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The Number of Equilibrium Extraction Stages is the number of Ideal Equilibrium stages required for Liquid-Liquid Extraction. Check FAQs
N=(zC-(ysKSolute)xC-(ysKSolute))-1
N - Number of Equilibrium Extraction Stages?zC - Mass Fraction of Solute in the Feed?ys - Mass Fraction of Solute in the Solvent?KSolute - Distribution Coefficient of Solute?xC - Mass Fraction of Solute in the Raffinate?

Number of Stages for Extraction Factor equal to 1 Example

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Here is how the Number of Stages for Extraction Factor equal to 1 equation looks like with Values.

Here is how the Number of Stages for Extraction Factor equal to 1 equation looks like with Units.

Here is how the Number of Stages for Extraction Factor equal to 1 equation looks like.

3.0008Edit=(0.5Edit-(0.05Edit2.6Edit)0.1394Edit-(0.05Edit2.6Edit))-1
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Number of Stages for Extraction Factor equal to 1 Solution

Follow our step by step solution on how to calculate Number of Stages for Extraction Factor equal to 1?

FIRST Step Consider the formula
N=(zC-(ysKSolute)xC-(ysKSolute))-1
Next Step Substitute values of Variables
N=(0.5-(0.052.6)0.1394-(0.052.6))-1
Next Step Prepare to Evaluate
N=(0.5-(0.052.6)0.1394-(0.052.6))-1
Next Step Evaluate
N=3.00076814748432
LAST Step Rounding Answer
N=3.0008

Number of Stages for Extraction Factor equal to 1 Formula Elements

Variables
Number of Equilibrium Extraction Stages
The Number of Equilibrium Extraction Stages is the number of Ideal Equilibrium stages required for Liquid-Liquid Extraction.
Symbol: N
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Mass Fraction of Solute in the Feed
The Mass Fraction of Solute in the Feed is the mass fraction of the solute in the Feed to the Liquid-Liquid Extraction operation.
Symbol: zC
Measurement: NAUnit: Unitless
Note: Value should be less than 1.
Mass Fraction of Solute in the Solvent
The Mass Fraction of Solute in the Solvent is the mass ratio of the solute in the inlet solvent to the solvent mass in Liquid-Liquid Extraction operation.
Symbol: ys
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Distribution Coefficient of Solute
The distribution coefficient of solute is defined as the concentration of solute in the extract phase divided by the concentration of solute in the raffinate phase.
Symbol: KSolute
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Mass Fraction of Solute in the Raffinate
The Mass Fraction of Solute in the Raffinate Phase is the mass fraction of the solute in the raffinate phase after separation of the ternary mixture.
Symbol: xC
Measurement: NAUnit: Unitless
Note: Value should be less than 1.

Other Formulas to find Number of Equilibrium Extraction Stages

​Go Number of Ideal Equilibrium Extraction Stages
N=log10(zCXN)log10((KSoluteE'F')+1)
​Go Number of Extraction Stages by Kremser Equation
N=log10((zC-(ysKSolute)(xC-ysKSolute))(1-(1ε))+(1ε))log10(ε)

Other formulas in Kremser's Equation for Liquid Liquid Extraction category

​Go Distribution Coefficient of Carrier Liquid from Activity Coefficients
KCarrierLiq=ΥaRΥaE
​Go Distribution Coefficient of Carrier Liquid from Mass Fraction
KCarrierLiq=yAxA
​Go Distribution Coefficient of Solute from Activity Coefficient
KSolute=ΥcRΥcE
​Go Distribution Coefficient of Solute from Mass Fractions
KSolute=yCxC

How to Evaluate Number of Stages for Extraction Factor equal to 1?

Number of Stages for Extraction Factor equal to 1 evaluator uses Number of Equilibrium Extraction Stages = ((Mass Fraction of Solute in the Feed-(Mass Fraction of Solute in the Solvent/Distribution Coefficient of Solute))/(Mass Fraction of Solute in the Raffinate-(Mass Fraction of Solute in the Solvent/Distribution Coefficient of Solute)))-1 to evaluate the Number of Equilibrium Extraction Stages, The Number of Stages for Extraction Factor equal to 1 formula is defined as the calculation for number of stages for extraction operation according to the Kremser Souders Brown equation for extraction factor equal to 1. Number of Equilibrium Extraction Stages is denoted by N symbol.

How to evaluate Number of Stages for Extraction Factor equal to 1 using this online evaluator? To use this online evaluator for Number of Stages for Extraction Factor equal to 1, enter Mass Fraction of Solute in the Feed (zC), Mass Fraction of Solute in the Solvent (ys), Distribution Coefficient of Solute (KSolute) & Mass Fraction of Solute in the Raffinate (xC) and hit the calculate button.

FAQs on Number of Stages for Extraction Factor equal to 1

What is the formula to find Number of Stages for Extraction Factor equal to 1?
The formula of Number of Stages for Extraction Factor equal to 1 is expressed as Number of Equilibrium Extraction Stages = ((Mass Fraction of Solute in the Feed-(Mass Fraction of Solute in the Solvent/Distribution Coefficient of Solute))/(Mass Fraction of Solute in the Raffinate-(Mass Fraction of Solute in the Solvent/Distribution Coefficient of Solute)))-1. Here is an example- 3.000768 = ((0.5-(0.05/2.6))/(0.1394-(0.05/2.6)))-1.
How to calculate Number of Stages for Extraction Factor equal to 1?
With Mass Fraction of Solute in the Feed (zC), Mass Fraction of Solute in the Solvent (ys), Distribution Coefficient of Solute (KSolute) & Mass Fraction of Solute in the Raffinate (xC) we can find Number of Stages for Extraction Factor equal to 1 using the formula - Number of Equilibrium Extraction Stages = ((Mass Fraction of Solute in the Feed-(Mass Fraction of Solute in the Solvent/Distribution Coefficient of Solute))/(Mass Fraction of Solute in the Raffinate-(Mass Fraction of Solute in the Solvent/Distribution Coefficient of Solute)))-1.
What are the other ways to Calculate Number of Equilibrium Extraction Stages?
Here are the different ways to Calculate Number of Equilibrium Extraction Stages-
  • Number of Equilibrium Extraction Stages=(log10(Mass Fraction of Solute in the Feed/N Stages Mass Fraction of Solute in Raffinate))/(log10(((Distribution Coefficient of Solute*Solute Free Extract Phase Flowrate in LLE)/Solute Free Feed Flowrate in Extraction)+1))OpenImg
  • Number of Equilibrium Extraction Stages=(log10(((Mass Fraction of Solute in the Feed-(Mass Fraction of Solute in the Solvent/Distribution Coefficient of Solute))/(((Mass Fraction of Solute in the Raffinate-Mass Fraction of Solute in the Solvent)/Distribution Coefficient of Solute)))*(1-(1/Extraction Factor))+(1/Extraction Factor)))/(log10(Extraction Factor))OpenImg
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