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Maximum Voltage using Line Losses (1-Phase 2-Wire US) Formula

GoMaximum Voltage using Area of X-Section (1-Phase 2-Wire US) Formula

GoMaximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US) Formula

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Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire. Check FAQs

V m = 2 \cdot P \cdot \frac{\sqrt{ρ \cdot \frac{L}{A \cdot P loss}}}{\cos (Φ)}

V_m - Maximum Voltage Underground AC?P - Power Transmitted?ρ - Resistivity?L - Length of Underground AC Wire?A - Area of Underground AC Wire?P_loss - Line Losses?Φ - Phase Difference?

Maximum Voltage using Line Losses (1-Phase 2-Wire US) Example

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Here is how the Maximum Voltage using Line Losses (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Maximum Voltage using Line Losses (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Maximum Voltage using Line Losses (1-Phase 2-Wire US) equation looks like.

7.5699 = 2 \cdot 300 \cdot \frac{\sqrt{1.7E-5 \cdot \frac{24}{1.28 \cdot 2.67}}}{\cos (30)}

7.5699V = 2 \cdot 300W \cdot \frac{\sqrt{1.7E-5Ω*m \cdot \frac{24m}{1.28m² \cdot 2.67W}}}{\cos (30°)}

7.5699 = 2 \cdot 300 \cdot \frac{\sqrt{1.7E-5 \cdot \frac{24}{1.28 \cdot 2.67}}}{\cos (30)}

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Power System » fx Maximum Voltage using Line Losses (1-Phase 2-Wire US)

Maximum Voltage using Line Losses (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Maximum Voltage using Line Losses (1-Phase 2-Wire US)?

FIRST Step Consider the formula

V m = 2 \cdot P \cdot \frac{\sqrt{ρ \cdot \frac{L}{A \cdot P loss}}}{\cos (Φ)}

Next Step Substitute values of Variables

∴

V m = 2 \cdot 300W \cdot \frac{\sqrt{1.7E-5Ω*m \cdot \frac{24m}{1.28m² \cdot 2.67W}}}{\cos (30°)}

Next Step Convert Units

∴

V m = 2 \cdot 300W \cdot \frac{\sqrt{1.7E-5Ω*m \cdot \frac{24m}{1.28m² \cdot 2.67W}}}{\cos (0.5236rad)}

Next Step Prepare to Evaluate

∴

V m = 2 \cdot 300 \cdot \frac{\sqrt{1.7E-5 \cdot \frac{24}{1.28 \cdot 2.67}}}{\cos (0.5236)}

Next Step Evaluate

∴

V m = 7.56989899447257V

LAST Step Rounding Answer

∴

V m = 7.5699V

Maximum Voltage using Line Losses (1-Phase 2-Wire US) Formula Elements

Variables

Functions

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

Area of Underground AC Wire

Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.

Symbol: A

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Area of Underground AC Wire

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Maximum Voltage Underground AC

Go Maximum Voltage using Area of X-Section (1-Phase 2-Wire US)

V m = \sqrt{\frac{4 \cdot L \cdot ρ \cdot (P^{2})}{A \cdot P loss \cdot {(\cos (Φ))}^{2}}}

Go Maximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US)

V m = \sqrt{8 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot V \cdot {(\cos (Φ))}^{2}}}

Other formulas in Current and Voltage category

Go RMS Voltage(1-Phase 2-Wire US)

V rms = \frac{V m}{\sqrt{2}}

Go Load Current (1-Phase 2-Wire US)

I = P \cdot \frac{\sqrt{2}}{V m \cdot \cos (Φ)}

How to Evaluate Maximum Voltage using Line Losses (1-Phase 2-Wire US)?

Maximum Voltage using Line Losses (1-Phase 2-Wire US) evaluator uses Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference) to evaluate the Maximum Voltage Underground AC, The Maximum Voltage using Line Losses (1-Phase 2-Wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition. Maximum Voltage Underground AC is denoted by V_m symbol.

How to evaluate Maximum Voltage using Line Losses (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Maximum Voltage using Line Losses (1-Phase 2-Wire US), enter Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A), Line Losses (P_loss) & Phase Difference (Φ) and hit the calculate button.

FAQs on Maximum Voltage using Line Losses (1-Phase 2-Wire US)

What is the formula to find Maximum Voltage using Line Losses (1-Phase 2-Wire US)?

The formula of Maximum Voltage using Line Losses (1-Phase 2-Wire US) is expressed as Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference). Here is an example- 7.569899 = 2*300*sqrt(1.7E-05*24/(1.28*2.67))/cos(0.5235987755982).

How to calculate Maximum Voltage using Line Losses (1-Phase 2-Wire US)?

With Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A), Line Losses (P_loss) & Phase Difference (Φ) we can find Maximum Voltage using Line Losses (1-Phase 2-Wire US) using the formula - Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference). This formula also uses Cosine (cos), Square Root (sqrt) function(s).

What are the other ways to Calculate Maximum Voltage Underground AC?

Here are the different ways to Calculate Maximum Voltage Underground AC-

Maximum Voltage Underground AC=sqrt((4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*Line Losses*(cos(Phase Difference))^2))
Maximum Voltage Underground AC=sqrt(8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*Volume Of Conductor*(cos(Phase Difference))^2))
Maximum Voltage Underground AC=(sqrt(2))*Power Transmitted/(Current Underground AC*(cos(Phase Difference)))

Can the Maximum Voltage using Line Losses (1-Phase 2-Wire US) be negative?

Yes, the Maximum Voltage using Line Losses (1-Phase 2-Wire US), measured in Electric Potential can be negative.

Which unit is used to measure Maximum Voltage using Line Losses (1-Phase 2-Wire US)?

Maximum Voltage using Line Losses (1-Phase 2-Wire US) is usually measured using the Volt[V] for Electric Potential. Millivolt[V], Microvolt[V], Nanovolt[V] are the few other units in which Maximum Voltage using Line Losses (1-Phase 2-Wire US) can be measured.

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Maximum Voltage using Line Losses (1-Phase 2-Wire US) Formula

​GoMaximum Voltage using Area of X-Section (1-Phase 2-Wire US) Formula

​GoMaximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US) Formula

Maximum Voltage using Line Losses (1-Phase 2-Wire US) Example

Maximum Voltage using Line Losses (1-Phase 2-Wire US) Solution

Maximum Voltage using Line Losses (1-Phase 2-Wire US) Formula Elements

Other Formulas to find Maximum Voltage Underground AC

Other formulas in Current and Voltage category

How to Evaluate Maximum Voltage using Line Losses (1-Phase 2-Wire US)?

FAQs on Maximum Voltage using Line Losses (1-Phase 2-Wire US)

Variable Name

GoMaximum Voltage using Area of X-Section (1-Phase 2-Wire US) Formula

GoMaximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US) Formula