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NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass Formula

GoNTU relation of double pipe parallel flow heat exchanger Formula

GoNTU relation of double pipe counter flow heat exchanger Formula

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The number of transfer units is defined as ratio of overall thermal conductance to smaller heat capacity rate. NTU designates non-dimensional heat transfer size or thermal size of the exchanger. Check FAQs

NTU = - ({(1 + C^{2})}^{- 0.5}) \cdot (\frac{\ln (((\frac{2}{ϵ}) - 1 - C - ({(1 + C^{2})}^{- 0.5})))}{(\frac{2}{ϵ}) - 1 - C + ({(1 + C^{2})}^{- 0.5})})

NTU - Number of Transfer Units?C - Heat capacity ratio?ϵ - Effectiveness of Heat Exchanger?

NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass Example

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Here is how the NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass equation looks like with Values.

Here is how the NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass equation looks like with Units.

Here is how the NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass equation looks like.

-0.1323 = - ({(1 + {0.5}^{2})}^{- 0.5}) \cdot (\frac{\ln (((\frac{2}{0.1}) - 1 - 0.5 - ({(1 + {0.5}^{2})}^{- 0.5})))}{(\frac{2}{0.1}) - 1 - 0.5 + ({(1 + {0.5}^{2})}^{- 0.5})})

-0.1323 = - ({(1 + {0.5}^{2})}^{- 0.5}) \cdot (\frac{\ln (((\frac{2}{0.1}) - 1 - 0.5 - ({(1 + {0.5}^{2})}^{- 0.5})))}{(\frac{2}{0.1}) - 1 - 0.5 + ({(1 + {0.5}^{2})}^{- 0.5})})

-0.1323 = - ({(1 + {0.5}^{2})}^{- 0.5}) \cdot (\frac{\ln (((\frac{2}{0.1}) - 1 - 0.5 - ({(1 + {0.5}^{2})}^{- 0.5})))}{(\frac{2}{0.1}) - 1 - 0.5 + ({(1 + {0.5}^{2})}^{- 0.5})})

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NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass Solution

Follow our step by step solution on how to calculate NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass?

FIRST Step Consider the formula

NTU = - ({(1 + C^{2})}^{- 0.5}) \cdot (\frac{\ln (((\frac{2}{ϵ}) - 1 - C - ({(1 + C^{2})}^{- 0.5})))}{(\frac{2}{ϵ}) - 1 - C + ({(1 + C^{2})}^{- 0.5})})

Next Step Substitute values of Variables

∴

NTU = - ({(1 + {0.5}^{2})}^{- 0.5}) \cdot (\frac{\ln (((\frac{2}{0.1}) - 1 - 0.5 - ({(1 + {0.5}^{2})}^{- 0.5})))}{(\frac{2}{0.1}) - 1 - 0.5 + ({(1 + {0.5}^{2})}^{- 0.5})})

Next Step Prepare to Evaluate

∴

NTU = - ({(1 + {0.5}^{2})}^{- 0.5}) \cdot (\frac{\ln (((\frac{2}{0.1}) - 1 - 0.5 - ({(1 + {0.5}^{2})}^{- 0.5})))}{(\frac{2}{0.1}) - 1 - 0.5 + ({(1 + {0.5}^{2})}^{- 0.5})})

Next Step Evaluate

∴

NTU = -0.132275622144723

LAST Step Rounding Answer

∴

NTU = -0.1323

NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass Formula Elements

Variables

Functions

Number of Transfer Units

The number of transfer units is defined as ratio of overall thermal conductance to smaller heat capacity rate. NTU designates non-dimensional heat transfer size or thermal size of the exchanger.

Symbol: NTU

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Number of Transfer Units

Heat capacity ratio

Heat capacity ratio is the ratio of cmin and cmax.

Symbol: C

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Heat capacity ratio

Effectiveness of Heat Exchanger

The effectiveness of heat exchanger is defined as the ratio of the actual heat transfer to the maximum possible heat transfer.

