FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Pentagonal Face Area of Icosidodecahedron given Volume Formula

GoPentagonal Face Area of Icosidodecahedron Formula

GoPentagonal Face Area of Icosidodecahedron given Circumsphere Radius Formula

Fx Copy

LaTeX Copy

Pentagonal Face Area of Icosidodecahedron is the total quantity of two dimensional space enclosed on any of the pentagonal faces of the Icosidodecahedron. Check FAQs

A Pentagon = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot \frac{{(\frac{6 \cdot V}{45 + (17 \cdot \sqrt{5})})}^{\frac{2}{3}}}{4}

A_Pentagon - Pentagonal Face Area of Icosidodecahedron?V - Volume of Icosidodecahedron?

Pentagonal Face Area of Icosidodecahedron given Volume Example

With values

With units

Only example

Here is how the Pentagonal Face Area of Icosidodecahedron given Volume equation looks like with Values.

Here is how the Pentagonal Face Area of Icosidodecahedron given Volume equation looks like with Units.

Here is how the Pentagonal Face Area of Icosidodecahedron given Volume equation looks like.

173.4086 = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot \frac{{(\frac{6 \cdot 14000}{45 + (17 \cdot \sqrt{5})})}^{\frac{2}{3}}}{4}

173.4086m² = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot \frac{{(\frac{6 \cdot 14000m³}{45 + (17 \cdot \sqrt{5})})}^{\frac{2}{3}}}{4}

173.4086 = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot \frac{{(\frac{6 \cdot 14000}{45 + (17 \cdot \sqrt{5})})}^{\frac{2}{3}}}{4}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Math » Category

Geometry » Category

3D Geometry » fx Pentagonal Face Area of Icosidodecahedron given Volume

Pentagonal Face Area of Icosidodecahedron given Volume Solution

Follow our step by step solution on how to calculate Pentagonal Face Area of Icosidodecahedron given Volume?

FIRST Step Consider the formula

A Pentagon = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot \frac{{(\frac{6 \cdot V}{45 + (17 \cdot \sqrt{5})})}^{\frac{2}{3}}}{4}

Next Step Substitute values of Variables

∴

A Pentagon = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot \frac{{(\frac{6 \cdot 14000m³}{45 + (17 \cdot \sqrt{5})})}^{\frac{2}{3}}}{4}

Next Step Prepare to Evaluate

∴

A Pentagon = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot \frac{{(\frac{6 \cdot 14000}{45 + (17 \cdot \sqrt{5})})}^{\frac{2}{3}}}{4}

Next Step Evaluate

∴

A Pentagon = 173.408566269411m²

LAST Step Rounding Answer

∴

A Pentagon = 173.4086m²

Pentagonal Face Area of Icosidodecahedron given Volume Formula Elements

Variables

Functions

Pentagonal Face Area of Icosidodecahedron

Pentagonal Face Area of Icosidodecahedron is the total quantity of two dimensional space enclosed on any of the pentagonal faces of the Icosidodecahedron.

Symbol: A_Pentagon

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Pentagonal Face Area of Icosidodecahedron

Volume of Icosidodecahedron

Volume of Icosidodecahedron is the total quantity of three dimensional space enclosed by the surface of the Icosidodecahedron.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume of Icosidodecahedron

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Pentagonal Face Area of Icosidodecahedron

Go Pentagonal Face Area of Icosidodecahedron

A Pentagon = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot \frac{{l e}^{2}}{4}

Go Pentagonal Face Area of Icosidodecahedron given Circumsphere Radius

A Pentagon = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot {(\frac{r c}{1 + \sqrt{5}})}^{2}

Go Pentagonal Face Area of Icosidodecahedron given Midsphere Radius

A Pentagon = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot {(\frac{r m}{\sqrt{5 + (2 \cdot \sqrt{5})}})}^{2}

Go Pentagonal Face Area of Icosidodecahedron given Total Surface Area

A Pentagon = \sqrt{25 + (10 \cdot \sqrt{5})} \cdot \frac{TSA}{4 \cdot ((5 \cdot \sqrt{3}) + (3 \cdot \sqrt{25 + (10 \cdot \sqrt{5})}))}

How to Evaluate Pentagonal Face Area of Icosidodecahedron given Volume?

Pentagonal Face Area of Icosidodecahedron given Volume evaluator uses Pentagonal Face Area of Icosidodecahedron = sqrt(25+(10*sqrt(5)))*(((6*Volume of Icosidodecahedron)/(45+(17*sqrt(5))))^(2/3))/4 to evaluate the Pentagonal Face Area of Icosidodecahedron, Pentagonal Face Area of Icosidodecahedron given Volume formula is defined as the total quantity of two dimensional space enclosed on any of the pentagonal faces of the Icosidodecahedron, and calculated using the volume of the Icosidodecahedron. Pentagonal Face Area of Icosidodecahedron is denoted by A_Pentagon symbol.

How to evaluate Pentagonal Face Area of Icosidodecahedron given Volume using this online evaluator? To use this online evaluator for Pentagonal Face Area of Icosidodecahedron given Volume, enter Volume of Icosidodecahedron (V) and hit the calculate button.

FAQs on Pentagonal Face Area of Icosidodecahedron given Volume

What is the formula to find Pentagonal Face Area of Icosidodecahedron given Volume?

The formula of Pentagonal Face Area of Icosidodecahedron given Volume is expressed as Pentagonal Face Area of Icosidodecahedron = sqrt(25+(10*sqrt(5)))*(((6*Volume of Icosidodecahedron)/(45+(17*sqrt(5))))^(2/3))/4. Here is an example- 173.4086 = sqrt(25+(10*sqrt(5)))*(((6*14000)/(45+(17*sqrt(5))))^(2/3))/4.

How to calculate Pentagonal Face Area of Icosidodecahedron given Volume?

With Volume of Icosidodecahedron (V) we can find Pentagonal Face Area of Icosidodecahedron given Volume using the formula - Pentagonal Face Area of Icosidodecahedron = sqrt(25+(10*sqrt(5)))*(((6*Volume of Icosidodecahedron)/(45+(17*sqrt(5))))^(2/3))/4. This formula also uses Square Root (sqrt) function(s).

What are the other ways to Calculate Pentagonal Face Area of Icosidodecahedron?

Here are the different ways to Calculate Pentagonal Face Area of Icosidodecahedron-

Pentagonal Face Area of Icosidodecahedron=sqrt(25+(10*sqrt(5)))*(Edge Length of Icosidodecahedron^2)/4
Pentagonal Face Area of Icosidodecahedron=sqrt(25+(10*sqrt(5)))*(Circumsphere Radius of Icosidodecahedron/(1+sqrt(5)))^2
Pentagonal Face Area of Icosidodecahedron=sqrt(25+(10*sqrt(5)))*(Midsphere Radius of Icosidodecahedron/(sqrt(5+(2*sqrt(5)))))^2

Can the Pentagonal Face Area of Icosidodecahedron given Volume be negative?

No, the Pentagonal Face Area of Icosidodecahedron given Volume, measured in Area cannot be negative.

Which unit is used to measure Pentagonal Face Area of Icosidodecahedron given Volume?

Pentagonal Face Area of Icosidodecahedron given Volume is usually measured using the Square Meter[m²] for Area. Square Kilometer[m²], Square Centimeter[m²], Square Millimeter[m²] are the few other units in which Pentagonal Face Area of Icosidodecahedron given Volume can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit