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Long Diagonal of Heptagon given Inradius Formula

GoLong Diagonal of Heptagon Formula

GoLong Diagonal of Heptagon given Short Diagonal Formula

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Long Diagonal of Heptagon is the straight line joining two non-adjacent vertices which is across three sides of the Heptagon. Check FAQs

d Long = r i \cdot \frac{\tan (\frac{π}{7})}{\sin (\frac{(\frac{π}{2})}{7})}

d_Long - Long Diagonal of Heptagon?r_i - Inradius of Heptagon?π - Archimedes' constant?

Long Diagonal of Heptagon given Inradius Example

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Here is how the Long Diagonal of Heptagon given Inradius equation looks like with Values.

Here is how the Long Diagonal of Heptagon given Inradius equation looks like with Units.

Here is how the Long Diagonal of Heptagon given Inradius equation looks like.

23.8059 = 11 \cdot \frac{\tan (\frac{3.1416}{7})}{\sin (\frac{(\frac{3.1416}{2})}{7})}

23.8059m = 11m \cdot \frac{\tan (\frac{3.1416}{7})}{\sin (\frac{(\frac{3.1416}{2})}{7})}

23.8059 = 11 \cdot \frac{\tan (\frac{3.1416}{7})}{\sin (\frac{(\frac{3.1416}{2})}{7})}

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Long Diagonal of Heptagon given Inradius Solution

Follow our step by step solution on how to calculate Long Diagonal of Heptagon given Inradius?

FIRST Step Consider the formula

d Long = r i \cdot \frac{\tan (\frac{π}{7})}{\sin (\frac{(\frac{π}{2})}{7})}

Next Step Substitute values of Variables

∴

d Long = 11m \cdot \frac{\tan (\frac{π}{7})}{\sin (\frac{(\frac{π}{2})}{7})}

Next Step Substitute values of Constants

∴

d Long = 11m \cdot \frac{\tan (\frac{3.1416}{7})}{\sin (\frac{(\frac{3.1416}{2})}{7})}

Next Step Prepare to Evaluate

∴

d Long = 11 \cdot \frac{\tan (\frac{3.1416}{7})}{\sin (\frac{(\frac{3.1416}{2})}{7})}

Next Step Evaluate

∴

d Long = 23.8059436148277m

LAST Step Rounding Answer

∴

d Long = 23.8059m

Long Diagonal of Heptagon given Inradius Formula Elements

Variables

Constants

Functions

Long Diagonal of Heptagon

Long Diagonal of Heptagon is the straight line joining two non-adjacent vertices which is across three sides of the Heptagon.

Symbol: d_Long

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Long Diagonal of Heptagon

Inradius of Heptagon

Inradius of Heptagon is defined as the radius of the circle which is inscribed inside the Heptagon.

Symbol: r_i

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Inradius of Heptagon

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

sin

Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.

Syntax: sin(Angle)

tan

The tangent of an angle is a trigonometric ratio of the length of the side opposite an angle to the length of the side adjacent to an angle in a right triangle.

Syntax: tan(Angle)

Other Formulas to find Long Diagonal of Heptagon

Go Long Diagonal of Heptagon

d Long = \frac{S}{2 \cdot \sin (\frac{(\frac{π}{2})}{7})}

Go Long Diagonal of Heptagon given Short Diagonal

d Long = \frac{\frac{d Short}{2 \cdot \cos (\frac{π}{7})}}{2 \cdot \sin (\frac{(\frac{π}{2})}{7})}

Go Long Diagonal of Heptagon given Height

d Long = \frac{h \cdot \tan (\frac{(\frac{π}{2})}{7})}{\sin (\frac{(\frac{π}{2})}{7})}

Go Long Diagonal of Heptagon given Perimeter

d Long = \frac{\frac{P}{7}}{2 \cdot \sin (\frac{(\frac{π}{2})}{7})}

How to Evaluate Long Diagonal of Heptagon given Inradius?

Long Diagonal of Heptagon given Inradius evaluator uses Long Diagonal of Heptagon = Inradius of Heptagon*tan(pi/7)/sin(((pi/2))/7) to evaluate the Long Diagonal of Heptagon, The Long Diagonal of Heptagon given Inradius formula is defined as a straight line joining two non-adjacent vertices of the Heptagon across the three sides, calculated using inradius. Long Diagonal of Heptagon is denoted by d_Long symbol.

How to evaluate Long Diagonal of Heptagon given Inradius using this online evaluator? To use this online evaluator for Long Diagonal of Heptagon given Inradius, enter Inradius of Heptagon (r_i) and hit the calculate button.

FAQs on Long Diagonal of Heptagon given Inradius

What is the formula to find Long Diagonal of Heptagon given Inradius?

The formula of Long Diagonal of Heptagon given Inradius is expressed as Long Diagonal of Heptagon = Inradius of Heptagon*tan(pi/7)/sin(((pi/2))/7). Here is an example- 23.80594 = 11*tan(pi/7)/sin(((pi/2))/7).

How to calculate Long Diagonal of Heptagon given Inradius?

With Inradius of Heptagon (r_i) we can find Long Diagonal of Heptagon given Inradius using the formula - Long Diagonal of Heptagon = Inradius of Heptagon*tan(pi/7)/sin(((pi/2))/7). This formula also uses Archimedes' constant and , Sine (sin), Tangent (tan) function(s).

What are the other ways to Calculate Long Diagonal of Heptagon?

Here are the different ways to Calculate Long Diagonal of Heptagon-

Long Diagonal of Heptagon=Side of Heptagon/(2*sin(((pi/2))/7))
Long Diagonal of Heptagon=(Short Diagonal of Heptagon/(2*cos(pi/7)))/(2*sin(((pi/2))/7))
Long Diagonal of Heptagon=(Height of Heptagon*tan(((pi/2))/7))/sin(((pi/2))/7)

Can the Long Diagonal of Heptagon given Inradius be negative?

No, the Long Diagonal of Heptagon given Inradius, measured in Length cannot be negative.

Which unit is used to measure Long Diagonal of Heptagon given Inradius?

Long Diagonal of Heptagon given Inradius is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Long Diagonal of Heptagon given Inradius can be measured.

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