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Jet Ratio of Hydroelectric Power Plant Formula

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Jet ratio (m) is the ratio of Diameter of Pelton wheel to the diameter of the jet of water. Check FAQs

J = \frac{D b}{D n}

J - Jet Ratio?D_b - Bucket Circle Diameter?D_n - Nozzle Diameter?

Jet Ratio of Hydroelectric Power Plant Example

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Here is how the Jet Ratio of Hydroelectric Power Plant equation looks like with Values.

Here is how the Jet Ratio of Hydroelectric Power Plant equation looks like with Units.

Here is how the Jet Ratio of Hydroelectric Power Plant equation looks like.

15 = \frac{1}{0}

15 = \frac{1m}{0m}

15 = \frac{1}{0}

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Jet Ratio of Hydroelectric Power Plant Solution

Follow our step by step solution on how to calculate Jet Ratio of Hydroelectric Power Plant?

FIRST Step Consider the formula

J = \frac{D b}{D n}

Next Step Substitute values of Variables

∴

J = \frac{1m}{0m}

Next Step Prepare to Evaluate

∴

J = \frac{1}{0}

LAST Step Evaluate

∴

J = 15

Jet Ratio of Hydroelectric Power Plant Formula Elements

Variables

Jet Ratio

Jet ratio (m) is the ratio of Diameter of Pelton wheel to the diameter of the jet of water.

Symbol: J

Measurement: NAUnit: Unitless

Note: Value should be between 9.999 to 24.001.

Formulas to find Jet Ratio

Bucket Circle Diameter

Bucket circle diameter is the diameter of the circle that is formed by the tips of the turbine blades or buckets as they rotate.

Symbol: D_b

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Bucket Circle Diameter

Nozzle Diameter

Nozzle diameter is an important parameter in hydroelectric power plants as it affects the flow rate of water through the turbine and ultimately determines the amount of power that can be generated.

Symbol: D_n

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Nozzle Diameter

Other formulas in Hydroelectric Power Plant category

Go Energy Produced by Hydroelectric Power Plant

E = [g] \cdot ρ w \cdot Q \cdot H \cdot η \cdot t

Go Energy Produced by Hydroelectric Power Plant given Power

E = P h \cdot η \cdot t

Go Head or Height of Fall of Water given Power

H = \frac{P h}{[g] \cdot ρ w \cdot Q}

Go Flow Rate of Water given Power

Q = \frac{P h}{[g] \cdot ρ w \cdot H}

How to Evaluate Jet Ratio of Hydroelectric Power Plant?

Jet Ratio of Hydroelectric Power Plant evaluator uses Jet Ratio = Bucket Circle Diameter/Nozzle Diameter to evaluate the Jet Ratio, The Jet Ratio of Hydroelectric Power Plant formula is defined as the ratio of bucket diameter to nozzle diameter. Jet Ratio is denoted by J symbol.

How to evaluate Jet Ratio of Hydroelectric Power Plant using this online evaluator? To use this online evaluator for Jet Ratio of Hydroelectric Power Plant, enter Bucket Circle Diameter (D_b) & Nozzle Diameter (D_n) and hit the calculate button.

FAQs on Jet Ratio of Hydroelectric Power Plant

What is the formula to find Jet Ratio of Hydroelectric Power Plant?

The formula of Jet Ratio of Hydroelectric Power Plant is expressed as Jet Ratio = Bucket Circle Diameter/Nozzle Diameter. Here is an example- 15 = 1.23/0.082.

How to calculate Jet Ratio of Hydroelectric Power Plant?

With Bucket Circle Diameter (D_b) & Nozzle Diameter (D_n) we can find Jet Ratio of Hydroelectric Power Plant using the formula - Jet Ratio = Bucket Circle Diameter/Nozzle Diameter.

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