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Heat Transfer by Conduction at Base Formula

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Rate of Conductive Heat Transfer is the amount of heat flow through a body per unit time, usually measured in watts (joules per second). Check FAQs

Q fin = {(k fin \cdot A cs \cdot P f \cdot h)}^{0.5} \cdot (t o - t a)

Q_fin - Rate of Conductive Heat Transfer?k_fin - Thermal Conductivity?A_cs - Cross Sectional Area of Fin?P_f - Perimeter of the Fin?h - Convective Heat Transfer Coefficient?t_o - Base Temperature?t_a - Ambient Temperature?

Heat Transfer by Conduction at Base Example

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Here is how the Heat Transfer by Conduction at Base equation looks like with Values.

Here is how the Heat Transfer by Conduction at Base equation looks like with Units.

Here is how the Heat Transfer by Conduction at Base equation looks like.

43.2045 = {(205 \cdot 9E-5 \cdot 0.046 \cdot 30.17)}^{0.5} \cdot (573 - 303)

43.2045W = {(205W/(m*K) \cdot 9E-5m² \cdot 0.046m \cdot 30.17W/m²*K)}^{0.5} \cdot (573K - 303K)

43.2045 = {(205 \cdot 9E-5 \cdot 0.046 \cdot 30.17)}^{0.5} \cdot (573 - 303)

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Home » Engineering » Mechanical » Thermodynamics » Heat Transfer by Conduction at Base

Heat Transfer by Conduction at Base Solution

Follow our step by step solution on how to calculate Heat Transfer by Conduction at Base?

FIRST Step Consider the formula

Q fin = {(k fin \cdot A cs \cdot P f \cdot h)}^{0.5} \cdot (t o - t a)

Next Step Substitute values of Variables

∴

Q fin = {(205W/(m*K) \cdot 9E-5m² \cdot 0.046m \cdot 30.17W/m²*K)}^{0.5} \cdot (573K - 303K)

Next Step Prepare to Evaluate

∴

Q fin = {(205 \cdot 9E-5 \cdot 0.046 \cdot 30.17)}^{0.5} \cdot (573 - 303)

Next Step Evaluate

∴

Q fin = 43.2044539266497W

LAST Step Rounding Answer

∴

Q fin = 43.2045W

Heat Transfer by Conduction at Base Formula Elements

Variables

Rate of Conductive Heat Transfer

Rate of Conductive Heat Transfer is the amount of heat flow through a body per unit time, usually measured in watts (joules per second).

Symbol: Q_fin

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Thermal Conductivity

Thermal Conductivity of Fin is a material property that represents at which rate heat energy is transferred through the fin by conduction.

Symbol: k_fin

Measurement: Thermal ConductivityUnit: W/(m*K)

Note: Value should be greater than 0.

Cross Sectional Area of Fin

Cross Sectional Area of Fin is the surface area of the Fin which is perpendicular to the direction of Heat Flow.

Symbol: A_cs

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Perimeter of the Fin

Perimeter of the Fin refers to the total length of the outer boundary of the fin that is exposed to the surrounding medium.

Symbol: P_f

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Convective Heat Transfer Coefficient

Convective Heat Transfer Coefficient is a parameter that quantifies the rate of heat transfer between a solid surface and the surrounding fluid due to convection.

Symbol: h

Measurement: Heat Transfer CoefficientUnit: W/m²*K

Note: Value should be greater than 0.

Base Temperature

Base Temperature is the temperature at the base of the fin.

Symbol: t_o

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Ambient Temperature

Ambient Temperature is the temperature of the ambient or surrounding fluid which is in contact with the fin.

Symbol: t_a

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Credits

Creator Image

Created by Rushi Shah

K J Somaiya College of Engineering (K J Somaiya), Mumbai

Rushi Shah has created this Formula and 25+ more formulas!

Verifier Image

Verified by Dipto Mandal

Indian Institute of Information Technology (IIIT), Guwahati

Dipto Mandal has verified this Formula and 400+ more formulas!

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How to Evaluate Heat Transfer by Conduction at Base?

Heat Transfer by Conduction at Base evaluator uses Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature) to evaluate the Rate of Conductive Heat Transfer, Heat Transfer by conduction at Base is defined as the process in which the molecules are moved from the region of higher temperature to lower temperature. Rate of Conductive Heat Transfer is denoted by Q_fin symbol.

How to evaluate Heat Transfer by Conduction at Base using this online evaluator? To use this online evaluator for Heat Transfer by Conduction at Base, enter Thermal Conductivity (k_fin), Cross Sectional Area of Fin (A_cs), Perimeter of the Fin (P_f), Convective Heat Transfer Coefficient (h), Base Temperature (t_o) & Ambient Temperature (t_a) and hit the calculate button.

FAQs on Heat Transfer by Conduction at Base

What is the formula to find Heat Transfer by Conduction at Base?

The formula of Heat Transfer by Conduction at Base is expressed as Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature). Here is an example- 43.20445 = (205*9E-05*0.046*30.17)^0.5*(573-303).

How to calculate Heat Transfer by Conduction at Base?

With Thermal Conductivity (k_fin), Cross Sectional Area of Fin (A_cs), Perimeter of the Fin (P_f), Convective Heat Transfer Coefficient (h), Base Temperature (t_o) & Ambient Temperature (t_a) we can find Heat Transfer by Conduction at Base using the formula - Rate of Conductive Heat Transfer = (Thermal Conductivity*Cross Sectional Area of Fin*Perimeter of the Fin*Convective Heat Transfer Coefficient)^0.5*(Base Temperature-Ambient Temperature).

Can the Heat Transfer by Conduction at Base be negative?

Yes, the Heat Transfer by Conduction at Base, measured in Power can be negative.

Which unit is used to measure Heat Transfer by Conduction at Base?

Heat Transfer by Conduction at Base is usually measured using the Watt[W] for Power. Kilowatt[W], Milliwatt[W], Microwatt[W] are the few other units in which Heat Transfer by Conduction at Base can be measured.

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