))) - ((\frac{31.3}{100}) \cdot (16kN/m³ + 40 \cdot \log 10 (25Year)))}{\frac{16.4kN/m³ + 0.2 \cdot \log 10 (25Year)}{100}}

20.0606 = \frac{(15.06) - ((\frac{35}{100}) \cdot (19 + 0.1 \cdot \log 10 (25))) - ((\frac{31.3}{100}) \cdot (16 + 40 \cdot \log 10 (25)))}{\frac{16.4 + 0.2 \cdot \log 10 (25)}{100}}

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Percentage of Sand given Unit Weight of Deposit Solution

Follow our step by step solution on how to calculate Percentage of Sand given Unit Weight of Deposit?

FIRST Step Consider the formula

p sa = \frac{(W av) - ((\frac{p si}{100}) \cdot (W 2 + B 2 \cdot \log 10 (T))) - ((\frac{p cl}{100}) \cdot (W 3 + B 3 \cdot \log 10 (T)))}{\frac{W 1 + B 1 \cdot \log 10 (T)}{100}}

Next Step Substitute values of Variables

∴

p sa = \frac{(15.06kN/m³) - ((\frac{35}{100}) \cdot (19kN/m³ + 0.1 \cdot \log 10 (25Year))) - ((\frac{31.3}{100}) \cdot (16kN/m³ + 40 \cdot \log 10 (25Year)))}{\frac{16.4kN/m³ + 0.2 \cdot \log 10 (25Year)}{100}}

Next Step Convert Units

∴

p sa = \frac{(15060N/m³) - ((\frac{35}{100}) \cdot (19000N/m³ + 0.1 \cdot \log 10 (7.9E+8s))) - ((\frac{31.3}{100}) \cdot (16000N/m³ + 40 \cdot \log 10 (7.9E+8s)))}{\frac{16400N/m³ + 0.2 \cdot \log 10 (7.9E+8s)}{100}}

Next Step Prepare to Evaluate

∴

p sa = \frac{(15060) - ((\frac{35}{100}) \cdot (19000 + 0.1 \cdot \log 10 (7.9E+8))) - ((\frac{31.3}{100}) \cdot (16000 + 40 \cdot \log 10 (7.9E+8)))}{\frac{16400 + 0.2 \cdot \log 10 (7.9E+8)}{100}}

Next Step Evaluate

∴

p sa = 20.0606144199288

LAST Step Rounding Answer

∴

p sa = 20.0606

Percentage of Sand given Unit Weight of Deposit Formula Elements

Variables

Functions

Percentage of Sand

Percentage of Sand on weight basis present in the sediment deposit.

Symbol: p_sa

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Percentage of Sand

Average Unit Weight of Deposit

Average Unit Weight of Deposit refers to the weight per unit volume of sediment material deposited in a reservoir during a specific period.

Symbol: W_av

Measurement: Specific WeightUnit: kN/m³

Note: Value should be greater than 0.

Formulas to find Average Unit Weight of Deposit

Percentage of Silt

Percentage of Silt on weight basis present in the sediment deposit.

Symbol: p_si

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Percentage of Silt

Unit Weight of Silt

Unit Weight of Silt is the weight (mass multiplied by gravity) per unit volume of silt material at the end of the first year.

Symbol: W₂

Measurement: Specific WeightUnit: kN/m³

Note: Value should be greater than 0.

Formulas to find Unit Weight of Silt

Constant B2

Constant B2 is related to the compacting characteristics of the sediment components.

Symbol: B₂

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Constant B2

Age of Sediment

Age of Sediment is the time elapsed since the material was deposited in years.

Symbol: T

Measurement: TimeUnit: Year

Note: Value should be greater than 0.

Formulas to find Age of Sediment

Percentage of Clay

Percentage of Clay on weight basis present in the sediment deposit.

Symbol: p_cl

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Percentage of Clay

Unit Weight of Clay

Unit Weight of Clay is the weight (mass multiplied by gravity) per unit volume of clay material at the end of the first year.

Symbol: W₃

Measurement: Specific WeightUnit: kN/m³

Note: Value should be greater than 0.

Formulas to find Unit Weight of Clay

Constant B3

Constant B3 is related to the compacting characteristics of the sediment components.

Symbol: B₃

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Constant B3

Unit Weight of Sand

Unit Weight of Sand is the weight (mass multiplied by gravity) per unit volume of sand material at the end of the first year.

Symbol: W₁

Measurement: Specific WeightUnit: kN/m³

Note: Value should be greater than 0.

