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Maximum Height Attained by Object Formula

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Maximum Height of Crack is the highest point reached by an object under the influence of gravity, friction, and other external forces during its motion. Check FAQs

v max = \frac{{(u \cdot \sin (θ pr))}^{2}}{2 \cdot g}

v_max - Maximum Height of Crack?u - Initial Velocity?θ_pr - Angle of Projection?g - Acceleration due to Gravity?

Maximum Height Attained by Object Example

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Here is how the Maximum Height Attained by Object equation looks like with Values.

Here is how the Maximum Height Attained by Object equation looks like with Units.

Here is how the Maximum Height Attained by Object equation looks like.

9.4779 = \frac{{(35 \cdot \sin (0.4))}^{2}}{2 \cdot 9.8}

9.4779m = \frac{{(35m/s \cdot \sin (0.4rad))}^{2}}{2 \cdot 9.8m/s²}

9.4779 = \frac{{(35 \cdot \sin (0.4))}^{2}}{2 \cdot 9.8}

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Maximum Height Attained by Object Solution

Follow our step by step solution on how to calculate Maximum Height Attained by Object?

FIRST Step Consider the formula

v max = \frac{{(u \cdot \sin (θ pr))}^{2}}{2 \cdot g}

Next Step Substitute values of Variables

∴

v max = \frac{{(35m/s \cdot \sin (0.4rad))}^{2}}{2 \cdot 9.8m/s²}

Next Step Prepare to Evaluate

∴

v max = \frac{{(35 \cdot \sin (0.4))}^{2}}{2 \cdot 9.8}

Next Step Evaluate

∴

v max = 9.47791533290108m

LAST Step Rounding Answer

∴

v max = 9.4779m

Maximum Height Attained by Object Formula Elements

Variables

Functions

Maximum Height of Crack

Maximum Height of Crack is the highest point reached by an object under the influence of gravity, friction, and other external forces during its motion.

Symbol: v_max

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Maximum Height of Crack

Initial Velocity

Initial Velocity is the velocity of an object at the start of a motion, describing the object's initial state of motion.

Symbol: u

Measurement: SpeedUnit: m/s

Note: Value should be greater than 0.

Formulas to find Initial Velocity

Angle of Projection

Angle of Projection is the angle at which an object is projected from the ground, influencing its trajectory and range of motion.

Symbol: θ_pr

Measurement: AngleUnit: rad

Note: Value can be positive or negative.

Formulas to find Angle of Projection

Acceleration due to Gravity

Acceleration due to Gravity is the rate of change of velocity of an object under the influence of gravitational force, typically measured in meters per second squared.

Symbol: g

Measurement: AccelerationUnit: m/s²

Note: Value should be greater than 0.

Formulas to find Acceleration due to Gravity

sin

Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.

Syntax: sin(Angle)

Other formulas in Projectile Motion category

Go Maximum Height Attained for Inclined Projectile

H max = \frac{{(u \cdot \sin (θ inclination))}^{2}}{2 \cdot g \cdot \cos (α pl)}

Go Time of Flight for Inclined Projectile

T = \frac{2 \cdot u \cdot \sin (θ inclination)}{g \cdot \cos (α pl)}

Go Maximum Range of Flight for Inclined Projectile

R motion = \frac{u^{2} \cdot (1 - \sin (α pl))}{g \cdot {(\cos (α pl))}^{2}}

Go Time of Flight

T = \frac{2 \cdot u \cdot \sin (θ pr)}{g}

How to Evaluate Maximum Height Attained by Object?

Maximum Height Attained by Object evaluator uses Maximum Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity) to evaluate the Maximum Height of Crack, Maximum Height Attained by Object formula is defined as the highest point reached by an object under the sole influence of gravity, characterizing the maximum altitude achieved during its projectile motion. Maximum Height of Crack is denoted by v_max symbol.

How to evaluate Maximum Height Attained by Object using this online evaluator? To use this online evaluator for Maximum Height Attained by Object, enter Initial Velocity (u), Angle of Projection (θ_pr) & Acceleration due to Gravity (g) and hit the calculate button.

FAQs on Maximum Height Attained by Object

What is the formula to find Maximum Height Attained by Object?

The formula of Maximum Height Attained by Object is expressed as Maximum Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity). Here is an example- 9.477915 = ((35*sin(0.4))^2)/(2*9.8).

How to calculate Maximum Height Attained by Object?

With Initial Velocity (u), Angle of Projection (θ_pr) & Acceleration due to Gravity (g) we can find Maximum Height Attained by Object using the formula - Maximum Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity). This formula also uses Sine (sin) function(s).

Can the Maximum Height Attained by Object be negative?

No, the Maximum Height Attained by Object, measured in Length cannot be negative.

Which unit is used to measure Maximum Height Attained by Object?

Maximum Height Attained by Object is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Maximum Height Attained by Object can be measured.

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Maximum Height Attained by Object Formula

Maximum Height Attained by Object Example

Maximum Height Attained by Object Solution

Maximum Height Attained by Object Formula Elements

Other formulas in Projectile Motion category

How to Evaluate Maximum Height Attained by Object?

FAQs on Maximum Height Attained by Object

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