FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Output Current for Boost Regulator (DCM) Formula

Fx Copy

LaTeX Copy

Output Current of Boost DCM is the current the amplifier draws from the signal source. Check FAQs

i o(bo_dcm) = \frac{({V i(bo_dcm)}^{2}) \cdot {D bo_dcm}^{2} \cdot t c(bo_dcm)}{2 \cdot L x(bo_dcm) \cdot (V o(bo_dcm) - V i(bo_dcm))}

i_{o(bo_dcm)} - Output Current of Boost DCM?V_{i(bo_dcm)} - Input Voltage of Boost DCM?D_{bo_dcm} - Duty Cycle of Boost DCM?t_{c(bo_dcm)} - Time Commutation of Boost DCM?L_{x(bo_dcm)} - Critical Inductance of Boost DCM?V_{o(bo_dcm)} - Output Voltage of Boost DCM?

Output Current for Boost Regulator (DCM) Example

With values

With units

Only example

Here is how the Output Current for Boost Regulator (DCM) equation looks like with Values.

Here is how the Output Current for Boost Regulator (DCM) equation looks like with Units.

Here is how the Output Current for Boost Regulator (DCM) equation looks like.

1.9899 = \frac{({9.71}^{2}) \cdot {0.0359}^{2} \cdot 4.063}{2 \cdot 0.4191 \cdot (10.006 - 9.71)}

1.9899A = \frac{({9.71V}^{2}) \cdot {0.0359}^{2} \cdot 4.063s}{2 \cdot 0.4191H \cdot (10.006V - 9.71V)}

1.9899 = \frac{({9.71}^{2}) \cdot {0.0359}^{2} \cdot 4.063}{2 \cdot 0.4191 \cdot (10.006 - 9.71)}

Tip: Use pencil ( Pencil

Pencil

) icon above to edit Input Values and Units.

Solution

Copy

Share

You are here -

HomeIcon

Home » Category

Category

Engineering » Category

Category

Electrical » Category

Category

Power Electronics » fx Output Current for Boost Regulator (DCM)

Output Current for Boost Regulator (DCM) Solution

Follow our step by step solution on how to calculate Output Current for Boost Regulator (DCM)?

FIRST Step Consider the formula

i o(bo_dcm) = \frac{({V i(bo_dcm)}^{2}) \cdot {D bo_dcm}^{2} \cdot t c(bo_dcm)}{2 \cdot L x(bo_dcm) \cdot (V o(bo_dcm) - V i(bo_dcm))}

Next Step Substitute values of Variables

∴

i o(bo_dcm) = \frac{({9.71V}^{2}) \cdot {0.0359}^{2} \cdot 4.063s}{2 \cdot 0.4191H \cdot (10.006V - 9.71V)}

Next Step Prepare to Evaluate

∴

i o(bo_dcm) = \frac{({9.71}^{2}) \cdot {0.0359}^{2} \cdot 4.063}{2 \cdot 0.4191 \cdot (10.006 - 9.71)}

Next Step Evaluate

∴

i o(bo_dcm) = 1.98991631041753A

LAST Step Rounding Answer

∴

i o(bo_dcm) = 1.9899A

Output Current for Boost Regulator (DCM) Formula Elements

Variables

Output Current of Boost DCM

Output Current of Boost DCM is the current the amplifier draws from the signal source.

Symbol: i_{o(bo_dcm)}

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Output Current of Boost DCM

Open Variable

Input Voltage of Boost DCM

Input Voltage of Boost DCM is the voltage supplied to the voltage regulator circuit.

Symbol: V_{i(bo_dcm)}

Measurement: Electric PotentialUnit: V

Note: Value should be greater than 0.

Formulas to find Input Voltage of Boost DCM

Open Variable

Duty Cycle of Boost DCM

A Duty Cycle of Boost DCM or power cycle is the fraction of one period in which a signal or system is active in a voltage regulator circuit.

Symbol: D_{bo_dcm}

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Duty Cycle of Boost DCM

Open Variable

Time Commutation of Boost DCM

The Time Commutation of Boost DCM is the process of transferring current from one connection to another within an electric circuit such as voltage regulator circuit.

Symbol: t_{c(bo_dcm)}

Measurement: TimeUnit: s

Note: Value should be greater than 0.

Formulas to find Time Commutation of Boost DCM

Open Variable

Critical Inductance of Boost DCM

Critical Inductance of Boost DCM refers to the minimum value of the inductance required in these converters to maintain discontinuous current flow through the inductor.

Symbol: L_{x(bo_dcm)}

Measurement: InductanceUnit: H

Note: Value should be greater than 0.

Formulas to find Critical Inductance of Boost DCM

Open Variable

Output Voltage of Boost DCM

Output Voltage of Boost DCM signifies the voltage of the signal after it has been regulated by a voltage regulator circuit.

