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Load Current using Line Losses (1-Phase 2-Wire US) Formula

GoLoad Current (1-Phase 2-Wire US) Formula

GoLoad Current using Resistance (1-Phase 2-Wire US) Formula

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Current Underground AC is defined as the current flowing through the overhead ac supply wire. Check FAQs

I = \sqrt{P loss \cdot \frac{A}{2 \cdot ρ \cdot L}}

I - Current Underground AC?P_loss - Line Losses?A - Area of Underground AC Wire?ρ - Resistivity?L - Length of Underground AC Wire?

Load Current using Line Losses (1-Phase 2-Wire US) Example

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Here is how the Load Current using Line Losses (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Load Current using Line Losses (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Load Current using Line Losses (1-Phase 2-Wire US) equation looks like.

64.7166 = \sqrt{2.67 \cdot \frac{1.28}{2 \cdot 1.7E-5 \cdot 24}}

64.7166A = \sqrt{2.67W \cdot \frac{1.28m²}{2 \cdot 1.7E-5Ω*m \cdot 24m}}

64.7166 = \sqrt{2.67 \cdot \frac{1.28}{2 \cdot 1.7E-5 \cdot 24}}

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Load Current using Line Losses (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Load Current using Line Losses (1-Phase 2-Wire US)?

FIRST Step Consider the formula

I = \sqrt{P loss \cdot \frac{A}{2 \cdot ρ \cdot L}}

Next Step Substitute values of Variables

∴

I = \sqrt{2.67W \cdot \frac{1.28m²}{2 \cdot 1.7E-5Ω*m \cdot 24m}}

Next Step Prepare to Evaluate

∴

I = \sqrt{2.67 \cdot \frac{1.28}{2 \cdot 1.7E-5 \cdot 24}}

Next Step Evaluate

∴

I = 64.7165766563533A

LAST Step Rounding Answer

∴

I = 64.7166A

Load Current using Line Losses (1-Phase 2-Wire US) Formula Elements

Variables

Functions

Current Underground AC

Current Underground AC is defined as the current flowing through the overhead ac supply wire.

Symbol: I

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Current Underground AC

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Area of Underground AC Wire

Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.

Symbol: A

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Area of Underground AC Wire

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Current Underground AC

Go Load Current (1-Phase 2-Wire US)

I = P \cdot \frac{\sqrt{2}}{V m \cdot \cos (Φ)}

Go Load Current using Resistance (1-Phase 2-Wire US)

I = \sqrt{\frac{P loss}{2 \cdot R}}

Go Load Current using Constant (1-Phase 2-Wire US)

I = \sqrt{K \cdot \frac{P loss}{2 \cdot ρ \cdot {(L \cdot \cos (Φ))}^{2}}}

Other formulas in Current and Voltage category

Go RMS Voltage(1-Phase 2-Wire US)

V rms = \frac{V m}{\sqrt{2}}

Go Maximum Voltage using Area of X-Section (1-Phase 2-Wire US)

V m = \sqrt{\frac{4 \cdot L \cdot ρ \cdot (P^{2})}{A \cdot P loss \cdot {(\cos (Φ))}^{2}}}

Go Maximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US)

V m = \sqrt{8 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot V \cdot {(\cos (Φ))}^{2}}}

Go RMS Voltage using Area of X-Section (1-Phase 2-Wire US)

V rms = \sqrt{\frac{2 \cdot L \cdot ρ \cdot (P^{2})}{A \cdot P loss \cdot ({(\cos (Φ))}^{2})}}

How to Evaluate Load Current using Line Losses (1-Phase 2-Wire US)?

Load Current using Line Losses (1-Phase 2-Wire US) evaluator uses Current Underground AC = sqrt(Line Losses*Area of Underground AC Wire/(2*Resistivity*Length of Underground AC Wire)) to evaluate the Current Underground AC, The Load Current using Line Losses (1-Phase 2-Wire US) formula is defined as the current that flows into the load of the one-phase two-wire underground system. Current Underground AC is denoted by I symbol.

How to evaluate Load Current using Line Losses (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Load Current using Line Losses (1-Phase 2-Wire US), enter Line Losses (P_loss), Area of Underground AC Wire (A), Resistivity (ρ) & Length of Underground AC Wire (L) and hit the calculate button.

FAQs on Load Current using Line Losses (1-Phase 2-Wire US)

What is the formula to find Load Current using Line Losses (1-Phase 2-Wire US)?

The formula of Load Current using Line Losses (1-Phase 2-Wire US) is expressed as Current Underground AC = sqrt(Line Losses*Area of Underground AC Wire/(2*Resistivity*Length of Underground AC Wire)). Here is an example- 64.71658 = sqrt(2.67*1.28/(2*1.7E-05*24)).

How to calculate Load Current using Line Losses (1-Phase 2-Wire US)?

With Line Losses (P_loss), Area of Underground AC Wire (A), Resistivity (ρ) & Length of Underground AC Wire (L) we can find Load Current using Line Losses (1-Phase 2-Wire US) using the formula - Current Underground AC = sqrt(Line Losses*Area of Underground AC Wire/(2*Resistivity*Length of Underground AC Wire)). This formula also uses Square Root (sqrt) function(s).

What are the other ways to Calculate Current Underground AC?

Here are the different ways to Calculate Current Underground AC-

Current Underground AC=Power Transmitted*sqrt(2)/(Maximum Voltage Underground AC*cos(Phase Difference))
Current Underground AC=sqrt(Line Losses/(2*Resistance Underground AC))
Current Underground AC=sqrt(Constant Underground AC*Line Losses/(2*Resistivity*(Length of Underground AC Wire*cos(Phase Difference))^2))

Can the Load Current using Line Losses (1-Phase 2-Wire US) be negative?

Yes, the Load Current using Line Losses (1-Phase 2-Wire US), measured in Electric Current can be negative.

Which unit is used to measure Load Current using Line Losses (1-Phase 2-Wire US)?

Load Current using Line Losses (1-Phase 2-Wire US) is usually measured using the Ampere[A] for Electric Current. Milliampere[A], Microampere[A], Centiampere[A] are the few other units in which Load Current using Line Losses (1-Phase 2-Wire US) can be measured.

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Load Current using Line Losses (1-Phase 2-Wire US) Formula

​GoLoad Current (1-Phase 2-Wire US) Formula

​GoLoad Current using Resistance (1-Phase 2-Wire US) Formula

Load Current using Line Losses (1-Phase 2-Wire US) Example

Load Current using Line Losses (1-Phase 2-Wire US) Solution

Load Current using Line Losses (1-Phase 2-Wire US) Formula Elements

Other Formulas to find Current Underground AC

Other formulas in Current and Voltage category

How to Evaluate Load Current using Line Losses (1-Phase 2-Wire US)?

FAQs on Load Current using Line Losses (1-Phase 2-Wire US)

Variable Name

GoLoad Current (1-Phase 2-Wire US) Formula

GoLoad Current using Resistance (1-Phase 2-Wire US) Formula