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Height of Center of Gravity of Vehicle by method of jacking Vehicle from Rear Formula

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Height of Center of Gravity (C.G.) of vehicle is the vertical distance from the ground to the point where the weight of the vehicle is concentrated. Check FAQs

h cg = (R LF \cdot (\frac{c}{b})) + (R LR \cdot (\frac{a cg}{b})) + (\frac{(W F \cdot b) - (m \cdot c)}{m \cdot \tan (θ a)})

h_cg - Height of Center of Gravity (C.G.) of Vehicle?R_LF - Loaded Radius of Front Wheels?c - Horizontal Distance of C.G. From Rear Axle?b - Wheelbase of Vehicle?R_LR - Loaded Radius of Rear Wheels?a_cg - Horizontal Distance of C.G. From Front Axle?W_F - Weight of Front Wheels with Rear Elevated?m - Mass of Vehicle?θ_a - Angle through which Rear Axle of Vehicle Raised?

Height of Center of Gravity of Vehicle by method of jacking Vehicle from Rear Example

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Here is how the Height of Center of Gravity of Vehicle by method of jacking Vehicle from Rear equation looks like with Values.

Here is how the Height of Center of Gravity of Vehicle by method of jacking Vehicle from Rear equation looks like with Units.

Here is how the Height of Center of Gravity of Vehicle by method of jacking Vehicle from Rear equation looks like.

1480.92 = (11 \cdot (\frac{30}{2.7})) + (15 \cdot (\frac{27}{2.7})) + (\frac{(150 \cdot 2.7) - (55 \cdot 30)}{55 \cdot \tan (10)})

1480.92in = (11in \cdot (\frac{30in}{2.7m})) + (15in \cdot (\frac{27in}{2.7m})) + (\frac{(150kg \cdot 2.7m) - (55kg \cdot 30in)}{55kg \cdot \tan (10°)})

1480.92 = (11 \cdot (\frac{30}{2.7})) + (15 \cdot (\frac{27}{2.7})) + (\frac{(150 \cdot 2.7) - (55 \cdot 30)}{55 \cdot \tan (10)})

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Height of Center of Gravity of Vehicle by method of jacking Vehicle from Rear Solution

Follow our step by step solution on how to calculate Height of Center of Gravity of Vehicle by method of jacking Vehicle from Rear?

FIRST Step Consider the formula

h cg = (R LF \cdot (\frac{c}{b})) + (R LR \cdot (\frac{a cg}{b})) + (\frac{(W F \cdot b) - (m \cdot c)}{m \cdot \tan (θ a)})

Next Step Substitute values of Variables

∴

h cg = (11in \cdot (\frac{30in}{2.7m})) + (15in \cdot (\frac{27in}{2.7m})) + (\frac{(150kg \cdot 2.7m) - (55kg \cdot 30in)}{55kg \cdot \tan (10°)})

Next Step Convert Units

∴

h cg = (0.2794m \cdot (\frac{0.762m}{2.7m})) + (0.381m \cdot (\frac{0.6858m}{2.7m})) + (\frac{(150kg \cdot 2.7m) - (55kg \cdot 0.762m)}{55kg \cdot \tan (0.1745rad)})

Next Step Prepare to Evaluate

∴

h cg = (0.2794 \cdot (\frac{0.762}{2.7})) + (0.381 \cdot (\frac{0.6858}{2.7})) + (\frac{(150 \cdot 2.7) - (55 \cdot 0.762)}{55 \cdot \tan (0.1745)})

Next Step Evaluate

∴

h cg = 37.6153671776983m

Next Step Convert to Output's Unit

∴

h cg = 1480.91996761999in

LAST Step Rounding Answer

∴

h cg = 1480.92in

Height of Center of Gravity of Vehicle by method of jacking Vehicle from Rear Formula Elements

Variables

Functions

Height of Center of Gravity (C.G.) of Vehicle

Height of Center of Gravity (C.G.) of vehicle is the vertical distance from the ground to the point where the weight of the vehicle is concentrated.

Symbol: h_cg

Measurement: LengthUnit: in

Note: Value can be positive or negative.

Formulas to find Height of Center of Gravity (C.G.) of Vehicle

Loaded Radius of Front Wheels

Loaded radius of front wheels is the distance from the center of the wheel to the road surface, affecting the racing car's tire behavior and performance.

Symbol: R_LF

Measurement: LengthUnit: in