Formulas to find Unit Weight of Sand

Constant B1

Constant B1 is related to the compacting characteristics of the sediment components.

Symbol: B₁

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Constant B1

log10

The common logarithm, also known as the base-10 logarithm or the decimal logarithm, is a mathematical function that is the inverse of the exponential function.

Syntax: log10(Number)

Other formulas in Density of Sediment Deposits category

Go Rough Estimation for Unit Weight of Deposit by Koelzer and Lara Formula

W T = ((\frac{p sa}{100}) \cdot (W 1 + B 1 \cdot \log 10 (T))) + ((\frac{p si}{100}) \cdot (W 2 + B 2 \cdot \log 10 (T))) + ((\frac{p cl}{100}) \cdot (W 3 + B 3 \cdot \log 10 (T)))

Go Percentage of Silt for Unit Weight of Deposits

p si = \frac{(W av) - ((\frac{p sa}{100}) \cdot (W 1 + B 1 \cdot \log 10 (T))) - ((\frac{p cl}{100}) \cdot (W 3 + B 3 \cdot \log 10 (T)))}{\frac{W 2 + B 2 \cdot \log 10 (T)}{100}}

How to Evaluate Percentage of Sand given Unit Weight of Deposit?

Percentage of Sand given Unit Weight of Deposit evaluator uses Percentage of Sand = ((Average Unit Weight of Deposit)-((Percentage of Silt/100)*(Unit Weight of Silt+Constant B2*log10(Age of Sediment)))-((Percentage of Clay/100)*(Unit Weight of Clay+Constant B3*log10(Age of Sediment))))/((Unit Weight of Sand+Constant B1*log10(Age of Sediment))/100) to evaluate the Percentage of Sand, The Percentage of Sand given Unit Weight of Deposit formula is defined as the total percentage of sand on weight basis present in the sediment deposit. Percentage of Sand is denoted by p_sa symbol.

How to evaluate Percentage of Sand given Unit Weight of Deposit using this online evaluator? To use this online evaluator for Percentage of Sand given Unit Weight of Deposit, enter Average Unit Weight of Deposit (W_av), Percentage of Silt (p_si), Unit Weight of Silt (W₂), Constant B2 (B₂), Age of Sediment (T), Percentage of Clay (p_cl), Unit Weight of Clay (W₃), Constant B3 (B₃), Unit Weight of Sand (W₁) & Constant B1 (B₁) and hit the calculate button.

FAQs on Percentage of Sand given Unit Weight of Deposit

What is the formula to find Percentage of Sand given Unit Weight of Deposit?

The formula of Percentage of Sand given Unit Weight of Deposit is expressed as Percentage of Sand = ((Average Unit Weight of Deposit)-((Percentage of Silt/100)*(Unit Weight of Silt+Constant B2*log10(Age of Sediment)))-((Percentage of Clay/100)*(Unit Weight of Clay+Constant B3*log10(Age of Sediment))))/((Unit Weight of Sand+Constant B1*log10(Age of Sediment))/100). Here is an example- 20.06061 = ((15060)-((35/100)*(19000+0.1*log10(788923800)))-((31.3/100)*(16000+40*log10(788923800))))/((16400+0.2*log10(788923800))/100).

How to calculate Percentage of Sand given Unit Weight of Deposit?

With Average Unit Weight of Deposit (W_av), Percentage of Silt (p_si), Unit Weight of Silt (W₂), Constant B2 (B₂), Age of Sediment (T), Percentage of Clay (p_cl), Unit Weight of Clay (W₃), Constant B3 (B₃), Unit Weight of Sand (W₁) & Constant B1 (B₁) we can find Percentage of Sand given Unit Weight of Deposit using the formula - Percentage of Sand = ((Average Unit Weight of Deposit)-((Percentage of Silt/100)*(Unit Weight of Silt+Constant B2*log10(Age of Sediment)))-((Percentage of Clay/100)*(Unit Weight of Clay+Constant B3*log10(Age of Sediment))))/((Unit Weight of Sand+Constant B1*log10(Age of Sediment))/100). This formula also uses Common Logarithm (log10) function(s).

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Percentage of Sand given Unit Weight of Deposit Formula

Percentage of Sand given Unit Weight of Deposit Example

Percentage of Sand given Unit Weight of Deposit Solution

Percentage of Sand given Unit Weight of Deposit Formula Elements

Other formulas in Density of Sediment Deposits category

How to Evaluate Percentage of Sand given Unit Weight of Deposit?

FAQs on Percentage of Sand given Unit Weight of Deposit

Variable Name