Fx Copy
LaTeX Copy
Percent Enantiomeric Excess is a measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other. Check FAQs
%ee=(|R-S|R+S)100
%ee - Percent Enantiomeric Excess?R - Moles of R?S - Moles of S?

Percent Enantiomeric Excess Considering Amount of Enantiomer Example

With values
With units
Only example

Here is how the Percent Enantiomeric Excess Considering Amount of Enantiomer equation looks like with Values.

Here is how the Percent Enantiomeric Excess Considering Amount of Enantiomer equation looks like with Units.

Here is how the Percent Enantiomeric Excess Considering Amount of Enantiomer equation looks like.

39.1304Edit=(|12.8Edit-5.6Edit|12.8Edit+5.6Edit)100
You are here -
HomeIcon Home » Category Chemistry » Category Organic Chemistry » Category Optical Activity » fx Percent Enantiomeric Excess Considering Amount of Enantiomer

Percent Enantiomeric Excess Considering Amount of Enantiomer Solution

Follow our step by step solution on how to calculate Percent Enantiomeric Excess Considering Amount of Enantiomer?

FIRST Step Consider the formula
%ee=(|R-S|R+S)100
Next Step Substitute values of Variables
%ee=(|12.8mol-5.6mol|12.8mol+5.6mol)100
Next Step Prepare to Evaluate
%ee=(|12.8-5.6|12.8+5.6)100
Next Step Evaluate
%ee=39.1304347826087
LAST Step Rounding Answer
%ee=39.1304

Percent Enantiomeric Excess Considering Amount of Enantiomer Formula Elements

Variables
Functions
Percent Enantiomeric Excess
Percent Enantiomeric Excess is a measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other.
Symbol: %ee
Measurement: NAUnit: Unitless
Note: Value can be positive or negative.
Moles of R
Moles of R is the unit of measurement for amount of substance, a quantity proportional to the number of elementary entities of a substance.
Symbol: R
Measurement: Amount of SubstanceUnit: mol
Note: Value can be positive or negative.
Moles of S
Moles of S is the unit of measurement for amount of substance, a quantity proportional to the number of elementary entities of a substance.
Symbol: S
Measurement: Amount of SubstanceUnit: mol
Note: Value can be positive or negative.
abs
The absolute value of a number is its distance from zero on the number line. It's always a positive value, as it represents the magnitude of a number without considering its direction.
Syntax: abs(Number)

Other Formulas to find Percent Enantiomeric Excess

​Go Percent Enantiomeric Excess
%ee=|FR-FS|100

Other formulas in Optical Activity category

​Go Specific Rotation of Optically Active Compound
[α]D=αlc
​Go Optical Purity
OP=([α]obs[α]max)100
​Go Enantiomeric Excess
ee=|FR-FS|
​Go Fraction of Major Isomer
FR=50+(%ee2)

How to Evaluate Percent Enantiomeric Excess Considering Amount of Enantiomer?

Percent Enantiomeric Excess Considering Amount of Enantiomer evaluator uses Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100 to evaluate the Percent Enantiomeric Excess, The Percent Enantiomeric Excess Considering Amount of Enantiomer formula is defined as measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other. Percent Enantiomeric Excess is denoted by %ee symbol.

How to evaluate Percent Enantiomeric Excess Considering Amount of Enantiomer using this online evaluator? To use this online evaluator for Percent Enantiomeric Excess Considering Amount of Enantiomer, enter Moles of R (R) & Moles of S (S) and hit the calculate button.

FAQs on Percent Enantiomeric Excess Considering Amount of Enantiomer

What is the formula to find Percent Enantiomeric Excess Considering Amount of Enantiomer?
The formula of Percent Enantiomeric Excess Considering Amount of Enantiomer is expressed as Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100. Here is an example- 45.45455 = (abs(12.8-5.6)/(12.8+5.6))*100.
How to calculate Percent Enantiomeric Excess Considering Amount of Enantiomer?
With Moles of R (R) & Moles of S (S) we can find Percent Enantiomeric Excess Considering Amount of Enantiomer using the formula - Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100. This formula also uses Absolute (abs) function(s).
What are the other ways to Calculate Percent Enantiomeric Excess?
Here are the different ways to Calculate Percent Enantiomeric Excess-
  • Percent Enantiomeric Excess=abs(Mole Fraction of R-Mole Fraction of S)*100OpenImg
Copied!