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Number of Relations on Set A which are both Symmetric and Antisymmetric Formula

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No. of Symmetric and Antisymmetric Relations on A is the number of binary relations R on a set A which are both symmetric and antisymmetric. Check FAQs

N Symmetric & Antisymmetric = 2^{n (A)}

N_{Symmetric & Antisymmetric} - No. of Symmetric and Antisymmetric Relations on A?n_(A) - Number of Elements in Set A?

Number of Relations on Set A which are both Symmetric and Antisymmetric Example

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Here is how the Number of Relations on Set A which are both Symmetric and Antisymmetric equation looks like with Values.

Here is how the Number of Relations on Set A which are both Symmetric and Antisymmetric equation looks like with Units.

Here is how the Number of Relations on Set A which are both Symmetric and Antisymmetric equation looks like.

8 = 2^{3}

8 = 2^{3}

8 = 2^{3}

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Number of Relations on Set A which are both Symmetric and Antisymmetric Solution

Follow our step by step solution on how to calculate Number of Relations on Set A which are both Symmetric and Antisymmetric?

FIRST Step Consider the formula

N Symmetric & Antisymmetric = 2^{n (A)}

Next Step Substitute values of Variables

∴

N Symmetric & Antisymmetric = 2^{3}

Next Step Prepare to Evaluate

∴

N Symmetric & Antisymmetric = 2^{3}

LAST Step Evaluate

∴

N Symmetric & Antisymmetric = 8

Number of Relations on Set A which are both Symmetric and Antisymmetric Formula Elements

Variables

No. of Symmetric and Antisymmetric Relations on A

No. of Symmetric and Antisymmetric Relations on A is the number of binary relations R on a set A which are both symmetric and antisymmetric.

Symbol: N_{Symmetric & Antisymmetric}

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find No. of Symmetric and Antisymmetric Relations on A

Number of Elements in Set A

Number of Elements in Set A is the total count of elements present in the given finite set A.

Symbol: n_(A)

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Number of Elements in Set A

Other formulas in Relations category

Go Number of Relations from Set A to Set B

N Relations(A-B) = 2^{n (A) \cdot n (B)}

Go Number of Reflexive Relations on Set A

N Reflexive Relations = 2^{n (A) \cdot (n (A) - 1)}

Go Number of Symmetric Relations on Set A

N Symmetric Relations = 2^{\frac{n (A) \cdot (n (A) + 1)}{2}}

Go Number of Relations on Set A

N Relations(A) = 2^{{n (A)}^{2}}

How to Evaluate Number of Relations on Set A which are both Symmetric and Antisymmetric?

Number of Relations on Set A which are both Symmetric and Antisymmetric evaluator uses No. of Symmetric and Antisymmetric Relations on A = 2^(Number of Elements in Set A) to evaluate the No. of Symmetric and Antisymmetric Relations on A, The Number of Relations on Set A which are both Symmetric and Antisymmetric formula is defined as the number of binary relations R on a set A which are both symmetric and antisymmetric. No. of Symmetric and Antisymmetric Relations on A is denoted by N_{Symmetric & Antisymmetric} symbol.

How to evaluate Number of Relations on Set A which are both Symmetric and Antisymmetric using this online evaluator? To use this online evaluator for Number of Relations on Set A which are both Symmetric and Antisymmetric, enter Number of Elements in Set A (n_(A)) and hit the calculate button.

FAQs on Number of Relations on Set A which are both Symmetric and Antisymmetric

What is the formula to find Number of Relations on Set A which are both Symmetric and Antisymmetric?

The formula of Number of Relations on Set A which are both Symmetric and Antisymmetric is expressed as No. of Symmetric and Antisymmetric Relations on A = 2^(Number of Elements in Set A). Here is an example- 8 = 2^(3).

How to calculate Number of Relations on Set A which are both Symmetric and Antisymmetric?

With Number of Elements in Set A (n_(A)) we can find Number of Relations on Set A which are both Symmetric and Antisymmetric using the formula - No. of Symmetric and Antisymmetric Relations on A = 2^(Number of Elements in Set A).

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