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Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula

GoMaximum Voltage using Load Current (1-Phase 2-Wire Mid-Point Earthed) Formula

GoMaximum Voltage using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Formula

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Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire. Check FAQs

V m = (\frac{2 \cdot P}{\cos (Φ)}) \cdot \sqrt{ρ \cdot \frac{L}{A \cdot P loss}}

V_m - Maximum Voltage Underground AC?P - Power Transmitted?Φ - Phase Difference?ρ - Resistivity?L - Length of Underground AC Wire?A - Area of Underground AC Wire?P_loss - Line Losses?

Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Example

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Here is how the Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) equation looks like with Values.

Here is how the Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) equation looks like with Units.

Here is how the Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) equation looks like.

7.5699 = (\frac{2 \cdot 300}{\cos (30)}) \cdot \sqrt{1.7E-5 \cdot \frac{24}{1.28 \cdot 2.67}}

7.5699V = (\frac{2 \cdot 300W}{\cos (30°)}) \cdot \sqrt{1.7E-5Ω*m \cdot \frac{24m}{1.28m² \cdot 2.67W}}

7.5699 = (\frac{2 \cdot 300}{\cos (30)}) \cdot \sqrt{1.7E-5 \cdot \frac{24}{1.28 \cdot 2.67}}

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Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Solution

Follow our step by step solution on how to calculate Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

FIRST Step Consider the formula

V m = (\frac{2 \cdot P}{\cos (Φ)}) \cdot \sqrt{ρ \cdot \frac{L}{A \cdot P loss}}

Next Step Substitute values of Variables

∴

V m = (\frac{2 \cdot 300W}{\cos (30°)}) \cdot \sqrt{1.7E-5Ω*m \cdot \frac{24m}{1.28m² \cdot 2.67W}}

Next Step Convert Units

∴

V m = (\frac{2 \cdot 300W}{\cos (0.5236rad)}) \cdot \sqrt{1.7E-5Ω*m \cdot \frac{24m}{1.28m² \cdot 2.67W}}

Next Step Prepare to Evaluate

∴

V m = (\frac{2 \cdot 300}{\cos (0.5236)}) \cdot \sqrt{1.7E-5 \cdot \frac{24}{1.28 \cdot 2.67}}

Next Step Evaluate

∴

V m = 7.56989899447257V

LAST Step Rounding Answer

∴

V m = 7.5699V

Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula Elements

Variables

Functions

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

Area of Underground AC Wire

Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.

Symbol: A

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Area of Underground AC Wire

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Maximum Voltage Underground AC

Go Maximum Voltage using Load Current (1-Phase 2-Wire Mid-Point Earthed)

V m = \frac{\sqrt{2} \cdot P}{I \cdot \cos (Φ)}

Go Maximum Voltage using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

V m = (\frac{2 \cdot P}{\cos (Φ)}) \cdot \sqrt{\frac{R}{P loss}}

Other formulas in Current and Voltage category

Go Load Current (1-Phase 2-Wire Mid-Point Earthed)

I = \frac{\sqrt{2} \cdot P}{V m \cdot \cos (Φ)}

Go Load Current using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

I = \sqrt{\frac{P loss}{2 \cdot R}}

How to Evaluate Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) evaluator uses Maximum Voltage Underground AC = ((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)) to evaluate the Maximum Voltage Underground AC, The Maximum Voltage using Area of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition. Maximum Voltage Underground AC is denoted by V_m symbol.

How to evaluate Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) using this online evaluator? To use this online evaluator for Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed), enter Power Transmitted (P), Phase Difference (Φ), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A) & Line Losses (P_loss) and hit the calculate button.

FAQs on Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

What is the formula to find Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

The formula of Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) is expressed as Maximum Voltage Underground AC = ((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)). Here is an example- 7.569899 = ((2*300)/cos(0.5235987755982))*sqrt(1.7E-05*24/(1.28*2.67)).

How to calculate Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

With Power Transmitted (P), Phase Difference (Φ), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A) & Line Losses (P_loss) we can find Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) using the formula - Maximum Voltage Underground AC = ((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)). This formula also uses Cosine (cos), Square Root (sqrt) function(s).

What are the other ways to Calculate Maximum Voltage Underground AC?

Here are the different ways to Calculate Maximum Voltage Underground AC-

Maximum Voltage Underground AC=(sqrt(2)*Power Transmitted)/(Current Underground AC*cos(Phase Difference))
Maximum Voltage Underground AC=((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistance Underground AC/Line Losses)

Can the Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) be negative?

Yes, the Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed), measured in Electric Potential can be negative.

Which unit is used to measure Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) is usually measured using the Volt[V] for Electric Potential. Millivolt[V], Microvolt[V], Nanovolt[V] are the few other units in which Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) can be measured.

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Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula

​GoMaximum Voltage using Load Current (1-Phase 2-Wire Mid-Point Earthed) Formula

​GoMaximum Voltage using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Formula

Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Example

Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Solution

Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula Elements

Other Formulas to find Maximum Voltage Underground AC

Other formulas in Current and Voltage category

How to Evaluate Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

FAQs on Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Variable Name

GoMaximum Voltage using Load Current (1-Phase 2-Wire Mid-Point Earthed) Formula

GoMaximum Voltage using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Formula