FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Osmotic Pressure given Volume and Concentration of Two Substances Formula

GoOsmotic Pressure given Volume and Osmotic Pressure of Two Substances Formula

GoOsmotic Pressure using Number of Moles and Volume of Solution Formula

Fx Copy

LaTeX Copy

The Osmotic Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. Check FAQs

π = \frac{((C 1 \cdot V 1) + (C 2 \cdot V 2)) \cdot ([R] \cdot T)}{V 1 + V 2}

π - Osmotic Pressure?C₁ - Concentration of Particle 1?V₁ - Volume of Particle 1?C₂ - Concentration of Particle 2?V₂ - Volume of Particle 2?T - Temperature?[R] - Universal gas constant?

Osmotic Pressure given Volume and Concentration of Two Substances Example

With values

With units

Only example

Here is how the Osmotic Pressure given Volume and Concentration of Two Substances equation looks like with Values.

Here is how the Osmotic Pressure given Volume and Concentration of Two Substances equation looks like with Units.

Here is how the Osmotic Pressure given Volume and Concentration of Two Substances equation looks like.

2.0313 = \frac{((8.2E-7 \cdot 20) + (1.9E-7 \cdot 0.005)) \cdot (8.3145 \cdot 298)}{20 + 0.005}

2.0313Pa = \frac{((8.2E-7mol/L \cdot 20L) + (1.9E-7mol/L \cdot 0.005L)) \cdot (8.3145 \cdot 298K)}{20L + 0.005L}

2.0313 = \frac{((8.2E-7 \cdot 20) + (1.9E-7 \cdot 0.005)) \cdot (8.3145 \cdot 298)}{20 + 0.005}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Chemistry » Category

Solution and Colligative properties » Category

Osmotic Pressure » fx Osmotic Pressure given Volume and Concentration of Two Substances

Osmotic Pressure given Volume and Concentration of Two Substances Solution

Follow our step by step solution on how to calculate Osmotic Pressure given Volume and Concentration of Two Substances?

FIRST Step Consider the formula

π = \frac{((C 1 \cdot V 1) + (C 2 \cdot V 2)) \cdot ([R] \cdot T)}{V 1 + V 2}

Next Step Substitute values of Variables

∴

π = \frac{((8.2E-7mol/L \cdot 20L) + (1.9E-7mol/L \cdot 0.005L)) \cdot ([R] \cdot 298K)}{20L + 0.005L}

Next Step Substitute values of Constants

∴

π = \frac{((8.2E-7mol/L \cdot 20L) + (1.9E-7mol/L \cdot 0.005L)) \cdot (8.3145 \cdot 298K)}{20L + 0.005L}

Next Step Convert Units

∴

π = \frac{((0.0008mol/m³ \cdot 20L) + (0.0002mol/m³ \cdot 0.005L)) \cdot (8.3145 \cdot 298K)}{20L + 0.005L}

Next Step Prepare to Evaluate

∴

π = \frac{((0.0008 \cdot 20) + (0.0002 \cdot 0.005)) \cdot (8.3145 \cdot 298)}{20 + 0.005}

Next Step Evaluate

∴

π = 2.03133132433174Pa

LAST Step Rounding Answer

∴

π = 2.0313Pa

Osmotic Pressure given Volume and Concentration of Two Substances Formula Elements

Variables

Constants

Osmotic Pressure

The Osmotic Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane.

Symbol: π

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Osmotic Pressure

Concentration of Particle 1

The Concentration of Particle 1 is moles per liter of volume of particle 1 in solution.

Symbol: C₁

Measurement: Molar ConcentrationUnit: mol/L

Note: Value can be positive or negative.

Formulas to find Concentration of Particle 1

Volume of Particle 1

The Volume of particle 1 is the volume of particle 1 in solution.

Symbol: V₁

Measurement: VolumeUnit: L

Note: Value should be greater than 0.

Formulas to find Volume of Particle 1

Concentration of Particle 2

The Concentration of Particle 2 is moles per liter of volume of particle 2 in solution.

Symbol: C₂

Measurement: Molar ConcentrationUnit: mol/L

Note: Value can be positive or negative.

Formulas to find Concentration of Particle 2

Volume of Particle 2

The Volume of Particle 2 is the volume of particle 2 in solution.

Symbol: V₂

Measurement: VolumeUnit: L

Note: Value should be greater than 0.

Formulas to find Volume of Particle 2

Temperature

Temperature is the degree or intensity of heat present in a substance or object.

