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Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System Formula

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Inhibitor Concentration given Max Rate is defined as the number of moles of inhibitor present per liter of solution of the system. Check FAQs

I max = ((\frac{(\frac{V max \cdot S}{V 0}) - S}{K M}) - 1) \cdot K i

I_max - Inhibitor Concentration given Max Rate?V_max - Maximum Rate?S - Substrate Concentration?V₀ - Initial Reaction Rate?K_M - Michaelis Constant?K_i - Enzyme Inhibitor Dissociation Constant?

Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System Example

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Here is how the Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System equation looks like with Values.

Here is how the Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System equation looks like with Units.

Here is how the Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System equation looks like.

815.9444 = ((\frac{(\frac{40 \cdot 1.5}{0.45}) - 1.5}{3}) - 1) \cdot 19

815.9444mol/L = ((\frac{(\frac{40mol/L*s \cdot 1.5mol/L}{0.45mol/L*s}) - 1.5mol/L}{3mol/L}) - 1) \cdot 19mol/L

815.9444 = ((\frac{(\frac{40 \cdot 1.5}{0.45}) - 1.5}{3}) - 1) \cdot 19

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Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System Solution

Follow our step by step solution on how to calculate Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System?

FIRST Step Consider the formula

I max = ((\frac{(\frac{V max \cdot S}{V 0}) - S}{K M}) - 1) \cdot K i

Next Step Substitute values of Variables

∴

I max = ((\frac{(\frac{40mol/L*s \cdot 1.5mol/L}{0.45mol/L*s}) - 1.5mol/L}{3mol/L}) - 1) \cdot 19mol/L

Next Step Convert Units

∴

I max = ((\frac{(\frac{40000mol/m³*s \cdot 1500mol/m³}{450mol/m³*s}) - 1500mol/m³}{3000mol/m³}) - 1) \cdot 19000mol/m³

Next Step Prepare to Evaluate

∴

I max = ((\frac{(\frac{40000 \cdot 1500}{450}) - 1500}{3000}) - 1) \cdot 19000

Next Step Evaluate

∴

I max = 815944.444444444mol/m³

Next Step Convert to Output's Unit

∴

I max = 815.944444444444mol/L

LAST Step Rounding Answer

∴

I max = 815.9444mol/L

Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System Formula Elements

Variables

Inhibitor Concentration given Max Rate

Inhibitor Concentration given Max Rate is defined as the number of moles of inhibitor present per liter of solution of the system.

Symbol: I_max

Measurement: Molar ConcentrationUnit: mol/L

Note: Value can be positive or negative.

Formulas to find Inhibitor Concentration given Max Rate

Maximum Rate

The Maximum Rate is defined as the maximum speed achieved by the system at saturated substrate concentration.

Symbol: V_max

Measurement: Reaction RateUnit: mol/L*s

Note: Value can be positive or negative.

Formulas to find Maximum Rate

Substrate Concentration

The Substrate Concentration is the number of moles of substrate per liter solution.

Symbol: S

Measurement: Molar ConcentrationUnit: mol/L

Note: Value can be positive or negative.

Formulas to find Substrate Concentration

Initial Reaction Rate

The Initial Reaction Rate is defined as the initial speed at which a chemical reaction takes place.

Symbol: V₀

Measurement: Reaction RateUnit: mol/L*s

Note: Value can be positive or negative.

Formulas to find Initial Reaction Rate

Michaelis Constant

The Michaelis Constant is numerically equal to the substrate concentration at which the reaction rate is half of the maximum rate of the system.

Symbol: K_M

Measurement: Molar ConcentrationUnit: mol/L

Note: Value can be positive or negative.

Formulas to find Michaelis Constant

Enzyme Inhibitor Dissociation Constant

The Enzyme Inhibitor Dissociation Constant is measured by the method in which the inhibitor is titrated into a solution of enzyme and the heat released or absorbed is measured.

Symbol: K_i

Measurement: Molar ConcentrationUnit: mol/L

Note: Value can be positive or negative.

Formulas to find Enzyme Inhibitor Dissociation Constant

Other formulas in Competitive Inhibitor category

Go Modifying Factor of Enzyme Substrate Complex

α' = 1 + (\frac{I}{K i'})

Go Initial Rate of System given Rate Constant and Enzyme Substrate Complex Concentration

V RC = k 2 \cdot ES

Go Initial Reaction Rate given Dissociation Rate Constant

V DRC = \frac{V max \cdot S}{K D + S}

Go Maximum Rate given Dissociation Rate Constant

V max_DRC = \frac{V 0 \cdot (K D + S)}{S}

How to Evaluate Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System?

Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System evaluator uses Inhibitor Concentration given Max Rate = (((((Maximum Rate*Substrate Concentration)/Initial Reaction Rate)-Substrate Concentration)/Michaelis Constant)-1)*Enzyme Inhibitor Dissociation Constant to evaluate the Inhibitor Concentration given Max Rate, The Inhibitor concentration in competitive inhibition given maximum rate of system formula is defined as a plot of the reaction velocity (V0) associated with the concentration [S] of the substrate can then be used to determine values such as Vmax, initial velocity, and Km. Inhibitor Concentration given Max Rate is denoted by I_max symbol.

How to evaluate Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System using this online evaluator? To use this online evaluator for Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System, enter Maximum Rate (V_max), Substrate Concentration (S), Initial Reaction Rate (V₀), Michaelis Constant (K_M) & Enzyme Inhibitor Dissociation Constant (K_i) and hit the calculate button.

FAQs on Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System

What is the formula to find Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System?

The formula of Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System is expressed as Inhibitor Concentration given Max Rate = (((((Maximum Rate*Substrate Concentration)/Initial Reaction Rate)-Substrate Concentration)/Michaelis Constant)-1)*Enzyme Inhibitor Dissociation Constant. Here is an example- 0.815944 = (((((40000*1500)/450)-1500)/3000)-1)*19000.

How to calculate Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System?

With Maximum Rate (V_max), Substrate Concentration (S), Initial Reaction Rate (V₀), Michaelis Constant (K_M) & Enzyme Inhibitor Dissociation Constant (K_i) we can find Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System using the formula - Inhibitor Concentration given Max Rate = (((((Maximum Rate*Substrate Concentration)/Initial Reaction Rate)-Substrate Concentration)/Michaelis Constant)-1)*Enzyme Inhibitor Dissociation Constant.

Can the Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System be negative?

Yes, the Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System, measured in Molar Concentration can be negative.

Which unit is used to measure Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System?

Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System is usually measured using the Mole per Liter[mol/L] for Molar Concentration. Mole per Cubic Meter[mol/L], Mole per Cubic Millimeter[mol/L], Kilomole per Cubic Meter[mol/L] are the few other units in which Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System can be measured.

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Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System Formula

Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System Example

Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System Solution

Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System Formula Elements

Other formulas in Competitive Inhibitor category

How to Evaluate Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System?

FAQs on Inhibitor Concentration in Competitive Inhibition given Maximum Rate of System

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