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Magnetic Field on Axis of Ring Formula

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GoMagnetic Field due to Straight Conductor Formula

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The Magnetic Field is a vector field around a magnet or electric current that exerts force on other magnets or moving charges. It is described by both direction and strength. Check FAQs

B = \frac{[Permeability-vacuum] \cdot i \cdot {r ring}^{2}}{2 \cdot {({r ring}^{2} + d^{2})}^{\frac{3}{2}}}

B - Magnetic Field?i - Electric Current?r_ring - Radius of Ring?d - Perpendicular Distance?[Permeability-vacuum] - Permeability of vacuum?

Magnetic Field on Axis of Ring Example

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Here is how the Magnetic Field on Axis of Ring equation looks like with Values.

Here is how the Magnetic Field on Axis of Ring equation looks like with Units.

Here is how the Magnetic Field on Axis of Ring equation looks like.

1.2E-5 = \frac{1.3E-6 \cdot 0.1249 \cdot {0.006}^{2}}{2 \cdot {({0.006}^{2} + {0.0017}^{2})}^{\frac{3}{2}}}

1.2E-5Wb/m² = \frac{1.3E-6 \cdot 0.1249A \cdot {0.006m}^{2}}{2 \cdot {({0.006m}^{2} + {0.0017m}^{2})}^{\frac{3}{2}}}

1.2E-5 = \frac{1.3E-6 \cdot 0.1249 \cdot {0.006}^{2}}{2 \cdot {({0.006}^{2} + {0.0017}^{2})}^{\frac{3}{2}}}

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Magnetic Field on Axis of Ring Solution

Follow our step by step solution on how to calculate Magnetic Field on Axis of Ring?

FIRST Step Consider the formula

B = \frac{[Permeability-vacuum] \cdot i \cdot {r ring}^{2}}{2 \cdot {({r ring}^{2} + d^{2})}^{\frac{3}{2}}}

Next Step Substitute values of Variables

∴

B = \frac{[Permeability-vacuum] \cdot 0.1249A \cdot {0.006m}^{2}}{2 \cdot {({0.006m}^{2} + {0.0017m}^{2})}^{\frac{3}{2}}}

Next Step Substitute values of Constants

∴

B = \frac{1.3E-6 \cdot 0.1249A \cdot {0.006m}^{2}}{2 \cdot {({0.006m}^{2} + {0.0017m}^{2})}^{\frac{3}{2}}}

Next Step Prepare to Evaluate

∴

B = \frac{1.3E-6 \cdot 0.1249 \cdot {0.006}^{2}}{2 \cdot {({0.006}^{2} + {0.0017}^{2})}^{\frac{3}{2}}}

Next Step Evaluate

∴

B = 1.1633675292799E-05T

Next Step Convert to Output's Unit

∴

B = 1.1633675292799E-05Wb/m²

LAST Step Rounding Answer

∴

B = 1.2E-5Wb/m²

Magnetic Field on Axis of Ring Formula Elements

Variables

Constants

Magnetic Field

The Magnetic Field is a vector field around a magnet or electric current that exerts force on other magnets or moving charges. It is described by both direction and strength.

Symbol: B

Measurement: Magnetic FieldUnit: Wb/m²

Note: Value can be positive or negative.

Formulas to find Magnetic Field

Electric Current

Electric Current is the flow of electric charge through a conductor. It is measured by the amount of charge passing a point in the conductor per unit time.

Symbol: i

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Electric Current

Radius of Ring

The Radius of Ring is the distance from the center of the ring to any point on its circumference. It determines the size and shape of the ring.

Symbol: r_ring

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Radius of Ring

Perpendicular Distance

Perpendicular Distance is the shortest distance between a point and a line or surface, measured at a right angle to the line or surface.

Symbol: d

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Perpendicular Distance

Permeability of vacuum

Permeability of vacuum is a fundamental physical constant that relates the magnetic field within a vacuum to the current producing that field.

