FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Partial Pressure using Raoult's Law Formula

Fx Copy

LaTeX Copy

Equilibrium Partial Pressure A is the partial pressure for both homogeneous and heterogeneous reactions involving gas A. Check FAQs

p A = x A \cdot PA o

p_A - Equilibrium Partial Pressure A?x_A - Mole Fraction of Component A in Liquid Phase?PA^o - Vapor Pressure of Pure Component A?

Partial Pressure using Raoult's Law Example

With values

With units

Only example

Here is how the Partial Pressure using Raoult's Law equation looks like with Values.

Here is how the Partial Pressure using Raoult's Law equation looks like with Units.

Here is how the Partial Pressure using Raoult's Law equation looks like.

540 = 0.2 \cdot 2700

540Pa = 0.2 \cdot 2700Pa

540 = 0.2 \cdot 2700

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Chemical Engineering » Category

Mass Transfer Operations » fx Partial Pressure using Raoult's Law

Partial Pressure using Raoult's Law Solution

Follow our step by step solution on how to calculate Partial Pressure using Raoult's Law?

FIRST Step Consider the formula

p A = x A \cdot PA o

Next Step Substitute values of Variables

∴

p A = 0.2 \cdot 2700Pa

Next Step Prepare to Evaluate

∴

p A = 0.2 \cdot 2700

LAST Step Evaluate

∴

p A = 540Pa

Partial Pressure using Raoult's Law Formula Elements

Variables

Equilibrium Partial Pressure A

Equilibrium Partial Pressure A is the partial pressure for both homogeneous and heterogeneous reactions involving gas A.

Symbol: p_A

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Equilibrium Partial Pressure A

Mole Fraction of Component A in Liquid Phase

The Mole Fraction of Component A in Liquid Phase refers to the mole fraction of component A which is in the liquid phase.

Symbol: x_A

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Mole Fraction of Component A in Liquid Phase

Vapor Pressure of Pure Component A

Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.

Symbol: PA^o

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Vapor Pressure of Pure Component A

Other formulas in Mass Transfer Driving Force category

Go Logarithmic Mean of Concentration Difference

C bm = \frac{C b2 - C b1}{\ln (\frac{C b2}{C b1})}

Go Logarithmic Mean Partial Pressure Difference

P bm = \frac{P b2 - P b1}{\ln (\frac{P b2}{P b1})}

Go Total Concentration

C = C a + C b

How to Evaluate Partial Pressure using Raoult's Law?

Partial Pressure using Raoult's Law evaluator uses Equilibrium Partial Pressure A = Mole Fraction of Component A in Liquid Phase*Vapor Pressure of Pure Component A to evaluate the Equilibrium Partial Pressure A, Partial Pressure using Raoult's Law calculates the partial pressure of a given component in a mixture when the component's mole fraction in the liquid phase and the pure component vapor pressure is known. Equilibrium Partial Pressure A is denoted by p_A symbol.

How to evaluate Partial Pressure using Raoult's Law using this online evaluator? To use this online evaluator for Partial Pressure using Raoult's Law, enter Mole Fraction of Component A in Liquid Phase (x_A) & Vapor Pressure of Pure Component A (PA^o) and hit the calculate button.

FAQs on Partial Pressure using Raoult's Law

What is the formula to find Partial Pressure using Raoult's Law?

The formula of Partial Pressure using Raoult's Law is expressed as Equilibrium Partial Pressure A = Mole Fraction of Component A in Liquid Phase*Vapor Pressure of Pure Component A. Here is an example- 540 = 0.2*2700.

How to calculate Partial Pressure using Raoult's Law?

With Mole Fraction of Component A in Liquid Phase (x_A) & Vapor Pressure of Pure Component A (PA^o) we can find Partial Pressure using Raoult's Law using the formula - Equilibrium Partial Pressure A = Mole Fraction of Component A in Liquid Phase*Vapor Pressure of Pure Component A.

Can the Partial Pressure using Raoult's Law be negative?

Yes, the Partial Pressure using Raoult's Law, measured in Pressure can be negative.

Which unit is used to measure Partial Pressure using Raoult's Law?

Partial Pressure using Raoult's Law is usually measured using the Pascal[Pa] for Pressure. Kilopascal[Pa], Bar[Pa], Pound Per Square Inch[Pa] are the few other units in which Partial Pressure using Raoult's Law can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit