FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Mechanical efficiency given Specific Weight of Liquid Formula

Fx Copy

LaTeX Copy

Mechanical efficiency of centrifugal pump is the ratio of the power delivered by the impeller to the liquid to the power input to the pump shaft. Check FAQs

η cp = \frac{w \cdot (Q + q) \cdot (V w2 \cdot \frac{u 2}{[g]})}{P in}

η_cp - Mechanical Efficiency of Centrifugal Pump?w - Specific Weight of Fluid in Pump?Q - Actual Discharge at Centrifugal Pump Outlet?q - Leakage of Liquid from Impeller?V_w2 - Velocity of Whirl at Outlet?u₂ - Tangential Velocity of Impeller at Outlet?P_in - Input Power to Centrifugal Pump?[g] - Gravitational acceleration on Earth?

Mechanical efficiency given Specific Weight of Liquid Example

With values

With units

Only example

Here is how the Mechanical efficiency given Specific Weight of Liquid equation looks like with Values.

Here is how the Mechanical efficiency given Specific Weight of Liquid equation looks like with Units.

Here is how the Mechanical efficiency given Specific Weight of Liquid equation looks like.

0.5686 = \frac{9.81 \cdot (0.056 + 0.0029) \cdot (16 \cdot \frac{19}{9.8066})}{31.5}

0.5686 = \frac{9.81kN/m³ \cdot (0.056m³/s + 0.0029m³/s) \cdot (16m/s \cdot \frac{19m/s}{9.8066m/s²})}{31.5kW}

0.5686 = \frac{9.81 \cdot (0.056 + 0.0029) \cdot (16 \cdot \frac{19}{9.8066})}{31.5}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Physics » Category

Mechanical » Category

Fluid Mechanics » fx Mechanical efficiency given Specific Weight of Liquid

Mechanical efficiency given Specific Weight of Liquid Solution

Follow our step by step solution on how to calculate Mechanical efficiency given Specific Weight of Liquid?

FIRST Step Consider the formula

η cp = \frac{w \cdot (Q + q) \cdot (V w2 \cdot \frac{u 2}{[g]})}{P in}

Next Step Substitute values of Variables

∴

η cp = \frac{9.81kN/m³ \cdot (0.056m³/s + 0.0029m³/s) \cdot (16m/s \cdot \frac{19m/s}{[g]})}{31.5kW}

Next Step Substitute values of Constants

∴

η cp = \frac{9.81kN/m³ \cdot (0.056m³/s + 0.0029m³/s) \cdot (16m/s \cdot \frac{19m/s}{9.8066m/s²})}{31.5kW}

Next Step Convert Units

∴

η cp = \frac{9810N/m³ \cdot (0.056m³/s + 0.0029m³/s) \cdot (16m/s \cdot \frac{19m/s}{9.8066m/s²})}{31500W}

Next Step Prepare to Evaluate

∴

η cp = \frac{9810 \cdot (0.056 + 0.0029) \cdot (16 \cdot \frac{19}{9.8066})}{31500}

Next Step Evaluate

∴

η cp = 0.568625925119325

LAST Step Rounding Answer

∴

η cp = 0.5686

Mechanical efficiency given Specific Weight of Liquid Formula Elements

Variables

Constants

Mechanical Efficiency of Centrifugal Pump

Mechanical efficiency of centrifugal pump is the ratio of the power delivered by the impeller to the liquid to the power input to the pump shaft.

Symbol: η_cp

Measurement: NAUnit: Unitless

Note: Value should be less than 1.

Formulas to find Mechanical Efficiency of Centrifugal Pump

Specific Weight of Fluid in Pump

Specific weight of fluid in pump is the weight of fluid per unit volume.

Symbol: w

Measurement: Specific WeightUnit: kN/m³