Symbol: [Permeability-vacuum]

Value: 1.2566E-6

Other Formulas to find Magnetic Field

Go Field Inside Solenoid

B = \frac{[Permeability-vacuum] \cdot i \cdot N}{L solenoid}

Go Magnetic Field due to Straight Conductor

B = \frac{[Permeability-vacuum] \cdot i}{4 \cdot π \cdot d} \cdot (\cos (θ 1) - \cos (θ 2))

Go Magnetic Field Due to Infinite Straight Wire

B = \frac{[Permeability-vacuum] \cdot i}{2 \cdot π \cdot d}

Other formulas in Magnetism category

Go Force between Parallel Wires

F 𝑙 = \frac{[Permeability-vacuum] \cdot I 1 \cdot I 2}{2 \cdot π \cdot d}

Go Magnetic Field at Center of Arc

M arc = \frac{[Permeability-vacuum] \cdot i \cdot θ arc}{4 \cdot π \cdot r ring}

Go Magnetic Field at Center of Ring

M ring = \frac{[Permeability-vacuum] \cdot i}{2 \cdot r ring}

Go Field of Bar Magnet at Axial position

B axial = \frac{2 \cdot [Permeability-vacuum] \cdot M}{4 \cdot π \cdot a^{3}}

How to Evaluate Magnetic Field on Axis of Ring?

Magnetic Field on Axis of Ring evaluator uses Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2)) to evaluate the Magnetic Field, Magnetic Field on Axis of Ring formula is defined as a measure of the magnetic field strength at a point on the axis of a current-carrying ring, which is influenced by the ring's dimensions, the current flowing through it, and the permeability of the surrounding medium. Magnetic Field is denoted by B symbol.

How to evaluate Magnetic Field on Axis of Ring using this online evaluator? To use this online evaluator for Magnetic Field on Axis of Ring, enter Electric Current (i), Radius of Ring (r_ring) & Perpendicular Distance (d) and hit the calculate button.

FAQs on Magnetic Field on Axis of Ring

What is the formula to find Magnetic Field on Axis of Ring?

The formula of Magnetic Field on Axis of Ring is expressed as Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2)). Here is an example- 1.3E-5 = ([Permeability-vacuum]*0.1249*0.006^2)/(2*(0.006^2+0.00171^2)^(3/2)).

How to calculate Magnetic Field on Axis of Ring?

With Electric Current (i), Radius of Ring (r_ring) & Perpendicular Distance (d) we can find Magnetic Field on Axis of Ring using the formula - Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2)). This formula also uses Permeability of vacuum constant(s).

What are the other ways to Calculate Magnetic Field?

Here are the different ways to Calculate Magnetic Field-

Magnetic Field=([Permeability-vacuum]*Electric Current*Number of Turns)/Length of Solenoid
Magnetic Field=([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2))
Magnetic Field=([Permeability-vacuum]*Electric Current)/(2*pi*Perpendicular Distance)

Can the Magnetic Field on Axis of Ring be negative?

Yes, the Magnetic Field on Axis of Ring, measured in Magnetic Field can be negative.

Which unit is used to measure Magnetic Field on Axis of Ring?

Magnetic Field on Axis of Ring is usually measured using the Weber per Square Meter[Wb/m²] for Magnetic Field. Tesla[Wb/m²], Microtesla[Wb/m²], Megatesla[Wb/m²] are the few other units in which Magnetic Field on Axis of Ring can be measured.

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Magnetic Field on Axis of Ring Formula

​GoField Inside Solenoid Formula

​GoMagnetic Field due to Straight Conductor Formula

Magnetic Field on Axis of Ring Example

Magnetic Field on Axis of Ring Solution

Magnetic Field on Axis of Ring Formula Elements

Other Formulas to find Magnetic Field

Other formulas in Magnetism category

How to Evaluate Magnetic Field on Axis of Ring?

FAQs on Magnetic Field on Axis of Ring

Variable Name

GoField Inside Solenoid Formula

GoMagnetic Field due to Straight Conductor Formula