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Input Resistance in Small-Signal Operation of Current Mirrors Formula

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Input resistance is the resistance value of the voltage amplifier. Check FAQs

R i = \frac{1}{g m}

R_i - Input Resistance?g_m - Transconductance?

Input Resistance in Small-Signal Operation of Current Mirrors Example

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Here is how the Input Resistance in Small-Signal Operation of Current Mirrors equation looks like with Values.

Here is how the Input Resistance in Small-Signal Operation of Current Mirrors equation looks like with Units.

Here is how the Input Resistance in Small-Signal Operation of Current Mirrors equation looks like.

4 = \frac{1}{0.25}

4Ω = \frac{1}{0.25S}

4 = \frac{1}{0.25}

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Input Resistance in Small-Signal Operation of Current Mirrors Solution

Follow our step by step solution on how to calculate Input Resistance in Small-Signal Operation of Current Mirrors?

FIRST Step Consider the formula

R i = \frac{1}{g m}

Next Step Substitute values of Variables

∴

R i = \frac{1}{0.25S}

Next Step Prepare to Evaluate

∴

R i = \frac{1}{0.25}

LAST Step Evaluate

∴

R i = 4Ω

Input Resistance in Small-Signal Operation of Current Mirrors Formula Elements

Variables

Input Resistance

Input resistance is the resistance value of the voltage amplifier.

Symbol: R_i

Measurement: Electric ResistanceUnit: Ω

Note: Value should be greater than 0.

Formulas to find Input Resistance

Transconductance

Transconductance is the change in the drain current divided by the small change in the gate/source voltage with a constant drain/source voltage.

Symbol: g_m

Measurement: Electric ConductanceUnit: S

Note: Value should be greater than 0.

Formulas to find Transconductance

Other formulas in Signal Amplifier category

Go Signal Current

I s = I p \cdot \sin (ω \cdot T)

Go Overall Voltage Gain given Signal Source

G vt = \frac{V o}{S i}

Go Current Transfer Ratio of Mirror with Base Current Compensation

I o = I ref \cdot (\frac{1}{1 + \frac{2}{β^{2}}})

Go Voltage Gain of Small-Signal Operation of Current Mirrors

G is = \frac{g m2 \cdot V gs}{I ss}

How to Evaluate Input Resistance in Small-Signal Operation of Current Mirrors?

Input Resistance in Small-Signal Operation of Current Mirrors evaluator uses Input Resistance = 1/Transconductance to evaluate the Input Resistance, The input resistance in small-signal operation of current mirrors is defined as the resistance seen by the current source or voltage source which drives the circuit. Input Resistance is denoted by R_i symbol.

How to evaluate Input Resistance in Small-Signal Operation of Current Mirrors using this online evaluator? To use this online evaluator for Input Resistance in Small-Signal Operation of Current Mirrors, enter Transconductance (g_m) and hit the calculate button.

FAQs on Input Resistance in Small-Signal Operation of Current Mirrors

What is the formula to find Input Resistance in Small-Signal Operation of Current Mirrors?

The formula of Input Resistance in Small-Signal Operation of Current Mirrors is expressed as Input Resistance = 1/Transconductance. Here is an example- 4E-6 = 1/0.25.

How to calculate Input Resistance in Small-Signal Operation of Current Mirrors?

With Transconductance (g_m) we can find Input Resistance in Small-Signal Operation of Current Mirrors using the formula - Input Resistance = 1/Transconductance.

Can the Input Resistance in Small-Signal Operation of Current Mirrors be negative?

No, the Input Resistance in Small-Signal Operation of Current Mirrors, measured in Electric Resistance cannot be negative.

Which unit is used to measure Input Resistance in Small-Signal Operation of Current Mirrors?

Input Resistance in Small-Signal Operation of Current Mirrors is usually measured using the Ohm[Ω] for Electric Resistance. Megohm[Ω], Microhm[Ω], Volt per Ampere[Ω] are the few other units in which Input Resistance in Small-Signal Operation of Current Mirrors can be measured.

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