Symbol: ϵ

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Effectiveness of Heat Exchanger

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

Other Formulas to find Number of Transfer Units

Go NTU relation of double pipe parallel flow heat exchanger

NTU = \frac{- \ln (1 - (1 + C) \cdot ϵ)}{1 + C}

Go NTU relation of double pipe counter flow heat exchanger

NTU = (\frac{1}{C - 1}) \cdot (\ln (\frac{ϵ - 1}{C \cdot ϵ - 1}))

Go NTU relation of double pipe counter flow heat exchanger given C equal to 1

NTU = \frac{ϵ}{1 - ϵ}

Go NTU relation of double pipe counter flow heat exchanger with Cmax mixed and Cmin unmixed

NTU = - \ln (1 + (\frac{1}{C}) \cdot (\ln (1 - C \cdot ϵ)))

How to Evaluate NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass?

NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass evaluator uses Number of Transfer Units = -((1+Heat capacity ratio^2)^-0.5)*(ln(((2/Effectiveness of Heat Exchanger)-1-Heat capacity ratio-((1+Heat capacity ratio^2)^-0.5)))/((2/Effectiveness of Heat Exchanger)-1-Heat capacity ratio+((1+Heat capacity ratio^2)^-0.5))) to evaluate the Number of Transfer Units, The NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass formula is defined as the amount of energy units transferred between the fluids in the heat exchanger. Number of Transfer Units is denoted by NTU symbol.

How to evaluate NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass using this online evaluator? To use this online evaluator for NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass, enter Heat capacity ratio (C) & Effectiveness of Heat Exchanger (ϵ) and hit the calculate button.

FAQs on NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass

What is the formula to find NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass?

The formula of NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass is expressed as Number of Transfer Units = -((1+Heat capacity ratio^2)^-0.5)*(ln(((2/Effectiveness of Heat Exchanger)-1-Heat capacity ratio-((1+Heat capacity ratio^2)^-0.5)))/((2/Effectiveness of Heat Exchanger)-1-Heat capacity ratio+((1+Heat capacity ratio^2)^-0.5))). Here is an example- -0.132276 = -((1+0.5^2)^-0.5)*(ln(((2/0.1)-1-0.5-((1+0.5^2)^-0.5)))/((2/0.1)-1-0.5+((1+0.5^2)^-0.5))).

How to calculate NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass?

With Heat capacity ratio (C) & Effectiveness of Heat Exchanger (ϵ) we can find NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass using the formula - Number of Transfer Units = -((1+Heat capacity ratio^2)^-0.5)*(ln(((2/Effectiveness of Heat Exchanger)-1-Heat capacity ratio-((1+Heat capacity ratio^2)^-0.5)))/((2/Effectiveness of Heat Exchanger)-1-Heat capacity ratio+((1+Heat capacity ratio^2)^-0.5))). This formula also uses Natural Logarithm (ln) function(s).

What are the other ways to Calculate Number of Transfer Units?

Here are the different ways to Calculate Number of Transfer Units-

Number of Transfer Units=(-ln(1-(1+Heat capacity ratio)*Effectiveness of Heat Exchanger))/(1+Heat capacity ratio)
Number of Transfer Units=(1/(Heat capacity ratio-1))*(ln((Effectiveness of Heat Exchanger-1)/(Heat capacity ratio*Effectiveness of Heat Exchanger-1)))
Number of Transfer Units=Effectiveness of Heat Exchanger/(1-Effectiveness of Heat Exchanger)

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NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass Formula

​GoNTU relation of double pipe parallel flow heat exchanger Formula

​GoNTU relation of double pipe counter flow heat exchanger Formula

NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass Example

NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass Solution

NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass Formula Elements

Other Formulas to find Number of Transfer Units

How to Evaluate NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass?

FAQs on NTU relation of heat exchanger with one shell pass and 2, 4, 6 tube pass

Variable Name

GoNTU relation of double pipe parallel flow heat exchanger Formula

GoNTU relation of double pipe counter flow heat exchanger Formula