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Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Formula

GoLoad Current using Line Losses (2 Phase 4 Wire US) Formula

GoLoad Current using Area of X-Section (2 Phase 4 Wire US) Formula

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Current Underground AC is defined as the current flowing through the overhead ac supply wire. Check FAQs

I = \sqrt{V \cdot \frac{P loss}{4 \cdot ρ \cdot (L^{2})}}

I - Current Underground AC?V - Volume Of Conductor?P_loss - Line Losses?ρ - Resistivity?L - Length of Underground AC Wire?

Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Example

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Here is how the Load Current using Volume of Conductor Material (2 Phase 4 Wire US) equation looks like with Values.

Here is how the Load Current using Volume of Conductor Material (2 Phase 4 Wire US) equation looks like with Units.

Here is how the Load Current using Volume of Conductor Material (2 Phase 4 Wire US) equation looks like.

63.9537 = \sqrt{60 \cdot \frac{2.67}{4 \cdot 1.7E-5 \cdot (24^{2})}}

63.9537A = \sqrt{60m³ \cdot \frac{2.67W}{4 \cdot 1.7E-5Ω*m \cdot ({24m}^{2})}}

63.9537 = \sqrt{60 \cdot \frac{2.67}{4 \cdot 1.7E-5 \cdot (24^{2})}}

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Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Solution

Follow our step by step solution on how to calculate Load Current using Volume of Conductor Material (2 Phase 4 Wire US)?

FIRST Step Consider the formula

I = \sqrt{V \cdot \frac{P loss}{4 \cdot ρ \cdot (L^{2})}}

Next Step Substitute values of Variables

∴

I = \sqrt{60m³ \cdot \frac{2.67W}{4 \cdot 1.7E-5Ω*m \cdot ({24m}^{2})}}

Next Step Prepare to Evaluate

∴

I = \sqrt{60 \cdot \frac{2.67}{4 \cdot 1.7E-5 \cdot (24^{2})}}

Next Step Evaluate

∴

I = 63.9536826884251A

LAST Step Rounding Answer

∴

I = 63.9537A

Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Formula Elements

Variables

Functions

Current Underground AC

Current Underground AC is defined as the current flowing through the overhead ac supply wire.

Symbol: I

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Current Underground AC

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume Of Conductor

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Current Underground AC

Go Load Current using Line Losses (2 Phase 4 Wire US)

I = \sqrt{\frac{P loss}{2} \cdot R}

Go Load Current using Area of X-Section (2 Phase 4 Wire US)

I = \sqrt{P loss \cdot \frac{A}{2 \cdot ρ \cdot L}}

Go Load Current (2 Phase 4 Wire US)

I = \sqrt{2} \cdot \frac{P}{V m \cdot \cos (Φ)}

Other formulas in Current and Voltage category

Go Maximum Voltage using Area of X-Section (2 Phase 4 Wire US)

V m = (2 \cdot \frac{P}{\cos (Φ)}) \cdot \sqrt{ρ \cdot \frac{L}{P loss \cdot A}}

Go RMS Voltage using Area of X-Section (2 Phase 4 Wire US)

V rms = (\frac{P}{\cos (Φ)}) \cdot \sqrt{ρ \cdot \frac{L}{P loss \cdot A}}

Go Maximum Voltage using Line Losses (2 Phase 4 Wire US)

V m = (2 \cdot \frac{P}{\cos (Φ)}) \cdot \sqrt{\frac{R}{P loss}}

Go RMS Voltage using Line Losses (2 Phase 4 Wire US)

V rms = (\frac{P}{\cos (Φ)}) \cdot \sqrt{\frac{R}{P loss}}

How to Evaluate Load Current using Volume of Conductor Material (2 Phase 4 Wire US)?

Load Current using Volume of Conductor Material (2 Phase 4 Wire US) evaluator uses Current Underground AC = sqrt(Volume Of Conductor*Line Losses/(4*Resistivity*(Length of Underground AC Wire^2))) to evaluate the Current Underground AC, The Load Current using Volume of Conductor Material (2 phase 4 wire US) formula is defined as the current that flows into the load of the two-phase four-wire underground system. Current Underground AC is denoted by I symbol.

How to evaluate Load Current using Volume of Conductor Material (2 Phase 4 Wire US) using this online evaluator? To use this online evaluator for Load Current using Volume of Conductor Material (2 Phase 4 Wire US), enter Volume Of Conductor (V), Line Losses (P_loss), Resistivity (ρ) & Length of Underground AC Wire (L) and hit the calculate button.

FAQs on Load Current using Volume of Conductor Material (2 Phase 4 Wire US)

What is the formula to find Load Current using Volume of Conductor Material (2 Phase 4 Wire US)?

The formula of Load Current using Volume of Conductor Material (2 Phase 4 Wire US) is expressed as Current Underground AC = sqrt(Volume Of Conductor*Line Losses/(4*Resistivity*(Length of Underground AC Wire^2))). Here is an example- 63.95368 = sqrt(60*2.67/(4*1.7E-05*(24^2))).

How to calculate Load Current using Volume of Conductor Material (2 Phase 4 Wire US)?

With Volume Of Conductor (V), Line Losses (P_loss), Resistivity (ρ) & Length of Underground AC Wire (L) we can find Load Current using Volume of Conductor Material (2 Phase 4 Wire US) using the formula - Current Underground AC = sqrt(Volume Of Conductor*Line Losses/(4*Resistivity*(Length of Underground AC Wire^2))). This formula also uses Square Root (sqrt) function(s).

What are the other ways to Calculate Current Underground AC?

Here are the different ways to Calculate Current Underground AC-

Current Underground AC=sqrt(Line Losses/2*Resistance Underground AC)
Current Underground AC=sqrt(Line Losses*Area of Underground AC Wire/(2*Resistivity*Length of Underground AC Wire))
Current Underground AC=sqrt(2)*Power Transmitted/(Maximum Voltage Underground AC*cos(Phase Difference))

Can the Load Current using Volume of Conductor Material (2 Phase 4 Wire US) be negative?

Yes, the Load Current using Volume of Conductor Material (2 Phase 4 Wire US), measured in Electric Current can be negative.

Which unit is used to measure Load Current using Volume of Conductor Material (2 Phase 4 Wire US)?

Load Current using Volume of Conductor Material (2 Phase 4 Wire US) is usually measured using the Ampere[A] for Electric Current. Milliampere[A], Microampere[A], Centiampere[A] are the few other units in which Load Current using Volume of Conductor Material (2 Phase 4 Wire US) can be measured.

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Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Formula

​GoLoad Current using Line Losses (2 Phase 4 Wire US) Formula

​GoLoad Current using Area of X-Section (2 Phase 4 Wire US) Formula

Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Example

Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Solution

Load Current using Volume of Conductor Material (2 Phase 4 Wire US) Formula Elements

Other Formulas to find Current Underground AC

Other formulas in Current and Voltage category

How to Evaluate Load Current using Volume of Conductor Material (2 Phase 4 Wire US)?

FAQs on Load Current using Volume of Conductor Material (2 Phase 4 Wire US)

Variable Name

GoLoad Current using Line Losses (2 Phase 4 Wire US) Formula

GoLoad Current using Area of X-Section (2 Phase 4 Wire US) Formula