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Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) Formula

GoLength of Shaft in given Static Deflection (Shaft Fixed, Uniformly Distributed Load) Formula

GoLength of Shaft given Natural Circular Frequency (Shaft Fixed, Uniformly Distributed Load) Formula

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Length of shaft is the distance between two ends of shaft. Check FAQs

L shaft = {3.573}^{2} \cdot {(\frac{E \cdot I shaft \cdot g}{w \cdot f^{2}})}^{\frac{1}{4}}

L_shaft - Length of Shaft?E - Young's Modulus?I_shaft - Moment of inertia of shaft?g - Acceleration due to Gravity?w - Load per unit length?f - Frequency?

Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) Example

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Here is how the Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) equation looks like with Values.

Here is how the Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) equation looks like with Units.

Here is how the Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) equation looks like.

5572.2631 = {3.573}^{2} \cdot {(\frac{15 \cdot 6 \cdot 9.8}{3 \cdot 90^{2}})}^{\frac{1}{4}}

5572.2631mm = {3.573}^{2} \cdot {(\frac{15N/m \cdot 6kg·m² \cdot 9.8m/s²}{3 \cdot {90Hz}^{2}})}^{\frac{1}{4}}

5572.2631 = {3.573}^{2} \cdot {(\frac{15 \cdot 6 \cdot 9.8}{3 \cdot 90^{2}})}^{\frac{1}{4}}

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Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) Solution

Follow our step by step solution on how to calculate Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load)?

FIRST Step Consider the formula

L shaft = {3.573}^{2} \cdot {(\frac{E \cdot I shaft \cdot g}{w \cdot f^{2}})}^{\frac{1}{4}}

Next Step Substitute values of Variables

∴

L shaft = {3.573}^{2} \cdot {(\frac{15N/m \cdot 6kg·m² \cdot 9.8m/s²}{3 \cdot {90Hz}^{2}})}^{\frac{1}{4}}

Next Step Prepare to Evaluate

∴

L shaft = {3.573}^{2} \cdot {(\frac{15 \cdot 6 \cdot 9.8}{3 \cdot 90^{2}})}^{\frac{1}{4}}

Next Step Evaluate

∴

L shaft = 5.57226305383515m

Next Step Convert to Output's Unit

∴

L shaft = 5572.26305383515mm

LAST Step Rounding Answer

∴

L shaft = 5572.2631mm

Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) Formula Elements

Variables

Length of Shaft

Length of shaft is the distance between two ends of shaft.

Symbol: L_shaft

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Length of Shaft

Young's Modulus

Young's Modulus is a mechanical property of linear elastic solid substances. It describes the relationship between longitudinal stress and longitudinal strain.

Symbol: E

Measurement: Stiffness ConstantUnit: N/m

Note: Value should be greater than 0.

Formulas to find Young's Modulus

Moment of inertia of shaft

Moment of inertia of shaft can be calculated by taking the distance of each particle from the axis of rotation.

Symbol: I_shaft

Measurement: Moment of InertiaUnit: kg·m²

Note: Value should be greater than 0.

Formulas to find Moment of inertia of shaft

Acceleration due to Gravity

Acceleration due to Gravity is acceleration gained by an object because of gravitational force.

Symbol: g

Measurement: AccelerationUnit: m/s²

Note: Value should be greater than 0.

Formulas to find Acceleration due to Gravity

Load per unit length

Load per unit length is the distributed load which is spread over a surface or line.

Symbol: w

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Load per unit length

Frequency

Frequency refers to the number of occurrences of a periodic event per time and is measured in cycles/second.

Symbol: f

Measurement: FrequencyUnit: Hz

Note: Value can be positive or negative.

