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Interchange factor for two rectangles with common side at right angles to each other Formula

GoInfinite parallel planes Formula

GoInterchange factor for infinitely long concentric cylinders Formula

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Interchange factor is defined as the fraction of the energy leaving an isothermal area of a body that is incident upon the area of another body. Check FAQs

f 1-2 = ε 1 \cdot ε 2

f_1-2 - Interchange Factor?ε₁ - Emissivity of Body 1?ε₂ - Emissivity of Body 2?

Interchange factor for two rectangles with common side at right angles to each other Example

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Here is how the Interchange factor for two rectangles with common side at right angles to each other equation looks like with Values.

Here is how the Interchange factor for two rectangles with common side at right angles to each other equation looks like with Units.

Here is how the Interchange factor for two rectangles with common side at right angles to each other equation looks like.

0.12 = 0.4 \cdot 0.3

0.12 = 0.4 \cdot 0.3

0.12 = 0.4 \cdot 0.3

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Interchange factor for two rectangles with common side at right angles to each other Solution

Follow our step by step solution on how to calculate Interchange factor for two rectangles with common side at right angles to each other?

FIRST Step Consider the formula

f 1-2 = ε 1 \cdot ε 2

Next Step Substitute values of Variables

∴

f 1-2 = 0.4 \cdot 0.3

Next Step Prepare to Evaluate

∴

f 1-2 = 0.4 \cdot 0.3

LAST Step Evaluate

∴

f 1-2 = 0.12

Interchange factor for two rectangles with common side at right angles to each other Formula Elements

Variables

Interchange Factor

Interchange factor is defined as the fraction of the energy leaving an isothermal area of a body that is incident upon the area of another body.

Symbol: f_1-2

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Interchange Factor

Emissivity of Body 1

The Emissivity of Body 1 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.

Symbol: ε₁

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Emissivity of Body 1

Emissivity of Body 2

The Emissivity of Body 2 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.

Symbol: ε₂

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Emissivity of Body 2

Other Formulas to find Interchange Factor

Go Infinite parallel planes

f 1-2 = {((\frac{1}{ε 1}) + (\frac{1}{ε 2}) - 1)}^{- 1}

Go Interchange factor for infinitely long concentric cylinders

f 1-2 = {((\frac{1}{ε 1}) + ((\frac{A 1}{A 2}) \cdot ((\frac{1}{ε 2}) - 1)))}^{- 1}

Go Interchange factor for infinitely long concentric spheres

f 1-2 = {((\frac{1}{ε 1}) + ((\frac{A 1}{A 2}) \cdot ((\frac{1}{ε 2}) - 1)))}^{- 1}

Go Interchange factor for large body enclosed by another body

f 1-2 = {((\frac{1}{ε 1}) + ((\frac{A 1}{A 2}) \cdot ((\frac{1}{ε 2}) - 1)))}^{- 1}

How to Evaluate Interchange factor for two rectangles with common side at right angles to each other?

Interchange factor for two rectangles with common side at right angles to each other evaluator uses Interchange Factor = Emissivity of Body 1*Emissivity of Body 2 to evaluate the Interchange Factor, The Interchange factor for two rectangles with common side at right angles to each other formula calculates the interchange factor which is the fraction of the energy leaving the surface area of rectangle 1 that is incident upon the surface area of rectangle 2 where the common sides of rectangles are at right angles to each other. Interchange Factor is denoted by f_1-2 symbol.

How to evaluate Interchange factor for two rectangles with common side at right angles to each other using this online evaluator? To use this online evaluator for Interchange factor for two rectangles with common side at right angles to each other, enter Emissivity of Body 1 (ε₁) & Emissivity of Body 2 (ε₂) and hit the calculate button.

FAQs on Interchange factor for two rectangles with common side at right angles to each other

What is the formula to find Interchange factor for two rectangles with common side at right angles to each other?

The formula of Interchange factor for two rectangles with common side at right angles to each other is expressed as Interchange Factor = Emissivity of Body 1*Emissivity of Body 2. Here is an example- 0.12 = 0.4*0.3.

How to calculate Interchange factor for two rectangles with common side at right angles to each other?

With Emissivity of Body 1 (ε₁) & Emissivity of Body 2 (ε₂) we can find Interchange factor for two rectangles with common side at right angles to each other using the formula - Interchange Factor = Emissivity of Body 1*Emissivity of Body 2.

What are the other ways to Calculate Interchange Factor?

Here are the different ways to Calculate Interchange Factor-

Interchange Factor=((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1)^(-1)
Interchange Factor=((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1)
Interchange Factor=((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1)

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Interchange factor for two rectangles with common side at right angles to each other Formula

​GoInfinite parallel planes Formula

​GoInterchange factor for infinitely long concentric cylinders Formula

Interchange factor for two rectangles with common side at right angles to each other Example

Interchange factor for two rectangles with common side at right angles to each other Solution

Interchange factor for two rectangles with common side at right angles to each other Formula Elements

Other Formulas to find Interchange Factor

How to Evaluate Interchange factor for two rectangles with common side at right angles to each other?

FAQs on Interchange factor for two rectangles with common side at right angles to each other

Variable Name

GoInfinite parallel planes Formula

GoInterchange factor for infinitely long concentric cylinders Formula