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Magnetic Field for Hertzian Dipole Formula

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Magnetic Field Component refers to the azimuthal component of the magnetic field. Check FAQs

H Φ = {(\frac{1}{r})}^{2} \cdot (\cos (2 \cdot π \cdot \frac{r}{λ}) + 2 \cdot π \cdot \frac{r}{λ} \cdot \sin (2 \cdot π \cdot \frac{r}{λ}))

H_Φ - Magnetic Field Component?r - Dipole Distance?λ - Dipole Wavelength?π - Archimedes' constant?

Magnetic Field for Hertzian Dipole Example

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Here is how the Magnetic Field for Hertzian Dipole equation looks like with Values.

Here is how the Magnetic Field for Hertzian Dipole equation looks like with Units.

Here is how the Magnetic Field for Hertzian Dipole equation looks like.

6.773 = {(\frac{1}{8.3})}^{2} \cdot (\cos (2 \cdot 3.1416 \cdot \frac{8.3}{20}) + 2 \cdot 3.1416 \cdot \frac{8.3}{20} \cdot \sin (2 \cdot 3.1416 \cdot \frac{8.3}{20}))

6.773mA/m = {(\frac{1}{8.3m})}^{2} \cdot (\cos (2 \cdot 3.1416 \cdot \frac{8.3m}{20m}) + 2 \cdot 3.1416 \cdot \frac{8.3m}{20m} \cdot \sin (2 \cdot 3.1416 \cdot \frac{8.3m}{20m}))

6.773 = {(\frac{1}{8.3})}^{2} \cdot (\cos (2 \cdot 3.1416 \cdot \frac{8.3}{20}) + 2 \cdot 3.1416 \cdot \frac{8.3}{20} \cdot \sin (2 \cdot 3.1416 \cdot \frac{8.3}{20}))

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Magnetic Field for Hertzian Dipole Solution

Follow our step by step solution on how to calculate Magnetic Field for Hertzian Dipole?

FIRST Step Consider the formula

H Φ = {(\frac{1}{r})}^{2} \cdot (\cos (2 \cdot π \cdot \frac{r}{λ}) + 2 \cdot π \cdot \frac{r}{λ} \cdot \sin (2 \cdot π \cdot \frac{r}{λ}))

Next Step Substitute values of Variables

∴

H Φ = {(\frac{1}{8.3m})}^{2} \cdot (\cos (2 \cdot π \cdot \frac{8.3m}{20m}) + 2 \cdot π \cdot \frac{8.3m}{20m} \cdot \sin (2 \cdot π \cdot \frac{8.3m}{20m}))

Next Step Substitute values of Constants

∴

H Φ = {(\frac{1}{8.3m})}^{2} \cdot (\cos (2 \cdot 3.1416 \cdot \frac{8.3m}{20m}) + 2 \cdot 3.1416 \cdot \frac{8.3m}{20m} \cdot \sin (2 \cdot 3.1416 \cdot \frac{8.3m}{20m}))

Next Step Prepare to Evaluate

∴

H Φ = {(\frac{1}{8.3})}^{2} \cdot (\cos (2 \cdot 3.1416 \cdot \frac{8.3}{20}) + 2 \cdot 3.1416 \cdot \frac{8.3}{20} \cdot \sin (2 \cdot 3.1416 \cdot \frac{8.3}{20}))

Next Step Evaluate

∴

H Φ = 0.00677303837762137A/m

Next Step Convert to Output's Unit

∴

H Φ = 6.77303837762137mA/m

LAST Step Rounding Answer

∴

H Φ = 6.773mA/m

Magnetic Field for Hertzian Dipole Formula Elements

Variables

Constants

Functions

Magnetic Field Component

Magnetic Field Component refers to the azimuthal component of the magnetic field.

Symbol: H_Φ

Measurement: Linear Current DensityUnit: mA/m

Note: Value can be positive or negative.

Formulas to find Magnetic Field Component

Dipole Distance

Dipole Distance refers to the radial distance from the dipole.

Symbol: r

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Dipole Distance

Dipole Wavelength

Dipole Wavelength refers to the wavelength of radiation emitted by the dipole.

Symbol: λ

Measurement: WavelengthUnit: m

Note: Value should be greater than 0.

Formulas to find Dipole Wavelength

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

sin

Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.

Syntax: sin(Angle)

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other formulas in Electromagnetic Radiation and Antennas category

Go Radiation Resistance of Antenna

R rad = 2 \cdot \frac{P r}{{i o}^{2}}

Go Average Power

P r = \frac{1}{2} \cdot {i o}^{2} \cdot R rad

Go Poynting Vector Magnitude

S r = \frac{1}{2} \cdot {(\frac{I d \cdot k \cdot d}{4 \cdot π})}^{2} \cdot η \cdot {(\sin (θ))}^{2}

Go Radiation Efficiency of Antenna

η r = \frac{G}{D max}

How to Evaluate Magnetic Field for Hertzian Dipole?

Magnetic Field for Hertzian Dipole evaluator uses Magnetic Field Component = (1/Dipole Distance)^2*(cos(2*pi*Dipole Distance/Dipole Wavelength)+2*pi*Dipole Distance/Dipole Wavelength*sin(2*pi*Dipole Distance/Dipole Wavelength)) to evaluate the Magnetic Field Component, Magnetic Field for Hertzian Dipole is the component of the radiated electromagnetic wave, perpendicular to the electric field, varying with distance and angle, proportional to current and inversely proportional to distance. Magnetic Field Component is denoted by H_Φ symbol.

How to evaluate Magnetic Field for Hertzian Dipole using this online evaluator? To use this online evaluator for Magnetic Field for Hertzian Dipole, enter Dipole Distance (r) & Dipole Wavelength (λ) and hit the calculate button.

FAQs on Magnetic Field for Hertzian Dipole

What is the formula to find Magnetic Field for Hertzian Dipole?

The formula of Magnetic Field for Hertzian Dipole is expressed as Magnetic Field Component = (1/Dipole Distance)^2*(cos(2*pi*Dipole Distance/Dipole Wavelength)+2*pi*Dipole Distance/Dipole Wavelength*sin(2*pi*Dipole Distance/Dipole Wavelength)). Here is an example- 6773.038 = (1/8.3)^2*(cos(2*pi*8.3/20)+2*pi*8.3/20*sin(2*pi*8.3/20)).

How to calculate Magnetic Field for Hertzian Dipole?

With Dipole Distance (r) & Dipole Wavelength (λ) we can find Magnetic Field for Hertzian Dipole using the formula - Magnetic Field Component = (1/Dipole Distance)^2*(cos(2*pi*Dipole Distance/Dipole Wavelength)+2*pi*Dipole Distance/Dipole Wavelength*sin(2*pi*Dipole Distance/Dipole Wavelength)). This formula also uses Archimedes' constant and , Sine (sin), Cosine (cos) function(s).

Can the Magnetic Field for Hertzian Dipole be negative?

Yes, the Magnetic Field for Hertzian Dipole, measured in Linear Current Density can be negative.

Which unit is used to measure Magnetic Field for Hertzian Dipole?

Magnetic Field for Hertzian Dipole is usually measured using the Milliampere per Meter[mA/m] for Linear Current Density. Ampere per Meter[mA/m], Ampere per Inch[mA/m], Abampere per Meter[mA/m] are the few other units in which Magnetic Field for Hertzian Dipole can be measured.

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