Formulas to find Frequency

Other Formulas to find Length of Shaft

Go Length of Shaft in given Static Deflection (Shaft Fixed, Uniformly Distributed Load)

L shaft = {(\frac{δ \cdot 384 \cdot E \cdot I shaft}{w})}^{\frac{1}{4}}

Go Length of Shaft given Natural Circular Frequency (Shaft Fixed, Uniformly Distributed Load)

L shaft = {(\frac{504 \cdot E \cdot I shaft \cdot g}{w \cdot {ω n}^{2}})}^{\frac{1}{4}}

Other formulas in Shaft Fixed at Both Ends Carrying a Uniformly Distributed Load category

Go Circular Frequency given Static Deflection (Shaft Fixed, Uniformly Distributed Load)

ω n = \frac{2 \cdot π \cdot 0.571}{\sqrt{δ}}

Go Static Deflection given Natural Frequency (Shaft Fixed, Uniformly Distributed Load)

δ = {(\frac{0.571}{f})}^{2}

Go Natural Frequency given Static Deflection (Shaft Fixed, Uniformly Distributed Load)

f = \frac{0.571}{\sqrt{δ}}

Go M.I of Shaft given Static Deflection for Fixed Shaft and Uniformly Distributed Load

I shaft = \frac{w \cdot {L shaft}^{4}}{384 \cdot E \cdot δ}

How to Evaluate Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load)?

Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) evaluator uses Length of Shaft = 3.573^2*((Young's Modulus*Moment of inertia of shaft*Acceleration due to Gravity)/(Load per unit length*Frequency^2))^(1/4) to evaluate the Length of Shaft, Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) formula is defined as the calculation that determines the length of a shaft under fixed and uniformly distributed load conditions, considering the natural frequency of free transverse vibrations, modulus of elasticity, moment of inertia, weight, and gravity. Length of Shaft is denoted by L_shaft symbol.

How to evaluate Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) using this online evaluator? To use this online evaluator for Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load), enter Young's Modulus (E), Moment of inertia of shaft (I_shaft), Acceleration due to Gravity (g), Load per unit length (w) & Frequency (f) and hit the calculate button.

FAQs on Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load)

What is the formula to find Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load)?

The formula of Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) is expressed as Length of Shaft = 3.573^2*((Young's Modulus*Moment of inertia of shaft*Acceleration due to Gravity)/(Load per unit length*Frequency^2))^(1/4). Here is an example- 5.6E+6 = 3.573^2*((15*6*9.8)/(3*90^2))^(1/4).

How to calculate Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load)?

With Young's Modulus (E), Moment of inertia of shaft (I_shaft), Acceleration due to Gravity (g), Load per unit length (w) & Frequency (f) we can find Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) using the formula - Length of Shaft = 3.573^2*((Young's Modulus*Moment of inertia of shaft*Acceleration due to Gravity)/(Load per unit length*Frequency^2))^(1/4).

What are the other ways to Calculate Length of Shaft?

Here are the different ways to Calculate Length of Shaft-

Length of Shaft=((Static Deflection*384*Young's Modulus*Moment of inertia of shaft)/(Load per unit length))^(1/4)
Length of Shaft=((504*Young's Modulus*Moment of inertia of shaft*Acceleration due to Gravity)/(Load per unit length*Natural Circular Frequency^2))^(1/4)

Can the Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) be negative?

No, the Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load), measured in Length cannot be negative.

Which unit is used to measure Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load)?

Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) is usually measured using the Millimeter[mm] for Length. Meter[mm], Kilometer[mm], Decimeter[mm] are the few other units in which Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) can be measured.

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Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) Formula

​GoLength of Shaft in given Static Deflection (Shaft Fixed, Uniformly Distributed Load) Formula

​GoLength of Shaft given Natural Circular Frequency (Shaft Fixed, Uniformly Distributed Load) Formula

Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) Example

Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) Solution

Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load) Formula Elements

Other Formulas to find Length of Shaft

Other formulas in Shaft Fixed at Both Ends Carrying a Uniformly Distributed Load category

How to Evaluate Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load)?

FAQs on Length of Shaft given Natural Frequency (Shaft Fixed, Uniformly Distributed Load)

Variable Name

GoLength of Shaft in given Static Deflection (Shaft Fixed, Uniformly Distributed Load) Formula

GoLength of Shaft given Natural Circular Frequency (Shaft Fixed, Uniformly Distributed Load) Formula