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Hydraulic Mean Depth using Central Angle Formula

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Hydraulic Mean Depth for Partially Full refers to the cross-sectional area of flow divided by the wetted perimeter, adapting to varying water levels. Check FAQs

r pf = (\frac{D pipe}{4}) \cdot (1 - (\frac{(360 \cdot \frac{π}{180}) \cdot \sin (∠ central)}{2 \cdot π \cdot ∠ central}))

r_pf - Hydraulic Mean Depth for Partially Full?D_pipe - Diameter of Pipe?∠_central - Central Angle?π - Archimedes' constant?

Hydraulic Mean Depth using Central Angle Example

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Here is how the Hydraulic Mean Depth using Central Angle equation looks like with Values.

Here is how the Hydraulic Mean Depth using Central Angle equation looks like with Units.

Here is how the Hydraulic Mean Depth using Central Angle equation looks like.

0.3871 = (\frac{2.64}{4}) \cdot (1 - (\frac{(360 \cdot \frac{3.1416}{180}) \cdot \sin (120)}{2 \cdot 3.1416 \cdot 120}))

0.3871m = (\frac{2.64m}{4}) \cdot (1 - (\frac{(360 \cdot \frac{3.1416}{180}) \cdot \sin (120°)}{2 \cdot 3.1416 \cdot 120°}))

0.3871 = (\frac{2.64}{4}) \cdot (1 - (\frac{(360 \cdot \frac{3.1416}{180}) \cdot \sin (120)}{2 \cdot 3.1416 \cdot 120}))

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Hydraulic Mean Depth using Central Angle Solution

Follow our step by step solution on how to calculate Hydraulic Mean Depth using Central Angle?

FIRST Step Consider the formula

r pf = (\frac{D pipe}{4}) \cdot (1 - (\frac{(360 \cdot \frac{π}{180}) \cdot \sin (∠ central)}{2 \cdot π \cdot ∠ central}))

Next Step Substitute values of Variables

∴

r pf = (\frac{2.64m}{4}) \cdot (1 - (\frac{(360 \cdot \frac{π}{180}) \cdot \sin (120°)}{2 \cdot π \cdot 120°}))

Next Step Substitute values of Constants

∴

r pf = (\frac{2.64m}{4}) \cdot (1 - (\frac{(360 \cdot \frac{3.1416}{180}) \cdot \sin (120°)}{2 \cdot 3.1416 \cdot 120°}))

Next Step Convert Units

∴

r pf = (\frac{2.64m}{4}) \cdot (1 - (\frac{(360 \cdot \frac{3.1416}{180}) \cdot \sin (2.0944rad)}{2 \cdot 3.1416 \cdot 2.0944rad}))

Next Step Prepare to Evaluate

∴

r pf = (\frac{2.64}{4}) \cdot (1 - (\frac{(360 \cdot \frac{3.1416}{180}) \cdot \sin (2.0944)}{2 \cdot 3.1416 \cdot 2.0944}))

Next Step Evaluate

∴

r pf = 0.387092196766099m

LAST Step Rounding Answer

∴

r pf = 0.3871m

Hydraulic Mean Depth using Central Angle Formula Elements

Variables

Constants

Functions

Hydraulic Mean Depth for Partially Full

Hydraulic Mean Depth for Partially Full refers to the cross-sectional area of flow divided by the wetted perimeter, adapting to varying water levels.

Symbol: r_pf

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Hydraulic Mean Depth for Partially Full

Diameter of Pipe

Diameter of Pipe is the diameter of the pipe in which the liquid is flowing.

Symbol: D_pipe

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Diameter of Pipe

Central Angle

A central angle is an angle whose apex (vertex) is the center O of a circle and whose legs (sides) are radii intersecting the circle in two distinct points A and B.

Symbol: ∠_central

Measurement: AngleUnit: °

Note: Value should be between 0 to 360.

Formulas to find Central Angle

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

sin

Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.

Syntax: sin(Angle)

Other formulas in Circular Sewer Section Running Full category

Go Diameter of pipe given Area of Cross-section

D pipe = {(\frac{a}{(\frac{π}{4}) \cdot ((\frac{∠ central}{360 \cdot \frac{π}{180}}) - (\frac{\sin (∠ central)}{2 \cdot π}))})}^{\frac{1}{2}}

Go Diameter of Pipe using Hydraulic Mean Depth

D pipe = \frac{r pf}{(\frac{1}{4}) \cdot (1 - (\frac{(360 \cdot \frac{π}{180}) \cdot \sin (∠ central)}{2 \cdot π \cdot ∠ central}))}

Go Discharge when Pipe is Running Full

Q = V \cdot A

Go Area of Cross-Section given Discharge

A = \frac{Q}{V}

How to Evaluate Hydraulic Mean Depth using Central Angle?

Hydraulic Mean Depth using Central Angle evaluator uses Hydraulic Mean Depth for Partially Full = (Diameter of Pipe/4)*(1-(((360*pi/180)*sin(Central Angle))/(2*pi*Central Angle))) to evaluate the Hydraulic Mean Depth for Partially Full, The Hydraulic Mean Depth using Central Angle is defined as the ratio of the cross-sectional area of fluid flow to the wetted perimeter in a channel or pipe. Hydraulic Mean Depth for Partially Full is denoted by r_pf symbol.

How to evaluate Hydraulic Mean Depth using Central Angle using this online evaluator? To use this online evaluator for Hydraulic Mean Depth using Central Angle, enter Diameter of Pipe (D_pipe) & Central Angle (∠_central) and hit the calculate button.

FAQs on Hydraulic Mean Depth using Central Angle

What is the formula to find Hydraulic Mean Depth using Central Angle?

The formula of Hydraulic Mean Depth using Central Angle is expressed as Hydraulic Mean Depth for Partially Full = (Diameter of Pipe/4)*(1-(((360*pi/180)*sin(Central Angle))/(2*pi*Central Angle))). Here is an example- 0.065791 = (2.64/4)*(1-(((360*pi/180)*sin(central_angle))/(2*pi*central_angle))).

How to calculate Hydraulic Mean Depth using Central Angle?

With Diameter of Pipe (D_pipe) & Central Angle (∠_central) we can find Hydraulic Mean Depth using Central Angle using the formula - Hydraulic Mean Depth for Partially Full = (Diameter of Pipe/4)*(1-(((360*pi/180)*sin(Central Angle))/(2*pi*Central Angle))). This formula also uses Archimedes' constant and Sine (sin) function(s).

Can the Hydraulic Mean Depth using Central Angle be negative?

No, the Hydraulic Mean Depth using Central Angle, measured in Length cannot be negative.

Which unit is used to measure Hydraulic Mean Depth using Central Angle?

Hydraulic Mean Depth using Central Angle is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Hydraulic Mean Depth using Central Angle can be measured.

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