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Molality using Relative Lowering of Vapour Pressure Formula

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Molality is defined as the total number of moles of solute per kilograms of solvent present in the solution. Check FAQs

m = \frac{(p o - p) \cdot 1000}{M \cdot p o}

m - Molality?p_o - Vapour Pressure of Pure Solvent?p - Vapour Pressure of Solvent in Solution?M - Molecular Mass Solvent?

Molality using Relative Lowering of Vapour Pressure Example

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Here is how the Molality using Relative Lowering of Vapour Pressure equation looks like with Values.

Here is how the Molality using Relative Lowering of Vapour Pressure equation looks like with Units.

Here is how the Molality using Relative Lowering of Vapour Pressure equation looks like.

2892.7778 = \frac{(2000 - 1895.86) \cdot 1000}{18 \cdot 2000}

2892.7778mol/kg = \frac{(2000Pa - 1895.86Pa) \cdot 1000}{18g \cdot 2000Pa}

2892.7778 = \frac{(2000 - 1895.86) \cdot 1000}{18 \cdot 2000}

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Molality using Relative Lowering of Vapour Pressure Solution

Follow our step by step solution on how to calculate Molality using Relative Lowering of Vapour Pressure?

FIRST Step Consider the formula

m = \frac{(p o - p) \cdot 1000}{M \cdot p o}

Next Step Substitute values of Variables

∴

m = \frac{(2000Pa - 1895.86Pa) \cdot 1000}{18g \cdot 2000Pa}

Next Step Convert Units

∴

m = \frac{(2000Pa - 1895.86Pa) \cdot 1000}{0.018kg \cdot 2000Pa}

Next Step Prepare to Evaluate

∴

m = \frac{(2000 - 1895.86) \cdot 1000}{0.018 \cdot 2000}

Next Step Evaluate

∴

m = 2892.77777777778mol/kg

LAST Step Rounding Answer

∴

m = 2892.7778mol/kg

Molality using Relative Lowering of Vapour Pressure Formula Elements

Variables

Molality

Molality is defined as the total number of moles of solute per kilograms of solvent present in the solution.

Symbol: m

Measurement: MolalityUnit: mol/kg

Note: Value can be positive or negative.

Formulas to find Molality

Vapour Pressure of Pure Solvent

The Vapour Pressure of Pure Solvent is the vapour pressure of solvent prior to addition of solute.

Symbol: p_o

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Vapour Pressure of Pure Solvent

Vapour Pressure of Solvent in Solution

The Vapour Pressure of Solvent in Solution is the vapour pressure of solvent post addition of solute.

Symbol: p

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Vapour Pressure of Solvent in Solution

Molecular Mass Solvent

The Molecular Mass Solvent is sum of the atomic masses of all atoms in a molecule, based on a scale in which the atomic masses.

Symbol: M

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Molecular Mass Solvent

Other formulas in Relative Lowering of Vapour Pressure category

Go Relative Lowering of Vapour Pressure

Δp = \frac{p o - p}{p o}

Go Mole Fraction of Solute given Vapour Pressure

x solute = \frac{p o - p}{p o}

Go Mole Fraction of Solvent given Vapour Pressure

x 2 = \frac{p}{p o}

Go Molecular Mass of Solvent given Relative Lowering of Vapour Pressure

M = \frac{(p o - p) \cdot 1000}{m \cdot p o}

How to Evaluate Molality using Relative Lowering of Vapour Pressure?

Molality using Relative Lowering of Vapour Pressure evaluator uses Molality = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molecular Mass Solvent*Vapour Pressure of Pure Solvent) to evaluate the Molality, The Molality using Relative Lowering of Vapour Pressure is a property of a solution and is defined as the number of moles of solute per kilogram of solvent. Molality is denoted by m symbol.

How to evaluate Molality using Relative Lowering of Vapour Pressure using this online evaluator? To use this online evaluator for Molality using Relative Lowering of Vapour Pressure, enter Vapour Pressure of Pure Solvent (p_o), Vapour Pressure of Solvent in Solution (p) & Molecular Mass Solvent (M) and hit the calculate button.

FAQs on Molality using Relative Lowering of Vapour Pressure

What is the formula to find Molality using Relative Lowering of Vapour Pressure?

The formula of Molality using Relative Lowering of Vapour Pressure is expressed as Molality = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molecular Mass Solvent*Vapour Pressure of Pure Solvent). Here is an example- 2892.778 = ((2000-1895.86)*1000)/(0.018*2000).

How to calculate Molality using Relative Lowering of Vapour Pressure?

With Vapour Pressure of Pure Solvent (p_o), Vapour Pressure of Solvent in Solution (p) & Molecular Mass Solvent (M) we can find Molality using Relative Lowering of Vapour Pressure using the formula - Molality = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molecular Mass Solvent*Vapour Pressure of Pure Solvent).

Can the Molality using Relative Lowering of Vapour Pressure be negative?

Yes, the Molality using Relative Lowering of Vapour Pressure, measured in Molality can be negative.

Which unit is used to measure Molality using Relative Lowering of Vapour Pressure?

Molality using Relative Lowering of Vapour Pressure is usually measured using the Mole per Kilogram[mol/kg] for Molality. Millimole per Kilogram[mol/kg] are the few other units in which Molality using Relative Lowering of Vapour Pressure can be measured.

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Molality using Relative Lowering of Vapour Pressure Formula

Molality using Relative Lowering of Vapour Pressure Example

Molality using Relative Lowering of Vapour Pressure Solution

Molality using Relative Lowering of Vapour Pressure Formula Elements

Other formulas in Relative Lowering of Vapour Pressure category

How to Evaluate Molality using Relative Lowering of Vapour Pressure?

FAQs on Molality using Relative Lowering of Vapour Pressure

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