Symbol: V_{o(bo_dcm)}

Measurement: Electric PotentialUnit: V

Note: Value should be greater than 0.

Formulas to find Output Voltage of Boost DCM

Open Variable

Other formulas in Discontinuous Conduction Mode category

Go Duty Cycle for Boost Regulator (DCM)

D bo_dcm = \sqrt{(2 \cdot L x(bo_dcm) \cdot \frac{i o(bo_dcm)}{V i(bo_dcm) \cdot t c(bo_dcm)}) \cdot ((\frac{V o(bo_dcm)}{V i(bo_dcm)}) - 1)}

Go Output Voltage for Boost Regulator (DCM)

V o(bo_dcm) = V i(bo_dcm) + (\frac{{V i(bo_dcm)}^{2} \cdot {D bo_dcm}^{2} \cdot t c(bo_dcm)}{2 \cdot L x(bo_dcm) \cdot i o(bo_dcm)})

Go Commutation Period for Boost Regulator (DCM)

t c(bo_dcm) = (\frac{2 \cdot L x(bo_dcm) \cdot i o(bo_dcm)}{({D bo_dcm}^{2}) \cdot V i(bo_dcm)}) \cdot ((\frac{V o(bo_dcm)}{V i(bo_dcm)}) - 1)

Go Inductor Value for Boost Regulator (DCM)

L x(bo_dcm) = \frac{({V i(bo_dcm)}^{2}) \cdot ({D bo_dcm}^{2}) \cdot t c(bo_dcm)}{2 \cdot (V o(bo_dcm) - V i(bo_dcm)) \cdot i o(bo_dcm)}

How to Evaluate Output Current for Boost Regulator (DCM)?

Output Current for Boost Regulator (DCM) evaluator uses Output Current of Boost DCM = ((Input Voltage of Boost DCM^2)*Duty Cycle of Boost DCM^2*Time Commutation of Boost DCM)/(2*Critical Inductance of Boost DCM*(Output Voltage of Boost DCM-Input Voltage of Boost DCM)) to evaluate the Output Current of Boost DCM, The Output Current for Boost Regulator (DCM) formula is defined as the difference between input and output voltage multiplied by duty cycle, time taken, and with the sum of duty cycle and delta then divided by twice of Inductance. Output Current of Boost DCM is denoted by i_{o(bo_dcm)} symbol.

How to evaluate Output Current for Boost Regulator (DCM) using this online evaluator? To use this online evaluator for Output Current for Boost Regulator (DCM), enter Input Voltage of Boost DCM (V_{i(bo_dcm)}), Duty Cycle of Boost DCM (D_{bo_dcm}), Time Commutation of Boost DCM (t_{c(bo_dcm)}), Critical Inductance of Boost DCM (L_{x(bo_dcm)}) & Output Voltage of Boost DCM (V_{o(bo_dcm)}) and hit the calculate button.

FAQs on Output Current for Boost Regulator (DCM)

What is the formula to find Output Current for Boost Regulator (DCM)?

The formula of Output Current for Boost Regulator (DCM) is expressed as Output Current of Boost DCM = ((Input Voltage of Boost DCM^2)*Duty Cycle of Boost DCM^2*Time Commutation of Boost DCM)/(2*Critical Inductance of Boost DCM*(Output Voltage of Boost DCM-Input Voltage of Boost DCM)). Here is an example- 1.989916 = ((9.71^2)*0.0359^2*4.063)/(2*0.4191*(10.006-9.71)).

How to calculate Output Current for Boost Regulator (DCM)?

With Input Voltage of Boost DCM (V_{i(bo_dcm)}), Duty Cycle of Boost DCM (D_{bo_dcm}), Time Commutation of Boost DCM (t_{c(bo_dcm)}), Critical Inductance of Boost DCM (L_{x(bo_dcm)}) & Output Voltage of Boost DCM (V_{o(bo_dcm)}) we can find Output Current for Boost Regulator (DCM) using the formula - Output Current of Boost DCM = ((Input Voltage of Boost DCM^2)*Duty Cycle of Boost DCM^2*Time Commutation of Boost DCM)/(2*Critical Inductance of Boost DCM*(Output Voltage of Boost DCM-Input Voltage of Boost DCM)).

Can the Output Current for Boost Regulator (DCM) be negative?

Yes, the Output Current for Boost Regulator (DCM), measured in Electric Current can be negative.

Which unit is used to measure Output Current for Boost Regulator (DCM)?

Output Current for Boost Regulator (DCM) is usually measured using the Ampere[A] for Electric Current. Milliampere[A], Microampere[A], Centiampere[A] are the few other units in which Output Current for Boost Regulator (DCM) can be measured.

Let Others Know

✖

WhatsApp

Copied!