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Initial Temperature using Integrated Form of Clausius-Clapeyron Equation Formula

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The Initial temperature is defined as the measure of heat under initial state or conditions. Check FAQs

T i = \frac{1}{(\frac{\ln (\frac{P f}{P i}) \cdot [R]}{LH}) + (\frac{1}{T f})}

T_i - Initial Temperature?P_f - Final Pressure of System?P_i - Initial Pressure of System?LH - Latent Heat?T_f - Final Temperature?[R] - Universal gas constant?

Initial Temperature using Integrated Form of Clausius-Clapeyron Equation Example

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Here is how the Initial Temperature using Integrated Form of Clausius-Clapeyron Equation equation looks like with Values.

Here is how the Initial Temperature using Integrated Form of Clausius-Clapeyron Equation equation looks like with Units.

Here is how the Initial Temperature using Integrated Form of Clausius-Clapeyron Equation equation looks like.

600.0014 = \frac{1}{(\frac{\ln (\frac{133.07}{65}) \cdot 8.3145}{25020.7}) + (\frac{1}{700})}

600.0014K = \frac{1}{(\frac{\ln (\frac{133.07Pa}{65Pa}) \cdot 8.3145}{25020.7J}) + (\frac{1}{700K})}

600.0014 = \frac{1}{(\frac{\ln (\frac{133.07}{65}) \cdot 8.3145}{25020.7}) + (\frac{1}{700})}

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Initial Temperature using Integrated Form of Clausius-Clapeyron Equation Solution

Follow our step by step solution on how to calculate Initial Temperature using Integrated Form of Clausius-Clapeyron Equation?

FIRST Step Consider the formula

T i = \frac{1}{(\frac{\ln (\frac{P f}{P i}) \cdot [R]}{LH}) + (\frac{1}{T f})}

Next Step Substitute values of Variables

∴

T i = \frac{1}{(\frac{\ln (\frac{133.07Pa}{65Pa}) \cdot [R]}{25020.7J}) + (\frac{1}{700K})}

Next Step Substitute values of Constants

∴

T i = \frac{1}{(\frac{\ln (\frac{133.07Pa}{65Pa}) \cdot 8.3145}{25020.7J}) + (\frac{1}{700K})}

Next Step Prepare to Evaluate

∴

T i = \frac{1}{(\frac{\ln (\frac{133.07}{65}) \cdot 8.3145}{25020.7}) + (\frac{1}{700})}

Next Step Evaluate

∴

T i = 600.00138895659K

LAST Step Rounding Answer

∴

T i = 600.0014K

Initial Temperature using Integrated Form of Clausius-Clapeyron Equation Formula Elements

Variables

Constants

Functions

Initial Temperature

The Initial temperature is defined as the measure of heat under initial state or conditions.

Symbol: T_i

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Formulas to find Initial Temperature

Final Pressure of System

Final Pressure of System is the total final pressure exerted by the molecules inside the system.

Symbol: P_f

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Final Pressure of System

Initial Pressure of System

Initial Pressure of System is the total initial pressure exerted by the molecules inside the system.

Symbol: P_i

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Initial Pressure of System

Latent Heat

Latent Heat is the heat that increases the specific humidity without a change in temperature.

Symbol: LH

Measurement: EnergyUnit: J

Note: Value can be positive or negative.

Formulas to find Latent Heat

Final Temperature

The Final temperature is the temperature at which measurements are made in final state.

Symbol: T_f

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Formulas to find Final Temperature

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

Other formulas in Clausius Clapeyron Equation category

Go August Roche Magnus Formula

e s = 6.1094 \cdot \exp (\frac{17.625 \cdot T}{T + 243.04})

Go Pressure for Transitions between Gas and Condensed Phase

P = \exp (- \frac{LH}{[R] \cdot T}) + c

Go Temperature for Transitions

T = - \frac{LH}{(\ln (P) - c) \cdot [R]}

Go Final Temperature using Integrated Form of Clausius-Clapeyron Equation

T f = \frac{1}{(- \frac{\ln (\frac{P f}{P i}) \cdot [R]}{LH}) + (\frac{1}{T i})}

How to Evaluate Initial Temperature using Integrated Form of Clausius-Clapeyron Equation?

Initial Temperature using Integrated Form of Clausius-Clapeyron Equation evaluator uses Initial Temperature = 1/(((ln(Final Pressure of System/Initial Pressure of System)*[R])/Latent Heat)+(1/Final Temperature)) to evaluate the Initial Temperature, The Initial Temperature using integrated form of Clausius-Clapeyron Equation is the initial state temperature of the system. Initial Temperature is denoted by T_i symbol.

How to evaluate Initial Temperature using Integrated Form of Clausius-Clapeyron Equation using this online evaluator? To use this online evaluator for Initial Temperature using Integrated Form of Clausius-Clapeyron Equation, enter Final Pressure of System (P_f), Initial Pressure of System (P_i), Latent Heat (LH) & Final Temperature (T_f) and hit the calculate button.

FAQs on Initial Temperature using Integrated Form of Clausius-Clapeyron Equation

What is the formula to find Initial Temperature using Integrated Form of Clausius-Clapeyron Equation?

The formula of Initial Temperature using Integrated Form of Clausius-Clapeyron Equation is expressed as Initial Temperature = 1/(((ln(Final Pressure of System/Initial Pressure of System)*[R])/Latent Heat)+(1/Final Temperature)). Here is an example- 600.0014 = 1/(((ln(133.07/65)*[R])/25020.7)+(1/700)).

How to calculate Initial Temperature using Integrated Form of Clausius-Clapeyron Equation?

With Final Pressure of System (P_f), Initial Pressure of System (P_i), Latent Heat (LH) & Final Temperature (T_f) we can find Initial Temperature using Integrated Form of Clausius-Clapeyron Equation using the formula - Initial Temperature = 1/(((ln(Final Pressure of System/Initial Pressure of System)*[R])/Latent Heat)+(1/Final Temperature)). This formula also uses Universal gas constant and Natural Logarithm (ln) function(s).

Can the Initial Temperature using Integrated Form of Clausius-Clapeyron Equation be negative?

No, the Initial Temperature using Integrated Form of Clausius-Clapeyron Equation, measured in Temperature cannot be negative.

Which unit is used to measure Initial Temperature using Integrated Form of Clausius-Clapeyron Equation?

Initial Temperature using Integrated Form of Clausius-Clapeyron Equation is usually measured using the Kelvin[K] for Temperature. Celsius[K], Fahrenheit[K], Rankine[K] are the few other units in which Initial Temperature using Integrated Form of Clausius-Clapeyron Equation can be measured.

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Initial Temperature using Integrated Form of Clausius-Clapeyron Equation Formula

Initial Temperature using Integrated Form of Clausius-Clapeyron Equation Example

Initial Temperature using Integrated Form of Clausius-Clapeyron Equation Solution

Initial Temperature using Integrated Form of Clausius-Clapeyron Equation Formula Elements

Other formulas in Clausius Clapeyron Equation category

How to Evaluate Initial Temperature using Integrated Form of Clausius-Clapeyron Equation?

FAQs on Initial Temperature using Integrated Form of Clausius-Clapeyron Equation

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