Symbol: T

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other Formulas to find Osmotic Pressure

Go Osmotic Pressure given Volume and Osmotic Pressure of Two Substances

π = \frac{(π 1 \cdot V 1) + (π 2 \cdot V 2)}{[R] \cdot T}

Go Osmotic Pressure using Number of Moles and Volume of Solution

π = \frac{n \cdot [R] \cdot T}{V}

Go Osmotic Pressure given Concentration of Two Substances

π = (C 1 + C 2) \cdot [R] \cdot T

Go Osmotic Pressure given Density of Solution

π = ρ sol \cdot [g] \cdot h

Other formulas in Osmotic Pressure category

Go Density of Solution given Osmotic Pressure

ρ sol = \frac{π}{[g] \cdot h}

Go Equilibrium Height given Osmotic Pressure

h = \frac{π}{[g] \cdot ρ sol}

Go Moles of Solute given Osmotic Pressure

n = \frac{π \cdot V}{[R] \cdot T}

Go Volume of Solution given Osmotic Pressure

V = \frac{n \cdot [R] \cdot T}{π}

How to Evaluate Osmotic Pressure given Volume and Concentration of Two Substances?

Osmotic Pressure given Volume and Concentration of Two Substances evaluator uses Osmotic Pressure = (((Concentration of Particle 1*Volume of Particle 1)+(Concentration of Particle 2*Volume of Particle 2))*([R]*Temperature))/(Volume of Particle 1+Volume of Particle 2) to evaluate the Osmotic Pressure, The Osmotic Pressure given Volume and Concentration of Two Substances is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. It is also defined as the measure of the tendency of a solution to take in pure solvent by osmosis. Osmotic Pressure is denoted by π symbol.

How to evaluate Osmotic Pressure given Volume and Concentration of Two Substances using this online evaluator? To use this online evaluator for Osmotic Pressure given Volume and Concentration of Two Substances, enter Concentration of Particle 1 (C₁), Volume of Particle 1 (V₁), Concentration of Particle 2 (C₂), Volume of Particle 2 (V₂) & Temperature (T) and hit the calculate button.

FAQs on Osmotic Pressure given Volume and Concentration of Two Substances

What is the formula to find Osmotic Pressure given Volume and Concentration of Two Substances?

The formula of Osmotic Pressure given Volume and Concentration of Two Substances is expressed as Osmotic Pressure = (((Concentration of Particle 1*Volume of Particle 1)+(Concentration of Particle 2*Volume of Particle 2))*([R]*Temperature))/(Volume of Particle 1+Volume of Particle 2). Here is an example- 2.031331 = (((0.00082*0.02)+(0.000189*5E-06))*([R]*298))/(0.02+5E-06).

How to calculate Osmotic Pressure given Volume and Concentration of Two Substances?

With Concentration of Particle 1 (C₁), Volume of Particle 1 (V₁), Concentration of Particle 2 (C₂), Volume of Particle 2 (V₂) & Temperature (T) we can find Osmotic Pressure given Volume and Concentration of Two Substances using the formula - Osmotic Pressure = (((Concentration of Particle 1*Volume of Particle 1)+(Concentration of Particle 2*Volume of Particle 2))*([R]*Temperature))/(Volume of Particle 1+Volume of Particle 2). This formula also uses Universal gas constant .

What are the other ways to Calculate Osmotic Pressure?

Here are the different ways to Calculate Osmotic Pressure-

Osmotic Pressure=((Osmotic Pressure of Particle 1*Volume of Particle 1)+(Osmotic Pressure of Particle 2*Volume of Particle 2))/([R]*Temperature)
Osmotic Pressure=(Number of Moles of Solute*[R]*Temperature)/Volume of Solution
Osmotic Pressure=(Concentration of Particle 1+Concentration of Particle 2)*[R]*Temperature

Can the Osmotic Pressure given Volume and Concentration of Two Substances be negative?

Yes, the Osmotic Pressure given Volume and Concentration of Two Substances, measured in Pressure can be negative.

Which unit is used to measure Osmotic Pressure given Volume and Concentration of Two Substances?

Osmotic Pressure given Volume and Concentration of Two Substances is usually measured using the Pascal[Pa] for Pressure. Kilopascal[Pa], Bar[Pa], Pound Per Square Inch[Pa] are the few other units in which Osmotic Pressure given Volume and Concentration of Two Substances can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Osmotic Pressure given Volume and Concentration of Two Substances Formula

​GoOsmotic Pressure given Volume and Osmotic Pressure of Two Substances Formula

​GoOsmotic Pressure using Number of Moles and Volume of Solution Formula

Osmotic Pressure given Volume and Concentration of Two Substances Example

Osmotic Pressure given Volume and Concentration of Two Substances Solution

Osmotic Pressure given Volume and Concentration of Two Substances Formula Elements

Other Formulas to find Osmotic Pressure

Other formulas in Osmotic Pressure category

How to Evaluate Osmotic Pressure given Volume and Concentration of Two Substances?

FAQs on Osmotic Pressure given Volume and Concentration of Two Substances

Variable Name

GoOsmotic Pressure given Volume and Osmotic Pressure of Two Substances Formula

GoOsmotic Pressure using Number of Moles and Volume of Solution Formula