FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation Formula

Fx Copy

LaTeX Copy

Initial Pressure of System is the total initial pressure exerted by the molecules inside the system. Check FAQs

P i = \frac{P f}{\exp (- \frac{LH \cdot ((\frac{1}{T f}) - (\frac{1}{T i}))}{[R]})}

P_i - Initial Pressure of System?P_f - Final Pressure of System?LH - Latent Heat?T_f - Final Temperature?T_i - Initial Temperature?[R] - Universal gas constant?

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation Example

With values

With units

Only example

Here is how the Initial Pressure using Integrated Form of Clausius-Clapeyron Equation equation looks like with Values.

Here is how the Initial Pressure using Integrated Form of Clausius-Clapeyron Equation equation looks like with Units.

Here is how the Initial Pressure using Integrated Form of Clausius-Clapeyron Equation equation looks like.

64.9992 = \frac{133.07}{\exp (- \frac{25020.7 \cdot ((\frac{1}{700}) - (\frac{1}{600}))}{8.3145})}

64.9992Pa = \frac{133.07Pa}{\exp (- \frac{25020.7J \cdot ((\frac{1}{700K}) - (\frac{1}{600K}))}{8.3145})}

64.9992 = \frac{133.07}{\exp (- \frac{25020.7 \cdot ((\frac{1}{700}) - (\frac{1}{600}))}{8.3145})}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Chemistry » Category

Solution and Colligative properties » Category

Clausius Clapeyron Equation » fx Initial Pressure using Integrated Form of Clausius-Clapeyron Equation

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation Solution

Follow our step by step solution on how to calculate Initial Pressure using Integrated Form of Clausius-Clapeyron Equation?

FIRST Step Consider the formula

P i = \frac{P f}{\exp (- \frac{LH \cdot ((\frac{1}{T f}) - (\frac{1}{T i}))}{[R]})}

Next Step Substitute values of Variables

∴

P i = \frac{133.07Pa}{\exp (- \frac{25020.7J \cdot ((\frac{1}{700K}) - (\frac{1}{600K}))}{[R]})}

Next Step Substitute values of Constants

∴

P i = \frac{133.07Pa}{\exp (- \frac{25020.7J \cdot ((\frac{1}{700K}) - (\frac{1}{600K}))}{8.3145})}

Next Step Prepare to Evaluate

∴

P i = \frac{133.07}{\exp (- \frac{25020.7 \cdot ((\frac{1}{700}) - (\frac{1}{600}))}{8.3145})}

Next Step Evaluate

∴

P i = 64.9992453227249Pa

LAST Step Rounding Answer

∴

P i = 64.9992Pa

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation Formula Elements

Variables

Constants

Functions

Initial Pressure of System

Initial Pressure of System is the total initial pressure exerted by the molecules inside the system.

Symbol: P_i

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Initial Pressure of System

Final Pressure of System

Final Pressure of System is the total final pressure exerted by the molecules inside the system.

Symbol: P_f

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Final Pressure of System

Latent Heat

Latent Heat is the heat that increases the specific humidity without a change in temperature.

Symbol: LH

Measurement: EnergyUnit: J

Note: Value can be positive or negative.

Formulas to find Latent Heat

Final Temperature

The Final temperature is the temperature at which measurements are made in final state.

Symbol: T_f

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Formulas to find Final Temperature

Initial Temperature

The Initial temperature is defined as the measure of heat under initial state or conditions.

Symbol: T_i

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Formulas to find Initial Temperature

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

exp

n an exponential function, the value of the function changes by a constant factor for every unit change in the independent variable.

Syntax: exp(Number)

Other formulas in Clausius Clapeyron Equation category

Go August Roche Magnus Formula

e s = 6.1094 \cdot \exp (\frac{17.625 \cdot T}{T + 243.04})

Go Pressure for Transitions between Gas and Condensed Phase

P = \exp (- \frac{LH}{[R] \cdot T}) + c

Go Temperature for Transitions

T = - \frac{LH}{(\ln (P) - c) \cdot [R]}

Go Final Temperature using Integrated Form of Clausius-Clapeyron Equation

T f = \frac{1}{(- \frac{\ln (\frac{P f}{P i}) \cdot [R]}{LH}) + (\frac{1}{T i})}

How to Evaluate Initial Pressure using Integrated Form of Clausius-Clapeyron Equation?

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation evaluator uses Initial Pressure of System = Final Pressure of System/(exp(-(Latent Heat*((1/Final Temperature)-(1/Initial Temperature)))/[R])) to evaluate the Initial Pressure of System, The Initial Pressure using integrated form of Clausius-Clapeyron Equation is the initial state pressure of the system. Initial Pressure of System is denoted by P_i symbol.

How to evaluate Initial Pressure using Integrated Form of Clausius-Clapeyron Equation using this online evaluator? To use this online evaluator for Initial Pressure using Integrated Form of Clausius-Clapeyron Equation, enter Final Pressure of System (P_f), Latent Heat (LH), Final Temperature (T_f) & Initial Temperature (T_i) and hit the calculate button.

FAQs on Initial Pressure using Integrated Form of Clausius-Clapeyron Equation

What is the formula to find Initial Pressure using Integrated Form of Clausius-Clapeyron Equation?

The formula of Initial Pressure using Integrated Form of Clausius-Clapeyron Equation is expressed as Initial Pressure of System = Final Pressure of System/(exp(-(Latent Heat*((1/Final Temperature)-(1/Initial Temperature)))/[R])). Here is an example- 64.99925 = 133.07/(exp(-(25020.7*((1/700)-(1/600)))/[R])).

How to calculate Initial Pressure using Integrated Form of Clausius-Clapeyron Equation?

With Final Pressure of System (P_f), Latent Heat (LH), Final Temperature (T_f) & Initial Temperature (T_i) we can find Initial Pressure using Integrated Form of Clausius-Clapeyron Equation using the formula - Initial Pressure of System = Final Pressure of System/(exp(-(Latent Heat*((1/Final Temperature)-(1/Initial Temperature)))/[R])). This formula also uses Universal gas constant and Exponential Growth (exp) function(s).

Can the Initial Pressure using Integrated Form of Clausius-Clapeyron Equation be negative?

Yes, the Initial Pressure using Integrated Form of Clausius-Clapeyron Equation, measured in Pressure can be negative.

Which unit is used to measure Initial Pressure using Integrated Form of Clausius-Clapeyron Equation?

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation is usually measured using the Pascal[Pa] for Pressure. Kilopascal[Pa], Bar[Pa], Pound Per Square Inch[Pa] are the few other units in which Initial Pressure using Integrated Form of Clausius-Clapeyron Equation can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation Formula

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation Example

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation Solution

Initial Pressure using Integrated Form of Clausius-Clapeyron Equation Formula Elements

Other formulas in Clausius Clapeyron Equation category

How to Evaluate Initial Pressure using Integrated Form of Clausius-Clapeyron Equation?

FAQs on Initial Pressure using Integrated Form of Clausius-Clapeyron Equation

Variable Name