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Number of Combinations is defined as the total number of unique arrangements that can be made from a set of items, without regard to the order of the items. Check FAQs
C=(p+q)!(p!)(q!)
C - Number of Combinations?p - Value of P?q - Value of Q?

No of Combinations of (P+Q) Things into Two Groups of P and Q Things Example

With values
With units
Only example

Here is how the No of Combinations of (P+Q) Things into Two Groups of P and Q Things equation looks like with Values.

Here is how the No of Combinations of (P+Q) Things into Two Groups of P and Q Things equation looks like with Units.

Here is how the No of Combinations of (P+Q) Things into Two Groups of P and Q Things equation looks like.

1716Edit=(7Edit+6Edit)!(7Edit!)(6Edit!)
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No of Combinations of (P+Q) Things into Two Groups of P and Q Things Solution

Follow our step by step solution on how to calculate No of Combinations of (P+Q) Things into Two Groups of P and Q Things?

FIRST Step Consider the formula
C=(p+q)!(p!)(q!)
Next Step Substitute values of Variables
C=(7+6)!(7!)(6!)
Next Step Prepare to Evaluate
C=(7+6)!(7!)(6!)
LAST Step Evaluate
C=1716

No of Combinations of (P+Q) Things into Two Groups of P and Q Things Formula Elements

Variables
Number of Combinations
Number of Combinations is defined as the total number of unique arrangements that can be made from a set of items, without regard to the order of the items.
Symbol: C
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Value of P
Value of P is any natural number or positive integer that can be used for combinatorial calculations.
Symbol: p
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Value of Q
Value of Q is any natural number or positive integer that can be used for combinatorial calculations.
Symbol: q
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.

Other Formulas to find Number of Combinations

​Go No of Combinations of N Different Things taken R at once
C=C(n,r)
​Go No of Combinations of N Different Things taken R at once and Repetition Allowed
C=C((n+r-1),r)
​Go No of Combinations of N Different Things taken R at once given M Specific Things Always Occur
C=C(n-mr-m)
​Go No of Combinations of N Different Things taken R at once given M Specific Things Never Occur
C=C((n-m),r)

Other formulas in Combinations category

​Go Nth Catalan Number
Cn=(1n+1)C(2n,n)

How to Evaluate No of Combinations of (P+Q) Things into Two Groups of P and Q Things?

No of Combinations of (P+Q) Things into Two Groups of P and Q Things evaluator uses Number of Combinations = ((Value of P+Value of Q)!)/((Value of P!)*(Value of Q!)) to evaluate the Number of Combinations, The No of Combinations of (P+Q) Things into Two Groups of P and Q Things formula is defined as the total number of ways in which (p + q) things can be divided into two groups of p and q things, where p and q are distinct natural numbers. Number of Combinations is denoted by C symbol.

How to evaluate No of Combinations of (P+Q) Things into Two Groups of P and Q Things using this online evaluator? To use this online evaluator for No of Combinations of (P+Q) Things into Two Groups of P and Q Things, enter Value of P (p) & Value of Q (q) and hit the calculate button.

FAQs on No of Combinations of (P+Q) Things into Two Groups of P and Q Things

What is the formula to find No of Combinations of (P+Q) Things into Two Groups of P and Q Things?
The formula of No of Combinations of (P+Q) Things into Two Groups of P and Q Things is expressed as Number of Combinations = ((Value of P+Value of Q)!)/((Value of P!)*(Value of Q!)). Here is an example- 792 = ((7+6)!)/((7!)*(6!)).
How to calculate No of Combinations of (P+Q) Things into Two Groups of P and Q Things?
With Value of P (p) & Value of Q (q) we can find No of Combinations of (P+Q) Things into Two Groups of P and Q Things using the formula - Number of Combinations = ((Value of P+Value of Q)!)/((Value of P!)*(Value of Q!)).
What are the other ways to Calculate Number of Combinations?
Here are the different ways to Calculate Number of Combinations-
  • Number of Combinations=C(Value of N,Value of R)OpenImg
  • Number of Combinations=C((Value of N+Value of R-1),Value of R)OpenImg
  • Number of Combinations=C((Value of N-Value of M),(Value of R-Value of M))OpenImg
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