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Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids Formula

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The Molecular Mass of Liquid A in a mixture of immiscible liquids. Check FAQs

M A = \frac{W A \cdot M B \cdot P B °}{P A ° \cdot W B}

M_A - Molecular Mass of Liquid A?W_A - Weight of Liquid A?M_B - Molecular Mass of Liquid B?P_B° - Vapor Pressure of Pure Component B?P_A° - Vapor Pressure of Pure Component A?W_B - Weight of Liquid B?

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids Example

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Here is how the Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids equation looks like with Values.

Here is how the Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids equation looks like with Units.

Here is how the Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids equation looks like.

14.7222 = \frac{0.5 \cdot 31.8 \cdot 0.25}{2.7 \cdot 0.1}

14.7222g = \frac{0.5g \cdot 31.8g \cdot 0.25Pa}{2.7Pa \cdot 0.1g}

14.7222 = \frac{0.5 \cdot 31.8 \cdot 0.25}{2.7 \cdot 0.1}

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Immiscible Liquids » fx Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids Solution

Follow our step by step solution on how to calculate Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids?

FIRST Step Consider the formula

M A = \frac{W A \cdot M B \cdot P B °}{P A ° \cdot W B}

Next Step Substitute values of Variables

∴

M A = \frac{0.5g \cdot 31.8g \cdot 0.25Pa}{2.7Pa \cdot 0.1g}

Next Step Convert Units

∴

M A = \frac{0.0005kg \cdot 0.0318kg \cdot 0.25Pa}{2.7Pa \cdot 0.0001kg}

Next Step Prepare to Evaluate

∴

M A = \frac{0.0005 \cdot 0.0318 \cdot 0.25}{2.7 \cdot 0.0001}

Next Step Evaluate

∴

M A = 0.0147222222222222kg

Next Step Convert to Output's Unit

∴

M A = 14.7222222222222g

LAST Step Rounding Answer

∴

M A = 14.7222g

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids Formula Elements

Variables

Molecular Mass of Liquid A

The Molecular Mass of Liquid A in a mixture of immiscible liquids.

Symbol: M_A

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Molecular Mass of Liquid A

Weight of Liquid A

The Weight of Liquid A in a mixture of immiscible liquids.

Symbol: W_A

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Weight of Liquid A

Molecular Mass of Liquid B

The Molecular Mass of Liquid B in a mixture of immiscible liquids.

Symbol: M_B

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Molecular Mass of Liquid B

Vapor Pressure of Pure Component B

Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.

Symbol: P_B°

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Vapor Pressure of Pure Component B

Vapor Pressure of Pure Component A

Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.

Symbol: P_A°

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Vapor Pressure of Pure Component A

Weight of Liquid B

The Weight of Liquid B in a mixture of immiscible liquids.

Symbol: W_B

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Weight of Liquid B

Other formulas in Immiscible Liquids category

Go Total Pressure of Mixture of Two Immiscible Liquids

P = P A ° + P B °

Go Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid

P A ° = \frac{W A \cdot M B \cdot P B °}{M A \cdot W B}

Go Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass

P A:B = \frac{W A \cdot M B}{W B \cdot M A}

Go Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles

P A:B = \frac{n A}{n B}

How to Evaluate Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids?

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids evaluator uses Molecular Mass of Liquid A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Vapor Pressure of Pure Component A*Weight of Liquid B) to evaluate the Molecular Mass of Liquid A, The Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids considering A as unknown parameter and B as known parameter. Molecular Mass of Liquid A is denoted by M_A symbol.

How to evaluate Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids using this online evaluator? To use this online evaluator for Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids, enter Weight of Liquid A (W_A), Molecular Mass of Liquid B (M_B), Vapor Pressure of Pure Component B (P_B°), Vapor Pressure of Pure Component A (P_A°) & Weight of Liquid B (W_B) and hit the calculate button.

FAQs on Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids

What is the formula to find Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids?

The formula of Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids is expressed as Molecular Mass of Liquid A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Vapor Pressure of Pure Component A*Weight of Liquid B). Here is an example- 14.72222 = (0.0005*0.0318*0.25)/(2.7*0.0001).

How to calculate Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids?

With Weight of Liquid A (W_A), Molecular Mass of Liquid B (M_B), Vapor Pressure of Pure Component B (P_B°), Vapor Pressure of Pure Component A (P_A°) & Weight of Liquid B (W_B) we can find Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids using the formula - Molecular Mass of Liquid A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Vapor Pressure of Pure Component A*Weight of Liquid B).

Can the Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids be negative?

No, the Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids, measured in Weight cannot be negative.

Which unit is used to measure Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids?

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids is usually measured using the Gram[g] for Weight. Kilogram[g], Milligram[g], Ton (Metric)[g] are the few other units in which Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids can be measured.

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Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids Formula

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids Example

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids Solution

Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids Formula Elements

Other formulas in Immiscible Liquids category

How to Evaluate Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids?

FAQs on Molecular Mass of Liquid in Mixture of Two Immiscible Liquids given Weight of Liquids

Variable Name