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Maximum Height is denoted as the largest distance an object covers in vertical direction in a projectile motion. Check FAQs
hmax=vpm2sin(αpr)22[g]
hmax - Maximum Height?vpm - Initial Velocity of Projectile Motion?αpr - Angle of Projection?[g] - Gravitational acceleration on Earth?

Maximum Height of Projectile on Horizontal Plane Example

With values
With units
Only example

Here is how the Maximum Height of Projectile on Horizontal Plane equation looks like with Values.

Here is how the Maximum Height of Projectile on Horizontal Plane equation looks like with Units.

Here is how the Maximum Height of Projectile on Horizontal Plane equation looks like.

22.9509Edit=30.01Edit2sin(44.99Edit)229.8066
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Maximum Height of Projectile on Horizontal Plane Solution

Follow our step by step solution on how to calculate Maximum Height of Projectile on Horizontal Plane?

FIRST Step Consider the formula
hmax=vpm2sin(αpr)22[g]
Next Step Substitute values of Variables
hmax=30.01m/s2sin(44.99°)22[g]
Next Step Substitute values of Constants
hmax=30.01m/s2sin(44.99°)229.8066m/s²
Next Step Convert Units
hmax=30.01m/s2sin(0.7852rad)229.8066m/s²
Next Step Prepare to Evaluate
hmax=30.012sin(0.7852)229.8066
Next Step Evaluate
hmax=22.9508989121245m
LAST Step Rounding Answer
hmax=22.9509m

Maximum Height of Projectile on Horizontal Plane Formula Elements

Variables
Constants
Functions
Maximum Height
Maximum Height is denoted as the largest distance an object covers in vertical direction in a projectile motion.
Symbol: hmax
Measurement: LengthUnit: m
Note: Value should be greater than 0.
Initial Velocity of Projectile Motion
Initial Velocity of Projectile Motion is the velocity at which motion starts.
Symbol: vpm
Measurement: SpeedUnit: m/s
Note: Value should be greater than 0.
Angle of Projection
Angle of Projection is angle made by the particle with horizontal when projected upwards with some initial velocity.
Symbol: αpr
Measurement: AngleUnit: °
Note: Value should be greater than 0.
Gravitational acceleration on Earth
Gravitational acceleration on Earth means that the velocity of an object in free fall will increase by 9.8 m/s2 every second.
Symbol: [g]
Value: 9.80665 m/s²
sin
Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.
Syntax: sin(Angle)

Other Formulas to find Maximum Height

​Go Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity
hmax=vvertpr

Other formulas in Projectile Motion category

​Go Horizontal Component of Velocity of Particle Projected Upwards from Point at Angle
vh=vpmcos(αpr)
​Go Vertical Component of Velocity of Particle Projected Upwards from Point at Angle
vv=vpmsin(αpr)
​Go Initial Velocity of Particle given Horizontal Component of Velocity
vpm=vhcos(αpr)
​Go Initial Velocity of Particle given Vertical Component of Velocity
vpm=vvsin(αpr)

How to Evaluate Maximum Height of Projectile on Horizontal Plane?

Maximum Height of Projectile on Horizontal Plane evaluator uses Maximum Height = (Initial Velocity of Projectile Motion^2*sin(Angle of Projection)^2)/(2*[g]) to evaluate the Maximum Height, Maximum Height of Projectile on Horizontal Plane formula is defined as the highest point reached by an object in a horizontal plane under the sole influence of gravity, where the object is projected with an initial velocity at an angle of elevation, and it depends on the initial velocity and the angle of projection. Maximum Height is denoted by hmax symbol.

How to evaluate Maximum Height of Projectile on Horizontal Plane using this online evaluator? To use this online evaluator for Maximum Height of Projectile on Horizontal Plane, enter Initial Velocity of Projectile Motion (vpm) & Angle of Projection pr) and hit the calculate button.

FAQs on Maximum Height of Projectile on Horizontal Plane

What is the formula to find Maximum Height of Projectile on Horizontal Plane?
The formula of Maximum Height of Projectile on Horizontal Plane is expressed as Maximum Height = (Initial Velocity of Projectile Motion^2*sin(Angle of Projection)^2)/(2*[g]). Here is an example- 22.95891 = (30.01^2*sin(0.785223630472101)^2)/(2*[g]).
How to calculate Maximum Height of Projectile on Horizontal Plane?
With Initial Velocity of Projectile Motion (vpm) & Angle of Projection pr) we can find Maximum Height of Projectile on Horizontal Plane using the formula - Maximum Height = (Initial Velocity of Projectile Motion^2*sin(Angle of Projection)^2)/(2*[g]). This formula also uses Gravitational acceleration on Earth constant(s) and Sine (sin) function(s).
What are the other ways to Calculate Maximum Height?
Here are the different ways to Calculate Maximum Height-
  • Maximum Height=Average Vertical Velocity*Time IntervalOpenImg
Can the Maximum Height of Projectile on Horizontal Plane be negative?
No, the Maximum Height of Projectile on Horizontal Plane, measured in Length cannot be negative.
Which unit is used to measure Maximum Height of Projectile on Horizontal Plane?
Maximum Height of Projectile on Horizontal Plane is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Maximum Height of Projectile on Horizontal Plane can be measured.
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