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Molar Mass of First Gas by Graham's law Formula

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The Molar Mass of First Gas is defined as the mass of the gas per mole. Check FAQs

M 1 = \frac{M 2}{{(\frac{r 1}{r 2})}^{2}}

M₁ - Molar Mass of First Gas?M₂ - Molar Mass of Second Gas?r₁ - Rate of Effusion of First Gas?r₂ - Rate of Effusion of Second Gas?

Molar Mass of First Gas by Graham's law Example

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Here is how the Molar Mass of First Gas by Graham's law equation looks like with Values.

Here is how the Molar Mass of First Gas by Graham's law equation looks like with Units.

Here is how the Molar Mass of First Gas by Graham's law equation looks like.

0.0648 = \frac{20.21}{{(\frac{2.12}{0.12})}^{2}}

0.0648g/mol = \frac{20.21g/mol}{{(\frac{2.12m³/s}{0.12m³/s})}^{2}}

0.0648 = \frac{20.21}{{(\frac{2.12}{0.12})}^{2}}

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Molar Mass of First Gas by Graham's law Solution

Follow our step by step solution on how to calculate Molar Mass of First Gas by Graham's law?

FIRST Step Consider the formula

M 1 = \frac{M 2}{{(\frac{r 1}{r 2})}^{2}}

Next Step Substitute values of Variables

∴

M 1 = \frac{20.21g/mol}{{(\frac{2.12m³/s}{0.12m³/s})}^{2}}

Next Step Convert Units

∴

M 1 = \frac{0.0202kg/mol}{{(\frac{2.12m³/s}{0.12m³/s})}^{2}}

Next Step Prepare to Evaluate

∴

M 1 = \frac{0.0202}{{(\frac{2.12}{0.12})}^{2}}

Next Step Evaluate

∴

M 1 = 6.4752580989676E-05kg/mol

Next Step Convert to Output's Unit

∴

M 1 = 0.064752580989676g/mol

LAST Step Rounding Answer

∴

M 1 = 0.0648g/mol

Molar Mass of First Gas by Graham's law Formula Elements

Variables

Molar Mass of First Gas

The Molar Mass of First Gas is defined as the mass of the gas per mole.

Symbol: M₁

Measurement: Molar MassUnit: g/mol

Note: Value can be positive or negative.

Formulas to find Molar Mass of First Gas

Molar Mass of Second Gas

The Molar Mass of Second Gas is defined as the mass of the gas per mole.

Symbol: M₂

Measurement: Molar MassUnit: g/mol

Note: Value can be positive or negative.

Formulas to find Molar Mass of Second Gas

Rate of Effusion of First Gas

The Rate of Effusion of First Gas is the special case of diffusion when the first gas is allowed to escape through the small hole.

Symbol: r₁

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value can be positive or negative.

Formulas to find Rate of Effusion of First Gas

Rate of Effusion of Second Gas

The Rate of Effusion of Second Gas is the special case of diffusion when the second gas is allowed to escape through the small hole.

Symbol: r₂

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value can be positive or negative.

Formulas to find Rate of Effusion of Second Gas

Other formulas in Graham's Law category

Go Rate of Effusion for First Gas by Graham's law

r 1 = (\sqrt{\frac{M 2}{M 1}}) \cdot r 2

Go Rate of Effusion for Second Gas by Graham's law

r 2 = \frac{r 1}{\sqrt{\frac{M 2}{M 1}}}

Go Molar Mass of Second Gas by Graham's law

M 2 = ({(\frac{r 1}{r 2})}^{2}) \cdot M 1

Go Rate of Effusion for First Gas given Densities by Graham's law

r 1 = (\sqrt{\frac{d 2}{d 1}}) \cdot r 2

How to Evaluate Molar Mass of First Gas by Graham's law?

Molar Mass of First Gas by Graham's law evaluator uses Molar Mass of First Gas = Molar Mass of Second Gas/((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2) to evaluate the Molar Mass of First Gas, The Molar mass of first gas by Graham's law formula is defined as rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight. Molar Mass of First Gas is denoted by M₁ symbol.

How to evaluate Molar Mass of First Gas by Graham's law using this online evaluator? To use this online evaluator for Molar Mass of First Gas by Graham's law, enter Molar Mass of Second Gas (M₂), Rate of Effusion of First Gas (r₁) & Rate of Effusion of Second Gas (r₂) and hit the calculate button.

FAQs on Molar Mass of First Gas by Graham's law

What is the formula to find Molar Mass of First Gas by Graham's law?

The formula of Molar Mass of First Gas by Graham's law is expressed as Molar Mass of First Gas = Molar Mass of Second Gas/((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2). Here is an example- 64.75258 = 0.02021/((2.12/0.12)^2).

How to calculate Molar Mass of First Gas by Graham's law?

With Molar Mass of Second Gas (M₂), Rate of Effusion of First Gas (r₁) & Rate of Effusion of Second Gas (r₂) we can find Molar Mass of First Gas by Graham's law using the formula - Molar Mass of First Gas = Molar Mass of Second Gas/((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2).

Can the Molar Mass of First Gas by Graham's law be negative?

Yes, the Molar Mass of First Gas by Graham's law, measured in Molar Mass can be negative.

Which unit is used to measure Molar Mass of First Gas by Graham's law?

Molar Mass of First Gas by Graham's law is usually measured using the Gram Per Mole[g/mol] for Molar Mass. Kilogram Per Mole[g/mol], Chlorine Molecule (Cl2) Molecular Mass[g/mol], Hydrogen (H) - Standard Atomic Weight[g/mol] are the few other units in which Molar Mass of First Gas by Graham's law can be measured.

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Molar Mass of First Gas by Graham's law Formula

Molar Mass of First Gas by Graham's law Example

Molar Mass of First Gas by Graham's law Solution

Molar Mass of First Gas by Graham's law Formula Elements

Other formulas in Graham's Law category

How to Evaluate Molar Mass of First Gas by Graham's law?

FAQs on Molar Mass of First Gas by Graham's law

Variable Name