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Interplanar Distance in Rhombohedral Crystal Lattice Formula

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Interplanar Spacing is the distance between adjacent and parallel planes of the crystal. Check FAQs

d = \sqrt{\frac{1}{\frac{(((h^{2}) + (k^{2}) + (l^{2})) \cdot ({\sin (α)}^{2})) + (((h \cdot k) + (k \cdot l) + (h \cdot l)) \cdot 2 \cdot ({\cos (α)}^{2})) - \cos (α)}{{a lattice}^{2} \cdot (1 - (3 \cdot ({\cos (α)}^{2})) + (2 \cdot ({\cos (α)}^{3})))}}}

d - Interplanar Spacing?h - Miller Index along x-axis?k - Miller Index along y-axis?l - Miller Index along z-axis?α - Lattice parameter alpha?a_lattice - Lattice Constant a?

Interplanar Distance in Rhombohedral Crystal Lattice Example

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Here is how the Interplanar Distance in Rhombohedral Crystal Lattice equation looks like with Values.

Here is how the Interplanar Distance in Rhombohedral Crystal Lattice equation looks like with Units.

Here is how the Interplanar Distance in Rhombohedral Crystal Lattice equation looks like.

0.0173 = \sqrt{\frac{1}{\frac{(((9^{2}) + (4^{2}) + (11^{2})) \cdot ({\sin (30)}^{2})) + (((9 \cdot 4) + (4 \cdot 11) + (9 \cdot 11)) \cdot 2 \cdot ({\cos (30)}^{2})) - \cos (30)}{14^{2} \cdot (1 - (3 \cdot ({\cos (30)}^{2})) + (2 \cdot ({\cos (30)}^{3})))}}}

0.0173nm = \sqrt{\frac{1}{\frac{(((9^{2}) + (4^{2}) + (11^{2})) \cdot ({\sin (30°)}^{2})) + (((9 \cdot 4) + (4 \cdot 11) + (9 \cdot 11)) \cdot 2 \cdot ({\cos (30°)}^{2})) - \cos (30°)}{{14A}^{2} \cdot (1 - (3 \cdot ({\cos (30°)}^{2})) + (2 \cdot ({\cos (30°)}^{3})))}}}

0.0173 = \sqrt{\frac{1}{\frac{(((9^{2}) + (4^{2}) + (11^{2})) \cdot ({\sin (30)}^{2})) + (((9 \cdot 4) + (4 \cdot 11) + (9 \cdot 11)) \cdot 2 \cdot ({\cos (30)}^{2})) - \cos (30)}{14^{2} \cdot (1 - (3 \cdot ({\cos (30)}^{2})) + (2 \cdot ({\cos (30)}^{3})))}}}

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Inter Planar Distance and Inter Planar Angle » fx Interplanar Distance in Rhombohedral Crystal Lattice

Interplanar Distance in Rhombohedral Crystal Lattice Solution

Follow our step by step solution on how to calculate Interplanar Distance in Rhombohedral Crystal Lattice?

FIRST Step Consider the formula

d = \sqrt{\frac{1}{\frac{(((h^{2}) + (k^{2}) + (l^{2})) \cdot ({\sin (α)}^{2})) + (((h \cdot k) + (k \cdot l) + (h \cdot l)) \cdot 2 \cdot ({\cos (α)}^{2})) - \cos (α)}{{a lattice}^{2} \cdot (1 - (3 \cdot ({\cos (α)}^{2})) + (2 \cdot ({\cos (α)}^{3})))}}}

Next Step Substitute values of Variables

∴

d = \sqrt{\frac{1}{\frac{(((9^{2}) + (4^{2}) + (11^{2})) \cdot ({\sin (30°)}^{2})) + (((9 \cdot 4) + (4 \cdot 11) + (9 \cdot 11)) \cdot 2 \cdot ({\cos (30°)}^{2})) - \cos (30°)}{{14A}^{2} \cdot (1 - (3 \cdot ({\cos (30°)}^{2})) + (2 \cdot ({\cos (30°)}^{3})))}}}

Next Step Convert Units

∴

d = \sqrt{\frac{1}{\frac{(((9^{2}) + (4^{2}) + (11^{2})) \cdot ({\sin (0.5236rad)}^{2})) + (((9 \cdot 4) + (4 \cdot 11) + (9 \cdot 11)) \cdot 2 \cdot ({\cos (0.5236rad)}^{2})) - \cos (0.5236rad)}{{1.4E-9m}^{2} \cdot (1 - (3 \cdot ({\cos (0.5236rad)}^{2})) + (2 \cdot ({\cos (0.5236rad)}^{3})))}}}

Next Step Prepare to Evaluate

∴

d = \sqrt{\frac{1}{\frac{(((9^{2}) + (4^{2}) + (11^{2})) \cdot ({\sin (0.5236)}^{2})) + (((9 \cdot 4) + (4 \cdot 11) + (9 \cdot 11)) \cdot 2 \cdot ({\cos (0.5236)}^{2})) - \cos (0.5236)}{{1.4E-9}^{2} \cdot (1 - (3 \cdot ({\cos (0.5236)}^{2})) + (2 \cdot ({\cos (0.5236)}^{3})))}}}

Next Step Evaluate

∴

d = 1.72733515814283E-11m

Next Step Convert to Output's Unit

∴

d = 0.0172733515814283nm

LAST Step Rounding Answer

∴

d = 0.0173nm

Interplanar Distance in Rhombohedral Crystal Lattice Formula Elements

Variables

Functions

Interplanar Spacing

Interplanar Spacing is the distance between adjacent and parallel planes of the crystal.

Symbol: d

Measurement: WavelengthUnit: nm

Note: Value should be greater than 0.

Formulas to find Interplanar Spacing

Miller Index along x-axis

The Miller Index along x-axis form a notation system in crystallography for planes in crystal (Bravais) lattices along the x-direction.

Symbol: h

Measurement: NAUnit: Unitless