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Magnetic Field due to Straight Conductor Formula

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GoField Inside Solenoid Formula

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The Magnetic Field is a vector field around a magnet or electric current that exerts force on other magnets or moving charges. It is described by both direction and strength. Check FAQs

B = \frac{[Permeability-vacuum] \cdot i}{4 \cdot π \cdot d} \cdot (\cos (θ 1) - \cos (θ 2))

B - Magnetic Field?i - Electric Current?d - Perpendicular Distance?θ₁ - Theta 1?θ₂ - Theta 2?[Permeability-vacuum] - Permeability of vacuum?π - Archimedes' constant?

Magnetic Field due to Straight Conductor Example

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Here is how the Magnetic Field due to Straight Conductor equation looks like with Values.

Here is how the Magnetic Field due to Straight Conductor equation looks like with Units.

Here is how the Magnetic Field due to Straight Conductor equation looks like.

1.5E-6 = \frac{1.3E-6 \cdot 0.1249}{4 \cdot 3.1416 \cdot 0.0017} \cdot (\cos (45) - \cos (60))

1.5E-6Wb/m² = \frac{1.3E-6 \cdot 0.1249A}{4 \cdot 3.1416 \cdot 0.0017m} \cdot (\cos (45°) - \cos (60°))

1.5E-6 = \frac{1.3E-6 \cdot 0.1249}{4 \cdot 3.1416 \cdot 0.0017} \cdot (\cos (45) - \cos (60))

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Magnetic Field due to Straight Conductor Solution

Follow our step by step solution on how to calculate Magnetic Field due to Straight Conductor?

FIRST Step Consider the formula

B = \frac{[Permeability-vacuum] \cdot i}{4 \cdot π \cdot d} \cdot (\cos (θ 1) - \cos (θ 2))

Next Step Substitute values of Variables

∴

B = \frac{[Permeability-vacuum] \cdot 0.1249A}{4 \cdot π \cdot 0.0017m} \cdot (\cos (45°) - \cos (60°))

Next Step Substitute values of Constants

∴

B = \frac{1.3E-6 \cdot 0.1249A}{4 \cdot 3.1416 \cdot 0.0017m} \cdot (\cos (45°) - \cos (60°))

Next Step Convert Units

∴

B = \frac{1.3E-6 \cdot 0.1249A}{4 \cdot 3.1416 \cdot 0.0017m} \cdot (\cos (0.7854rad) - \cos (1.0472rad))

Next Step Prepare to Evaluate

∴

B = \frac{1.3E-6 \cdot 0.1249}{4 \cdot 3.1416 \cdot 0.0017} \cdot (\cos (0.7854) - \cos (1.0472))

Next Step Evaluate

∴

B = 1.51272730819833E-06T

Next Step Convert to Output's Unit

∴

B = 1.51272730819833E-06Wb/m²

LAST Step Rounding Answer

∴

B = 1.5E-6Wb/m²

Magnetic Field due to Straight Conductor Formula Elements

Variables

Constants

Functions

Magnetic Field

The Magnetic Field is a vector field around a magnet or electric current that exerts force on other magnets or moving charges. It is described by both direction and strength.

Symbol: B

Measurement: Magnetic FieldUnit: Wb/m²

Note: Value can be positive or negative.

Formulas to find Magnetic Field

Electric Current

Electric Current is the flow of electric charge through a conductor. It is measured by the amount of charge passing a point in the conductor per unit time.

Symbol: i

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Electric Current

Perpendicular Distance

Perpendicular Distance is the shortest distance between a point and a line or surface, measured at a right angle to the line or surface.

Symbol: d

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Perpendicular Distance

Theta 1

Theta 1 is an angle used to represent a specific orientation or direction in a magnetic field. It is often used in calculations involving magnetic forces or fields.

Symbol: θ₁

Measurement: AngleUnit: °

Note: Value should be between 0 to 180.

Formulas to find Theta 1

Theta 2

Theta 2 is angle representing a different orientation or direction in a magnetic field.

Symbol: θ₂

Measurement: AngleUnit: °

Note: Value should be between 0 to 180.

Formulas to find Theta 2

Permeability of vacuum

Permeability of vacuum is a fundamental physical constant that relates the magnetic field within a vacuum to the current producing that field.

