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Maximum Voltage using Load Current (1-Phase 2-Wire US) Formula

GoMaximum Voltage using Area of X-Section (1-Phase 2-Wire US) Formula

GoMaximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US) Formula

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Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire. Check FAQs

V m = (\sqrt{2}) \cdot \frac{P}{I \cdot (\cos (Φ))}

V_m - Maximum Voltage Underground AC?P - Power Transmitted?I - Current Underground AC?Φ - Phase Difference?

Maximum Voltage using Load Current (1-Phase 2-Wire US) Example

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Here is how the Maximum Voltage using Load Current (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Maximum Voltage using Load Current (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Maximum Voltage using Load Current (1-Phase 2-Wire US) equation looks like.

54.4331 = (\sqrt{2}) \cdot \frac{300}{9 \cdot (\cos (30))}

54.4331V = (\sqrt{2}) \cdot \frac{300W}{9A \cdot (\cos (30°))}

54.4331 = (\sqrt{2}) \cdot \frac{300}{9 \cdot (\cos (30))}

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Maximum Voltage using Load Current (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Maximum Voltage using Load Current (1-Phase 2-Wire US)?

FIRST Step Consider the formula

V m = (\sqrt{2}) \cdot \frac{P}{I \cdot (\cos (Φ))}

Next Step Substitute values of Variables

∴

V m = (\sqrt{2}) \cdot \frac{300W}{9A \cdot (\cos (30°))}

Next Step Convert Units

∴

V m = (\sqrt{2}) \cdot \frac{300W}{9A \cdot (\cos (0.5236rad))}

Next Step Prepare to Evaluate

∴

V m = (\sqrt{2}) \cdot \frac{300}{9 \cdot (\cos (0.5236))}

Next Step Evaluate

∴

V m = 54.4331053951817V

LAST Step Rounding Answer

∴

V m = 54.4331V

Maximum Voltage using Load Current (1-Phase 2-Wire US) Formula Elements

Variables

Functions

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Current Underground AC

Current Underground AC is defined as the current flowing through the overhead ac supply wire.

Symbol: I

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Current Underground AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Maximum Voltage Underground AC

Go Maximum Voltage using Area of X-Section (1-Phase 2-Wire US)

V m = \sqrt{\frac{4 \cdot L \cdot ρ \cdot (P^{2})}{A \cdot P loss \cdot {(\cos (Φ))}^{2}}}

Go Maximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US)

V m = \sqrt{8 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot V \cdot {(\cos (Φ))}^{2}}}

Go Maximum Voltage using Line Losses (1-Phase 2-Wire US)

V m = 2 \cdot P \cdot \frac{\sqrt{ρ \cdot \frac{L}{A \cdot P loss}}}{\cos (Φ)}

Go Maximum Voltage using Resistance (1-Phase 2-Wire US)

V m = 2 \cdot P \cdot \frac{\sqrt{\frac{R}{P loss}}}{\cos (Φ)}

Other formulas in Current and Voltage category

Go RMS Voltage(1-Phase 2-Wire US)

V rms = \frac{V m}{\sqrt{2}}

Go Load Current (1-Phase 2-Wire US)

I = P \cdot \frac{\sqrt{2}}{V m \cdot \cos (Φ)}

Go RMS Voltage using Area of X-Section (1-Phase 2-Wire US)

V rms = \sqrt{\frac{2 \cdot L \cdot ρ \cdot (P^{2})}{A \cdot P loss \cdot ({(\cos (Φ))}^{2})}}

Go RMS Voltage using Volume of Conductor Material (1-Phase 2-Wire US)

V rms = \sqrt{4 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot {(\cos (Φ))}^{2} \cdot V}}

How to Evaluate Maximum Voltage using Load Current (1-Phase 2-Wire US)?

Maximum Voltage using Load Current (1-Phase 2-Wire US) evaluator uses Maximum Voltage Underground AC = (sqrt(2))*Power Transmitted/(Current Underground AC*(cos(Phase Difference))) to evaluate the Maximum Voltage Underground AC, The Maximum Voltage using Load Current (1-Phase 2-Wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition. Maximum Voltage Underground AC is denoted by V_m symbol.

How to evaluate Maximum Voltage using Load Current (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Maximum Voltage using Load Current (1-Phase 2-Wire US), enter Power Transmitted (P), Current Underground AC (I) & Phase Difference (Φ) and hit the calculate button.

FAQs on Maximum Voltage using Load Current (1-Phase 2-Wire US)

What is the formula to find Maximum Voltage using Load Current (1-Phase 2-Wire US)?

The formula of Maximum Voltage using Load Current (1-Phase 2-Wire US) is expressed as Maximum Voltage Underground AC = (sqrt(2))*Power Transmitted/(Current Underground AC*(cos(Phase Difference))). Here is an example- 54.43311 = (sqrt(2))*300/(9*(cos(0.5235987755982))).

How to calculate Maximum Voltage using Load Current (1-Phase 2-Wire US)?

With Power Transmitted (P), Current Underground AC (I) & Phase Difference (Φ) we can find Maximum Voltage using Load Current (1-Phase 2-Wire US) using the formula - Maximum Voltage Underground AC = (sqrt(2))*Power Transmitted/(Current Underground AC*(cos(Phase Difference))). This formula also uses Cosine (cos), Square Root (sqrt) function(s).

What are the other ways to Calculate Maximum Voltage Underground AC?

Here are the different ways to Calculate Maximum Voltage Underground AC-

Maximum Voltage Underground AC=sqrt((4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*Line Losses*(cos(Phase Difference))^2))
Maximum Voltage Underground AC=sqrt(8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*Volume Of Conductor*(cos(Phase Difference))^2))
Maximum Voltage Underground AC=2*Power Transmitted*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference)

Can the Maximum Voltage using Load Current (1-Phase 2-Wire US) be negative?

Yes, the Maximum Voltage using Load Current (1-Phase 2-Wire US), measured in Electric Potential can be negative.

Which unit is used to measure Maximum Voltage using Load Current (1-Phase 2-Wire US)?

Maximum Voltage using Load Current (1-Phase 2-Wire US) is usually measured using the Volt[V] for Electric Potential. Millivolt[V], Microvolt[V], Nanovolt[V] are the few other units in which Maximum Voltage using Load Current (1-Phase 2-Wire US) can be measured.

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Maximum Voltage using Load Current (1-Phase 2-Wire US) Formula

​GoMaximum Voltage using Area of X-Section (1-Phase 2-Wire US) Formula

​GoMaximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US) Formula

Maximum Voltage using Load Current (1-Phase 2-Wire US) Example

Maximum Voltage using Load Current (1-Phase 2-Wire US) Solution

Maximum Voltage using Load Current (1-Phase 2-Wire US) Formula Elements

Other Formulas to find Maximum Voltage Underground AC

Other formulas in Current and Voltage category

How to Evaluate Maximum Voltage using Load Current (1-Phase 2-Wire US)?

FAQs on Maximum Voltage using Load Current (1-Phase 2-Wire US)

Variable Name

GoMaximum Voltage using Area of X-Section (1-Phase 2-Wire US) Formula

GoMaximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US) Formula