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Number of Combinations is defined as the total number of unique arrangements that can be made from a set of items, without regard to the order of the items. Check FAQs
C=(p+1)(q+1)(2n)-1
C - Number of Combinations?p - Value of P?q - Value of Q?n - Value of N?

No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once Example

With values
With units
Only example

Here is how the No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once equation looks like with Values.

Here is how the No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once equation looks like with Units.

Here is how the No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once equation looks like.

14335Edit=(7Edit+1)(6Edit+1)(28Edit)-1

No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once Solution

Follow our step by step solution on how to calculate No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once?

FIRST Step Consider the formula
C=(p+1)(q+1)(2n)-1
Next Step Substitute values of Variables
C=(7+1)(6+1)(28)-1
Next Step Prepare to Evaluate
C=(7+1)(6+1)(28)-1
LAST Step Evaluate
C=14335

No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once Formula Elements

Variables
Number of Combinations
Number of Combinations is defined as the total number of unique arrangements that can be made from a set of items, without regard to the order of the items.
Symbol: C
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Value of P
Value of P is any natural number or positive integer that can be used for combinatorial calculations.
Symbol: p
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Value of Q
Value of Q is any natural number or positive integer that can be used for combinatorial calculations.
Symbol: q
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Value of N
Value of N is any natural number or positive integer that can be used for combinatorial calculations.
Symbol: n
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.

Other Formulas to find Number of Combinations

​Go No of Combinations of N Different Things taken R at once
C=C(n,r)
​Go No of Combinations of N Different Things taken R at once and Repetition Allowed
C=C((n+r-1),r)
​Go No of Combinations of N Different Things taken R at once given M Specific Things Always Occur
C=C(n-mr-m)
​Go No of Combinations of N Different Things taken R at once given M Specific Things Never Occur
C=C((n-m),r)

Other formulas in Combinations category

​Go Nth Catalan Number
Cn=(1n+1)C(2n,n)

How to Evaluate No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once?

No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once evaluator uses Number of Combinations = (Value of P+1)*(Value of Q+1)*(2^Value of N)-1 to evaluate the Number of Combinations, The No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once formula is defined as the total number of ways of selecting one or more things out of (p+q+n) things, where ‘p’ identical things of one type ‘q’ identical things of another type and ‘n’ different things. Number of Combinations is denoted by C symbol.

How to evaluate No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once using this online evaluator? To use this online evaluator for No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once, enter Value of P (p), Value of Q (q) & Value of N (n) and hit the calculate button.

FAQs on No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once

What is the formula to find No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once?
The formula of No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once is expressed as Number of Combinations = (Value of P+1)*(Value of Q+1)*(2^Value of N)-1. Here is an example- 7167 = (7+1)*(6+1)*(2^8)-1.
How to calculate No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once?
With Value of P (p), Value of Q (q) & Value of N (n) we can find No of Combinations of N Different Things, P and Q Identical Things taken Atleast One at once using the formula - Number of Combinations = (Value of P+1)*(Value of Q+1)*(2^Value of N)-1.
What are the other ways to Calculate Number of Combinations?
Here are the different ways to Calculate Number of Combinations-
  • Number of Combinations=C(Value of N,Value of R)OpenImg
  • Number of Combinations=C((Value of N+Value of R-1),Value of R)OpenImg
  • Number of Combinations=C((Value of N-Value of M),(Value of R-Value of M))OpenImg
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