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Interchange factor is defined as the fraction of the energy leaving an isothermal area of a body that is incident upon the area of another body. Check FAQs
f1-2=((1ε1)+((A1A2)((1ε2)-1)))-1
f1-2 - Interchange Factor?ε1 - Emissivity of Body 1?A1 - Surface Area of Body 1?A2 - Surface Area of Body 2?ε2 - Emissivity of Body 2?

Interchange factor for infinitely long concentric cylinders Example

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Here is how the Interchange factor for infinitely long concentric cylinders equation looks like with Values.

Here is how the Interchange factor for infinitely long concentric cylinders equation looks like with Units.

Here is how the Interchange factor for infinitely long concentric cylinders equation looks like.

0.1395Edit=((10.4Edit)+((100Edit50Edit)((10.3Edit)-1)))-1
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Interchange factor for infinitely long concentric cylinders Solution

Follow our step by step solution on how to calculate Interchange factor for infinitely long concentric cylinders?

FIRST Step Consider the formula
f1-2=((1ε1)+((A1A2)((1ε2)-1)))-1
Next Step Substitute values of Variables
f1-2=((10.4)+((10050)((10.3)-1)))-1
Next Step Prepare to Evaluate
f1-2=((10.4)+((10050)((10.3)-1)))-1
Next Step Evaluate
f1-2=0.13953488372093
LAST Step Rounding Answer
f1-2=0.1395

Interchange factor for infinitely long concentric cylinders Formula Elements

Variables
Interchange Factor
Interchange factor is defined as the fraction of the energy leaving an isothermal area of a body that is incident upon the area of another body.
Symbol: f1-2
Measurement: NAUnit: Unitless
Note: Value should be between 0 to 1.
Emissivity of Body 1
The Emissivity of Body 1 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
Symbol: ε1
Measurement: NAUnit: Unitless
Note: Value should be between 0 to 1.
Surface Area of Body 1
The Surface Area of Body 1 is the area of body 1 through which the radiation takes place.
Symbol: A1
Measurement: AreaUnit:
Note: Value can be positive or negative.
Surface Area of Body 2
The Surface Area of Body 2 is the area of body 2 upon which the radiation takes place.
Symbol: A2
Measurement: AreaUnit:
Note: Value can be positive or negative.
Emissivity of Body 2
The Emissivity of Body 2 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
Symbol: ε2
Measurement: NAUnit: Unitless
Note: Value should be between 0 to 1.

Other Formulas to find Interchange Factor

​Go Interchange Factor for Infinite parallel planes
f1-2=((1ε1)+(1ε2)-1)-1
​Go Interchange factor for infinitely long concentric spheres
f1-2=((1ε1)+((A1A2)((1ε2)-1)))-1
​Go Interchange factor for two rectangles with common side at right angles to each other
f1-2=ε1ε2
​Go Interchange factor for large body enclosed by another body
f1-2=((1ε1)+((A1A2)((1ε2)-1)))-1

How to Evaluate Interchange factor for infinitely long concentric cylinders?

Interchange factor for infinitely long concentric cylinders evaluator uses Interchange Factor = ((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1) to evaluate the Interchange Factor, Interchange factor for infinitely long concentric cylinders formula is defined as a measure of the thermal radiation exchange between two infinitely long concentric cylinders, taking into account their emissivities and surface areas, and is used to calculate the radiation heat transfer between them. Interchange Factor is denoted by f1-2 symbol.

How to evaluate Interchange factor for infinitely long concentric cylinders using this online evaluator? To use this online evaluator for Interchange factor for infinitely long concentric cylinders, enter Emissivity of Body 1 1), Surface Area of Body 1 (A1), Surface Area of Body 2 (A2) & Emissivity of Body 2 2) and hit the calculate button.

FAQs on Interchange factor for infinitely long concentric cylinders

What is the formula to find Interchange factor for infinitely long concentric cylinders?
The formula of Interchange factor for infinitely long concentric cylinders is expressed as Interchange Factor = ((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1). Here is an example- 0.139535 = ((1/0.4)+((100/50)*((1/0.3)-1)))^(-1).
How to calculate Interchange factor for infinitely long concentric cylinders?
With Emissivity of Body 1 1), Surface Area of Body 1 (A1), Surface Area of Body 2 (A2) & Emissivity of Body 2 2) we can find Interchange factor for infinitely long concentric cylinders using the formula - Interchange Factor = ((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1).
What are the other ways to Calculate Interchange Factor?
Here are the different ways to Calculate Interchange Factor-
  • Interchange Factor=((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1)^(-1)OpenImg
  • Interchange Factor=((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1)OpenImg
  • Interchange Factor=Emissivity of Body 1*Emissivity of Body 2OpenImg
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