Symbol: [Permeability-vacuum]

Value: 1.2566E-6

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other Formulas to find Magnetic Field

Go Magnetic Field on Axis of Ring

B = \frac{[Permeability-vacuum] \cdot i \cdot {r ring}^{2}}{2 \cdot {({r ring}^{2} + d^{2})}^{\frac{3}{2}}}

Go Field Inside Solenoid

B = \frac{[Permeability-vacuum] \cdot i \cdot N}{L solenoid}

Go Magnetic Field Due to Infinite Straight Wire

B = \frac{[Permeability-vacuum] \cdot i}{2 \cdot π \cdot d}

Other formulas in Magnetism category

Go Force between Parallel Wires

F 𝑙 = \frac{[Permeability-vacuum] \cdot I 1 \cdot I 2}{2 \cdot π \cdot d}

Go Magnetic Field at Center of Arc

M arc = \frac{[Permeability-vacuum] \cdot i \cdot θ arc}{4 \cdot π \cdot r ring}

Go Magnetic Field at Center of Ring

M ring = \frac{[Permeability-vacuum] \cdot i}{2 \cdot r ring}

Go Field of Bar Magnet at Axial position

B axial = \frac{2 \cdot [Permeability-vacuum] \cdot M}{4 \cdot π \cdot a^{3}}

How to Evaluate Magnetic Field due to Straight Conductor?

Magnetic Field due to Straight Conductor evaluator uses Magnetic Field = ([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2)) to evaluate the Magnetic Field, Magnetic Field due to Straight Conductor formula is defined as a measure of the magnetic force per unit length of a straight conductor carrying an electric current, which is influenced by the permeability of the surrounding medium, the current flowing through the conductor, and the distance from the conductor. Magnetic Field is denoted by B symbol.

How to evaluate Magnetic Field due to Straight Conductor using this online evaluator? To use this online evaluator for Magnetic Field due to Straight Conductor, enter Electric Current (i), Perpendicular Distance (d), Theta 1 (θ₁) & Theta 2 (θ₂) and hit the calculate button.

FAQs on Magnetic Field due to Straight Conductor

What is the formula to find Magnetic Field due to Straight Conductor?

The formula of Magnetic Field due to Straight Conductor is expressed as Magnetic Field = ([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2)). Here is an example- 0.269149 = ([Permeability-vacuum]*0.1249)/(4*pi*0.00171)*(cos(0.785398163397301)-cos(1.0471975511964)).

How to calculate Magnetic Field due to Straight Conductor?

With Electric Current (i), Perpendicular Distance (d), Theta 1 (θ₁) & Theta 2 (θ₂) we can find Magnetic Field due to Straight Conductor using the formula - Magnetic Field = ([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2)). This formula also uses Permeability of vacuum, Archimedes' constant and Cosine (cos) function(s).

What are the other ways to Calculate Magnetic Field?

Here are the different ways to Calculate Magnetic Field-

Magnetic Field=([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2))
Magnetic Field=([Permeability-vacuum]*Electric Current*Number of Turns)/Length of Solenoid
Magnetic Field=([Permeability-vacuum]*Electric Current)/(2*pi*Perpendicular Distance)

Can the Magnetic Field due to Straight Conductor be negative?

Yes, the Magnetic Field due to Straight Conductor, measured in Magnetic Field can be negative.

Which unit is used to measure Magnetic Field due to Straight Conductor?

Magnetic Field due to Straight Conductor is usually measured using the Weber per Square Meter[Wb/m²] for Magnetic Field. Tesla[Wb/m²], Microtesla[Wb/m²], Megatesla[Wb/m²] are the few other units in which Magnetic Field due to Straight Conductor can be measured.

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Magnetic Field due to Straight Conductor Formula

​GoMagnetic Field on Axis of Ring Formula

​GoField Inside Solenoid Formula

Magnetic Field due to Straight Conductor Example

Magnetic Field due to Straight Conductor Solution

Magnetic Field due to Straight Conductor Formula Elements

Other Formulas to find Magnetic Field

Other formulas in Magnetism category

How to Evaluate Magnetic Field due to Straight Conductor?

FAQs on Magnetic Field due to Straight Conductor

Variable Name

GoMagnetic Field on Axis of Ring Formula

GoField Inside Solenoid Formula