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Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) Formula

GoLine Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) Formula

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Line Losses is defined as the losses that are produced in the line. Check FAQs

P line = 4 \cdot ρ \cdot \frac{P^{2} \cdot l^{2}}{{V m}^{2} \cdot V}

P_line - Line Losses?ρ - Resistivity?P - Power Transmitted?l - Length of Wire DC?V_m - Maximum Voltage?V - Volume Of Conductor?

Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) Example

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Here is how the Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) equation looks like with Values.

Here is how the Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) equation looks like with Units.

Here is how the Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) equation looks like.

0.0005 = 4 \cdot 1.7E-5 \cdot \frac{300^{2} \cdot {3.2}^{2}}{60^{2} \cdot 35}

0.0005W = 4 \cdot 1.7E-5Ω*m \cdot \frac{{300W}^{2} \cdot {3.2m}^{2}}{{60V}^{2} \cdot 35m³}

0.0005 = 4 \cdot 1.7E-5 \cdot \frac{300^{2} \cdot {3.2}^{2}}{60^{2} \cdot 35}

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Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) Solution

Follow our step by step solution on how to calculate Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)?

FIRST Step Consider the formula

P line = 4 \cdot ρ \cdot \frac{P^{2} \cdot l^{2}}{{V m}^{2} \cdot V}

Next Step Substitute values of Variables

∴

P line = 4 \cdot 1.7E-5Ω*m \cdot \frac{{300W}^{2} \cdot {3.2m}^{2}}{{60V}^{2} \cdot 35m³}

Next Step Prepare to Evaluate

∴

P line = 4 \cdot 1.7E-5 \cdot \frac{300^{2} \cdot {3.2}^{2}}{60^{2} \cdot 35}

Next Step Evaluate

∴

P line = 0.000497371428571429W

LAST Step Rounding Answer

∴

P line = 0.0005W

Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) Formula Elements

Variables

Line Losses

Line Losses is defined as the losses that are produced in the line.

Symbol: P_line

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value should be greater than 0.

Formulas to find Power Transmitted

Length of Wire DC

Length of Wire DC is the measurement or extent of something from end to end.

Symbol: l

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Wire DC

Maximum Voltage

Maximum Voltage the highest voltage rating for electrical devices.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value can be positive or negative.

Formulas to find Volume Of Conductor

Other Formulas to find Line Losses

Go Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US)

P line = \frac{2 \cdot ρ \cdot l \cdot (P^{2})}{A \cdot ({V m}^{2} \cdot {\cos (θ)}^{2})}

Other formulas in Wire Parameters category

Go Length using Area of X-Section (2-Wire Mid-Point Earthed DC US)

l = A \cdot P line \cdot \frac{{V m}^{2}}{2 \cdot (P^{2}) \cdot ρ}

Go Length using Volume of Conductor Material (2-Wire Mid-Point DC US)

l = \sqrt{\frac{V \cdot P line}{4 \cdot ({C 1}^{2}) \cdot (ρ)}}

Go Area using Volume of Conductor Material (2-Wire Mid-Point DC US)

A = \frac{V}{2 \cdot l}

Go Volume of Conductor Material (2-Wire Mid-Point DC US)

V = 4 \cdot ρ \cdot (P^{2}) \cdot \frac{l^{2}}{P line \cdot ({V m}^{2})}

How to Evaluate Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)?

Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) evaluator uses Line Losses = 4*Resistivity*(Power Transmitted^2*Length of Wire DC^2)/(Maximum Voltage^2*Volume Of Conductor) to evaluate the Line Losses, The Line Losses using Volume of Conductor Material (2-wire Mid-point DC US) formula is defined as the loss of electric energy due to the heating of line wires by the current. Line Losses is denoted by P_line symbol.

How to evaluate Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) using this online evaluator? To use this online evaluator for Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US), enter Resistivity (ρ), Power Transmitted (P), Length of Wire DC (l), Maximum Voltage (V_m) & Volume Of Conductor (V) and hit the calculate button.

FAQs on Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)

What is the formula to find Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)?

The formula of Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) is expressed as Line Losses = 4*Resistivity*(Power Transmitted^2*Length of Wire DC^2)/(Maximum Voltage^2*Volume Of Conductor). Here is an example- 0.000497 = 4*1.7E-05*(300^2*3.2^2)/(60^2*35).

How to calculate Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)?

With Resistivity (ρ), Power Transmitted (P), Length of Wire DC (l), Maximum Voltage (V_m) & Volume Of Conductor (V) we can find Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) using the formula - Line Losses = 4*Resistivity*(Power Transmitted^2*Length of Wire DC^2)/(Maximum Voltage^2*Volume Of Conductor).

What are the other ways to Calculate Line Losses?

Here are the different ways to Calculate Line Losses-

Line Losses=(2*Resistivity*Length of Wire DC*(Power Transmitted^2))/(Area of underground dc wire*(Maximum Voltage^2*cos(Theta)^2))

Can the Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) be negative?

Yes, the Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US), measured in Power can be negative.

Which unit is used to measure Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)?

Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) is usually measured using the Watt[W] for Power. Kilowatt[W], Milliwatt[W], Microwatt[W] are the few other units in which Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) can be measured.

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Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) Formula

​GoLine Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) Formula

Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) Example

Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) Solution

Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US) Formula Elements

Other Formulas to find Line Losses

Other formulas in Wire Parameters category

How to Evaluate Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)?

FAQs on Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)

Variable Name

GoLine Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) Formula