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Line Losses using Resistance (1-Phase 2-Wire US) Formula

GoLine Losses (1-Phase 2-Wire US) Formula

GoLine Losses using Area of X-Section (1-Phase 2-Wire US) Formula

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Line Losses is defined as the total losses occurring in an Underground AC line when in use. Check FAQs

P loss = 2 \cdot (I^{2}) \cdot R

P_loss - Line Losses?I - Current Underground AC?R - Resistance Underground AC?

Line Losses using Resistance (1-Phase 2-Wire US) Example

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Here is how the Line Losses using Resistance (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Line Losses using Resistance (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Line Losses using Resistance (1-Phase 2-Wire US) equation looks like.

810 = 2 \cdot (9^{2}) \cdot 5

810W = 2 \cdot ({9A}^{2}) \cdot 5Ω

810 = 2 \cdot (9^{2}) \cdot 5

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Line Losses using Resistance (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Line Losses using Resistance (1-Phase 2-Wire US)?

FIRST Step Consider the formula

P loss = 2 \cdot (I^{2}) \cdot R

Next Step Substitute values of Variables

∴

P loss = 2 \cdot ({9A}^{2}) \cdot 5Ω

Next Step Prepare to Evaluate

∴

P loss = 2 \cdot (9^{2}) \cdot 5

LAST Step Evaluate

∴

P loss = 810W

Line Losses using Resistance (1-Phase 2-Wire US) Formula Elements

Variables

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Current Underground AC

Current Underground AC is defined as the current flowing through the overhead ac supply wire.

Symbol: I

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Current Underground AC

Resistance Underground AC

Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it.

Symbol: R

Measurement: Electric ResistanceUnit: Ω

Note: Value can be positive or negative.

Formulas to find Resistance Underground AC

Other Formulas to find Line Losses

Go Line Losses (1-Phase 2-Wire US)

P loss = 2 \cdot (I^{2}) \cdot R

Go Line Losses using Area of X-Section (1-Phase 2-Wire US)

P loss = \frac{4 \cdot L \cdot ρ \cdot (P^{2})}{A \cdot ({V m}^{2}) \cdot ({(\cos (Φ))}^{2})}

Go Line Losses using Volume of Conductor Material (1-Phase 2-Wire US)

P loss = 8 \cdot {(P)}^{2} \cdot ρ \cdot \frac{{(L)}^{2}}{{(V m \cdot \cos (Φ))}^{2} \cdot V}

Go Line Losses using Load Current (1-Phase 2-Wire US)

P loss = 2 \cdot R \cdot {(I)}^{2}

How to Evaluate Line Losses using Resistance (1-Phase 2-Wire US)?

Line Losses using Resistance (1-Phase 2-Wire US) evaluator uses Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC to evaluate the Line Losses, The Line Losses using Resistance (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current. Line Losses is denoted by P_loss symbol.

How to evaluate Line Losses using Resistance (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Line Losses using Resistance (1-Phase 2-Wire US), enter Current Underground AC (I) & Resistance Underground AC (R) and hit the calculate button.

FAQs on Line Losses using Resistance (1-Phase 2-Wire US)

What is the formula to find Line Losses using Resistance (1-Phase 2-Wire US)?

The formula of Line Losses using Resistance (1-Phase 2-Wire US) is expressed as Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC. Here is an example- 810 = 2*(9^2)*5.

How to calculate Line Losses using Resistance (1-Phase 2-Wire US)?

With Current Underground AC (I) & Resistance Underground AC (R) we can find Line Losses using Resistance (1-Phase 2-Wire US) using the formula - Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC.

What are the other ways to Calculate Line Losses?

Here are the different ways to Calculate Line Losses-

Line Losses=2*(Current Underground AC^2)*Resistance Underground AC
Line Losses=(4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*((cos(Phase Difference))^2))
Line Losses=8*(Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)

Can the Line Losses using Resistance (1-Phase 2-Wire US) be negative?

Yes, the Line Losses using Resistance (1-Phase 2-Wire US), measured in Power can be negative.

Which unit is used to measure Line Losses using Resistance (1-Phase 2-Wire US)?

Line Losses using Resistance (1-Phase 2-Wire US) is usually measured using the Watt[W] for Power. Kilowatt[W], Milliwatt[W], Microwatt[W] are the few other units in which Line Losses using Resistance (1-Phase 2-Wire US) can be measured.

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Line Losses using Resistance (1-Phase 2-Wire US) Formula

​GoLine Losses (1-Phase 2-Wire US) Formula

​GoLine Losses using Area of X-Section (1-Phase 2-Wire US) Formula

Line Losses using Resistance (1-Phase 2-Wire US) Example

Line Losses using Resistance (1-Phase 2-Wire US) Solution

Line Losses using Resistance (1-Phase 2-Wire US) Formula Elements

Other Formulas to find Line Losses

How to Evaluate Line Losses using Resistance (1-Phase 2-Wire US)?

FAQs on Line Losses using Resistance (1-Phase 2-Wire US)

Variable Name

GoLine Losses (1-Phase 2-Wire US) Formula

GoLine Losses using Area of X-Section (1-Phase 2-Wire US) Formula